以下哪一种技术是整数除2的最佳选择,为什么?
技巧1:
x = x >> 1;
技巧2:
x = x / 2;
这里x是整数。
以下哪一种技术是整数除2的最佳选择,为什么?
技巧1:
x = x >> 1;
技巧2:
x = x / 2;
这里x是整数。
当前回答
在性能方面。CPU的移位运算比除法运算快得多。 所以除以2或乘以2等都可以从移位运算中获益。
至于外观和感觉。作为工程师,我们什么时候变得如此依赖化妆品,连漂亮的女士都不用!:)
其他回答
x / 2更清晰,x >> 1快不了多少(根据一个微基准测试,对于Java JVM快30%左右)。正如其他人所注意到的,对于负数,舍入略有不同,所以当您想处理负数时必须考虑这一点。一些编译器可能会自动将x / 2转换为x >> 1,如果他们知道这个数字不可能是负数(即使我无法验证这一点)。
即使x / 2可能不使用(慢)除法CPU指令,因为一些捷径是可能的,但它仍然比x >> 1慢。
(This is a C / C++ question, other programming languages have more operators. For Java there is also the unsigned right shift, x >>> 1, which is again different. It allows to correctly calculate the mean (average) value of two values, so that (a + b) >>> 1 will return the mean value even for very large values of a and b. This is required for example for binary search if the array indices can get very large. There was a bug in many versions of binary search, because they used (a + b) / 2 to calculate the average. This doesn't work correctly. The correct solution is to use (a + b) >>> 1 instead.)
我说这些是为了参加编程比赛。一般来说,他们有非常大的输入,除以2会发生很多次,已知输入是正的或负的。
X >>1比X /2好。我在ideone.com上运行了一个程序,其中发生了超过10^10除以2的运算。X /2花了将近5.5s,而X >>1花了将近2.6s。
Knuth说:
过早的优化是万恶之源。
所以我建议用x /= 2;
这样代码很容易理解,而且我认为这种形式的操作优化,对处理器来说不会有太大的区别。
这个问题的答案取决于你工作的环境。
If you're working on an 8-bit microcontroller or anything without hardware support for multiplication, bit shifting is expected and commonplace, and while the compiler will almost certainly turn x /= 2 into x >>= 1, the presence of a division symbol will raise more eyebrows in that environment than using a shift to effect a division. If you're working in a performance-critical environment or section of code, or your code could be compiled with compiler optimization off, x >>= 1 with a comment explaining its reasoning is probably best just for clarity of purpose. If you're not under one of the above conditions, make your code more readable by simply using x /= 2. Better to save the next programmer who happens to look at your code the 10 second double-take on your shift operation than to needlessly prove you knew the shift was more efficient sans compiler optimization.
所有这些假设都是无符号整数。简单的移位可能不是你想要的符号。此外,DanielH提出了一个关于在ActionScript等特定语言中使用x *= 0.5的好观点。
X/Y是正确的…和" >> "移位运算符..如果我们想要二除一个整数,我们可以使用(/)被除数运算符。移位运算符用于移位位。
x = x / 2; x / = 2;我们可以这样用…