问题

我开始看看Swift编程语言,不知为何我不能正确地从特定的UIStoryboard输入一个UIViewController的初始化。

在Objective-C中,我简单地写:

UIStoryboard *storyboard = [UIStoryboard storyboardWithName:@"StoryboardName" bundle:nil];
UIViewController *viewController = [storyboard instantiateViewControllerWithIdentifier:@"ViewControllerID"];
[self presentViewController:viewController animated:YES completion:nil];

有人能帮助我如何在斯威夫特上实现这一点吗?


当前回答

这个答案是针对Swift 5.4和iOS 14.5 SDK进行的最新修订。


这只是新语法和稍微修改的api的问题。UIKit的底层功能并没有改变。对于绝大多数iOS SDK框架来说都是如此。

let storyboard = UIStoryboard(name: "myStoryboardName", bundle: nil)
let vc = storyboard.instantiateViewController(withIdentifier: "myVCID")
self.present(vc, animated: true)

确保在故事板中“故事板ID”下设置myVCID。

其他回答

斯威夫特4:

    let storyboard = UIStoryboard(name: "Main", bundle: nil)
    let yourVC: YourVC = storyboard.instantiateViewController(withIdentifier: "YourVC") as! YourVC

斯威夫特5

let vc = self.storyboard!.instantiateViewController(withIdentifier: "CVIdentifier")
self.present(vc, animated: true, completion: nil)

无论我怎么尝试,它都不适合我——没有错误,但我的屏幕上也没有新的视图控制器。不知道为什么,但是在超时函数中包装它最终使它工作:

DispatchQueue.main.asyncAfter(deadline: .now() + 0.0) {
    let storyboard = UIStoryboard(name: "Main", bundle: nil)
    let controller = storyboard.instantiateViewController(withIdentifier: "TabletViewController")
    self.present(controller, animated: true, completion: nil)
}
if let destinationVC = UIStoryboard(name: "Main", bundle: nil).instantiateViewController(withIdentifier: "DestinationVC") as? DestinationVC{
            let nav = self.navigationController
            //presenting
            nav?.present(destinationVC, animated: true, completion: {
                
            })
            //push
            nav?.pushViewController(destinationVC, animated: true)
        }

斯威夫特3

let settingStoryboard : UIStoryboard = UIStoryboard(name: "SettingViewController", bundle: nil)
let settingVC = settingStoryboard.instantiateViewController(withIdentifier: "SettingViewController") as! SettingViewController
self.present(settingVC, animated: true, completion: {

})