我正在使用以下代码在Android中拨打电话,但它给了我安全例外,请帮助。

 posted_by = "111-333-222-4";

 String uri = "tel:" + posted_by.trim() ;
 Intent intent = new Intent(Intent.ACTION_CALL);
 intent.setData(Uri.parse(uri));
 startActivity(intent);

权限

 <uses-permission android:name="android.permission.CALL_PHONE" />

异常

11-25 14:47:01.661: ERROR/AndroidRuntime(302): Uncaught handler: thread main exiting due to uncaught exception
11-25 14:47:01.681: ERROR/AndroidRuntime(302): java.lang.SecurityException: Permission Denial: starting Intent { act=android.intent.action.CALL dat=tel:111-333-222-4 cmp=com.android.phone/.OutgoingCallBroadcaster } from ProcessRecord{43d32508 302:com.Finditnear/10026} (pid=302, uid=10026) requires android.permission.CALL_PHONE
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at android.os.Parcel.readException(Parcel.java:1218)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at android.os.Parcel.readException(Parcel.java:1206)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at android.app.ActivityManagerProxy.startActivity(ActivityManagerNative.java:1214)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at android.app.Instrumentation.execStartActivity(Instrumentation.java:1373)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at android.app.Activity.startActivityForResult(Activity.java:2749)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at android.app.Activity.startActivity(Activity.java:2855)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at com.Finditnear.PostDetail$2$1$1$1.onClick(PostDetail.java:604)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at com.android.internal.app.AlertController$AlertParams$3.onItemClick(AlertController.java:884)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at android.widget.AdapterView.performItemClick(AdapterView.java:284)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at android.widget.ListView.performItemClick(ListView.java:3285)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at android.widget.AbsListView$PerformClick.run(AbsListView.java:1640)

当前回答

使用完整代码

          Intent callIntent = new Intent(Intent.ACTION_DIAL);
          callIntent.setData(Uri.parse("tel:"+Uri.encode(PhoneNum.trim())));
          callIntent.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
          startActivity(callIntent);     

其他回答

你也可以用这个:

String uri = "tel:" + posted_by.replaceAll("[^0-9|\\+]", "");

重要提示:

如果你使用Intent。ACTION_CALL必须增加CALL_PHONE权限。

如果你不想让你的应用在没有SIM卡或没有GSM的平板电脑上显示谷歌播放,这是可以的。

在活动中:

            Intent callIntent = new Intent(Intent.ACTION_CALL);
            callIntent.setData(Uri.parse("tel:" + Constants.CALL_CENTER_NUMBER));
            startActivity(callIntent);

清单:

<uses-permission android:name="android.permission.CALL_PHONE" />

因此,如果它不是应用程序的关键功能,尽量避免添加CALL_PHONE权限。

其他解决方案:

是在屏幕上显示手机应用程序,用户只需要点击呼叫按钮:

            Intent dialIntent = new Intent(Intent.ACTION_DIAL);
            dialIntent.setData(Uri.parse("tel:" + Constants.CALL_CENTER_NUMBER));
            startActivity(dialIntent);

这样做不需要许可。

字符串电话= "9553290143";

意图意图=新的意图(意图。ACTION_DIAL, Uri.fromParts("tel", phone, null));

startActivity(意图);

// Java
String mobileNumber = "99XXXXXXXX";
Intent intent = new Intent();
intent.setAction(Intent.ACTION_DIAL); // Action for what intent called for
intent.setData(Uri.parse("tel: " + mobileNumber)); // Data with intent respective action on intent
startActivity(intent);

// Kotlin
val mobileNumber = "99XXXXXXXX"
val intent = Intent()
intent.action = Intent.ACTION_DIAL // Action for what intent called for
intent.data = Uri.parse("tel: $mobileNumber") // Data with intent respective action on intent
startActivity(intent)

只是一个简单的联机程序,不需要任何额外的权限:

private void dialContactPhone(final String phoneNumber) {
    startActivity(new Intent(Intent.ACTION_DIAL, Uri.fromParts("tel", phoneNumber, null)));
}