是否有一种方法可以获取类实例上存在的属性列表?
class new_class():
def __init__(self, number):
self.multi = int(number) * 2
self.str = str(number)
a = new_class(2)
print(', '.join(a.SOMETHING))
期望的结果是输出"multi, str"。我希望它能看到脚本各个部分的当前属性。
是否有一种方法可以获取类实例上存在的属性列表?
class new_class():
def __init__(self, number):
self.multi = int(number) * 2
self.str = str(number)
a = new_class(2)
print(', '.join(a.SOMETHING))
期望的结果是输出"multi, str"。我希望它能看到脚本各个部分的当前属性。
当前回答
除了这些答案之外,我还将包括一个函数(python 3),用于输出任何值的几乎整个结构。它使用dir来建立属性名的完整列表,然后对每个名称使用getattr。它会显示值的每个成员的类型,如果可能的话还会显示整个成员:
import json
def get_info(obj):
type_name = type(obj).__name__
print('Value is of type {}!'.format(type_name))
prop_names = dir(obj)
for prop_name in prop_names:
prop_val = getattr(obj, prop_name)
prop_val_type_name = type(prop_val).__name__
print('{} has property "{}" of type "{}"'.format(type_name, prop_name, prop_val_type_name))
try:
val_as_str = json.dumps([ prop_val ], indent=2)[1:-1]
print(' Here\'s the {} value: {}'.format(prop_name, val_as_str))
except:
pass
现在,以下任何一项都应该让你有所了解:
get_info(None)
get_info('hello')
import numpy
get_info(numpy)
# ... etc.
其他回答
>>> ', '.join(i for i in dir(a) if not i.startswith('__'))
'multi, str'
这当然会打印类定义中的任何方法或属性。你可以通过将i.startwith('__')更改为i.startwith('_')来排除“私有”方法。
>>> class new_class():
... def __init__(self, number):
... self.multi = int(number) * 2
... self.str = str(number)
...
>>> a = new_class(2)
>>> a.__dict__
{'multi': 4, 'str': '2'}
>>> a.__dict__.keys()
dict_keys(['multi', 'str'])
您可能还会发现pprint有帮助。
你要这个干什么?如果不知道你的确切意图,可能很难得到最好的答案。
It is almost always better to do this manually if you want to display an instance of your class in a specific way. This will include exactly what you want and not include what you don't want, and the order will be predictable. If you are looking for a way to display the content of a class, manually format the attributes you care about and provide this as the __str__ or __repr__ method for your class. If you want to learn about what methods and such exist for an object to understand how it works, use help. help(a) will show you a formatted output about the object's class based on its docstrings. dir exists for programatically getting all the attributes of an object. (Accessing __dict__ does something I would group as the same but that I wouldn't use myself.) However, this may not include things you want and it may include things you do not want. It is unreliable and people think they want it a lot more often than they do. On a somewhat orthogonal note, there is very little support for Python 3 at the current time. If you are interested in writing real software you are going to want third-party stuff like numpy, lxml, Twisted, PIL, or any number of web frameworks that do not yet support Python 3 and do not have plans to any time too soon. The differences between 2.6 and the 3.x branch are small, but the difference in library support is huge.
dir(instance)
# or (same value)
instance.__dir__()
# or
instance.__dict__
然后可以用type()测试类型是什么,或者用callable()测试是否为方法。
除了这些答案之外,我还将包括一个函数(python 3),用于输出任何值的几乎整个结构。它使用dir来建立属性名的完整列表,然后对每个名称使用getattr。它会显示值的每个成员的类型,如果可能的话还会显示整个成员:
import json
def get_info(obj):
type_name = type(obj).__name__
print('Value is of type {}!'.format(type_name))
prop_names = dir(obj)
for prop_name in prop_names:
prop_val = getattr(obj, prop_name)
prop_val_type_name = type(prop_val).__name__
print('{} has property "{}" of type "{}"'.format(type_name, prop_name, prop_val_type_name))
try:
val_as_str = json.dumps([ prop_val ], indent=2)[1:-1]
print(' Here\'s the {} value: {}'.format(prop_name, val_as_str))
except:
pass
现在,以下任何一项都应该让你有所了解:
get_info(None)
get_info('hello')
import numpy
get_info(numpy)
# ... etc.