你可以使用dir(your_object)来获取属性，使用getattr(your_object, your_object_attr)来获取值

用法:

for att in dir(your_object):
    print (att, getattr(your_object,att))

如果你的对象没有__dict__，这特别有用。如果不是这样，你也可以尝试var(your_object)

你要这个干什么?如果不知道你的确切意图，可能很难得到最好的答案。

It is almost always better to do this manually if you want to display an instance of your class in a specific way. This will include exactly what you want and not include what you don't want, and the order will be predictable. If you are looking for a way to display the content of a class, manually format the attributes you care about and provide this as the __str__ or __repr__ method for your class. If you want to learn about what methods and such exist for an object to understand how it works, use help. help(a) will show you a formatted output about the object's class based on its docstrings. dir exists for programatically getting all the attributes of an object. (Accessing __dict__ does something I would group as the same but that I wouldn't use myself.) However, this may not include things you want and it may include things you do not want. It is unreliable and people think they want it a lot more often than they do. On a somewhat orthogonal note, there is very little support for Python 3 at the current time. If you are interested in writing real software you are going to want third-party stuff like numpy, lxml, Twisted, PIL, or any number of web frameworks that do not yet support Python 3 and do not have plans to any time too soon. The differences between 2.6 and the 3.x branch are small, but the difference in library support is huge.

请参阅已按顺序执行的python shell脚本，在这里您将获得以逗号分隔的字符串格式的类属性。

>>> class new_class():
...     def __init__(self, number):
...         self.multi = int(number)*2
...         self.str = str(number)
... 
>>> a = new_class(4)
>>> ",".join(a.__dict__.keys())
'str,multi'<br/>

我使用的是python 3.4

人们经常提到，要列出一个完整的属性列表，应该使用dir()。但是请注意，与普遍观点相反，dir()并没有显示所有属性。例如，你可能会注意到__name__可能在类的dir()列表中缺失，即使你可以从类本身访问它。从dir()的文档(Python 2, Python 3):

因为提供dir()主要是为了方便在 交互式提示符，它试图提供一组有趣的名称 它不仅仅是试图提供一个严格或一致定义的集合 的名称，其详细行为可能在不同版本之间更改。为 属性时，元类属性不在结果列表中 参数是一个类。

像下面这样的函数往往更完整，尽管不能保证完整性，因为dir()返回的列表可能受到许多因素的影响，包括实现__dir__()方法，或在类或其父类之一上自定义__getattr__()或__getattribute__()。详情请参阅所提供的链接。

def dirmore(instance):
    visible = dir(instance)
    visible += [a for a in set(dir(type)).difference(visible)
                if hasattr(instance, a)]
    return sorted(visible)

除了这些答案之外，我还将包括一个函数(python 3)，用于输出任何值的几乎整个结构。它使用dir来建立属性名的完整列表，然后对每个名称使用getattr。它会显示值的每个成员的类型，如果可能的话还会显示整个成员:

import json

def get_info(obj):

  type_name = type(obj).__name__
  print('Value is of type {}!'.format(type_name))
  prop_names = dir(obj)

  for prop_name in prop_names:
    prop_val = getattr(obj, prop_name)
    prop_val_type_name = type(prop_val).__name__
    print('{} has property "{}" of type "{}"'.format(type_name, prop_name, prop_val_type_name))

    try:
      val_as_str = json.dumps([ prop_val ], indent=2)[1:-1]
      print('  Here\'s the {} value: {}'.format(prop_name, val_as_str))
    except:
      pass

现在，以下任何一项都应该让你有所了解:

get_info(None)
get_info('hello')

import numpy
get_info(numpy)
# ... etc.

如前所述，使用obj。__dict__可以处理常见情况，但有些类没有__dict__属性，而使用__slots__(主要是为了提高内存效率)。

举个更有弹性的例子:

class A(object):
    __slots__ = ('x', 'y', )
    def __init__(self, x, y):
        self.x = x
        self.y = y


class B(object):
    def __init__(self, x, y):
        self.x = x
        self.y = y


def get_object_attrs(obj):
    try:
        return obj.__dict__
    except AttributeError:
        return {attr: getattr(obj, attr) for attr in obj.__slots__}


a = A(1,2)
b = B(1,2)
assert not hasattr(a, '__dict__')

print(get_object_attrs(a))
print(get_object_attrs(b))

这段代码的输出:

{'x': 1, 'y': 2}
{'x': 1, 'y': 2}

注一: Python是一种动态语言，它总是更好地了解你试图从中获取属性的类，因为即使这些代码也可能错过一些情况。

注2: 这段代码只输出实例变量，这意味着不提供类变量。例如:

class A(object):
    url = 'http://stackoverflow.com'
    def __init__(self, path):
        self.path = path

print(A('/questions').__dict__)

代码输出:

{'path': '/questions'}

这段代码不打印url类属性，可能会省略所需的类属性。 有时，我们可能认为属性是实例成员，但它不是，也不会在本例中显示。