尤其是iOS开发者:

如果B是a的浅拷贝，那么对于原语数据，它就像B = [a assign];对于对象，B = [A retain];

B和A指向同一个内存位置

如果B是a的深层副本，则B = [a copy];

B和A指向不同的内存位置

B的内存地址与A的相同

B和A的含量相同

复制array:

Array是一个类，这意味着它是引用类型，因此array1 = array2的结果 在引用同一个数组的两个变量中。

但是看看这个例子:

  static void Main()
    {
        int[] arr1 = new int[] { 1, 2, 3, 4, 5 }; 
        int[] arr2 = new int[] { 6, 7, 8, 9, 0 };

        Console.WriteLine(arr1[2] + " " + arr2[2]);
        arr2 = arr1;
        Console.WriteLine(arr1[2] + " " + arr2[2]); 
        arr2 = (int[])arr1.Clone();
        arr1[2] = 12;
        Console.WriteLine(arr1[2] + " " + arr2[2]);
    }

浅克隆意味着只复制克隆数组所表示的内存。

如果数组包含值类型对象，则复制值;

如果数组包含引用类型，则只复制引用-因此有两个数组，其成员引用相同的对象。

要创建复制引用类型的深度复制，必须循环遍历数组并手动克隆每个元素。

浅克隆: 定义:“对象的浅拷贝复制‘主’对象，但不复制内部对象。” 当一个自定义对象(例如。雇员)只有原始的，字符串类型的变量，然后你使用浅克隆。

Employee e = new Employee(2, "john cena");
Employee e2=e.clone();

返回super.clone();在重写的clone()方法中，您的工作就结束了。

深克隆: 定义:“与浅拷贝不同，深拷贝是对象的完全独立副本。” 表示当一个Employee对象持有另一个自定义对象时:

Employee e = new Employee(2, "john cena", new Address(12, "West Newbury", "Massachusetts");

然后，您必须在覆写的clone()方法中编写代码来克隆'Address'对象。否则Address对象不会被克隆，当你在克隆的Employee对象中改变Address的值时，它会导致一个错误，这也反映了原始的一个。

char * Source = "Hello, world.";

char * ShallowCopy = Source;    

char * DeepCopy = new char(strlen(Source)+1);
strcpy(DeepCopy,Source);        

“ShallowCopy”指向与“Source”相同的内存位置。 “DeepCopy”指向内存中的不同位置，但内容是相同的。

{想象两个对象:相同类型_t的A和B(相对于c++)，你正在考虑将A浅/深复制到B}

浅拷贝: 简单地将a的引用复制到b中，把它看作是a的地址的副本。 因此，A和B的地址将是相同的，即它们将指向相同的内存位置，即数据内容。

Deep copy: Simply makes a copy of all the members of A, allocates memory in a different location for B and then assigns the copied members to B to achieve deep copy. In this way, if A becomes non-existant B is still valid in the memory. The correct term to use would be cloning, where you know that they both are totally the same, but yet different (i.e. stored as two different entities in the memory space). You can also provide your clone wrapper where you can decide via inclusion/exclusion list which properties to select during deep copy. This is quite a common practice when you create APIs.

只有当你了解其中的利害关系时，你才可以选择做浅拷贝。当你在c++或C中有大量的指针要处理时，做一个对象的浅拷贝真的是一个坏主意。

EXAMPLE_OF_DEEP COPY_ An example is, when you are trying to do image processing and object recognition you need to mask "Irrelevant and Repetitive Motion" out of your processing areas. If you are using image pointers, then you might have the specification to save those mask images. NOW... if you do a shallow copy of the image, when the pointer references are KILLED from the stack, you lost the reference and its copy i.e. there will be a runtime error of access violation at some point. In this case, what you need is a deep copy of your image by CLONING it. In this way you can retrieve the masks in case you need them in the future.

EXAMPLE_OF_SHALLOW_COPY I am not extremely knowledgeable compared to the users in StackOverflow so feel free to delete this part and put a good example if you can clarify. But I really think it is not a good idea to do shallow copy if you know that your program is gonna run for an infinite period of time i.e. continuous "push-pop" operation over the stack with function calls. If you are demonstrating something to an amateur or novice person (e.g. C/C++ tutorial stuff) then it is probably okay. But if you are running an application such as surveillance and detection system, or Sonar Tracking System, you are not supposed to keep shallow copying your objects around because it will kill your program sooner or later.

我想给出一个例子，而不是正式的定义。

var originalObject = { 
    a : 1, 
    b : 2, 
    c : 3,
};

这段代码显示了一个浅拷贝:

var copyObject1 = originalObject;

console.log(copyObject1.a);         // it will print 1 
console.log(originalObject.a);       // it will also print 1 
copyObject1.a = 4; 
console.log(copyObject1.a);           //now it will print 4 
console.log(originalObject.a);       // now it will also print 4

var copyObject2 = Object.assign({}, originalObject);

console.log(copyObject2.a);        // it will print 1 
console.log(originalObject.a);      // it will also print 1 
copyObject2.a = 4; 
console.log(copyObject2.a);        // now it will print 4 
console.log(originalObject.a);      // now it will print 1

这段代码显示了一个深度拷贝:

var copyObject2 = Object.assign({}, originalObject);

console.log(copyObject2.a);        // it will print 1 
console.log(originalObject.a);      // it will also print 1 
copyObject2.a = 4; 
console.log(copyObject2.a);        // now it will print 4 
console.log(originalObject.a);      // !! now it will print 1 !!