问题
我开始看看Swift编程语言，不知为何我不能正确地从特定的UIStoryboard输入一个UIViewController的初始化。
在Objective-C中，我简单地写:
UIStoryboard *storyboard = [UIStoryboard storyboardWithName:@"StoryboardName" bundle:nil];
UIViewController *viewController = [storyboard instantiateViewControllerWithIdentifier:@"ViewControllerID"];
[self presentViewController:viewController animated:YES completion:nil];
有人能帮助我如何在斯威夫特上实现这一点吗?
当前回答
if let destinationVC = UIStoryboard(name: "Main", bundle: nil).instantiateViewController(withIdentifier: "DestinationVC") as? DestinationVC{
let nav = self.navigationController
//presenting
nav?.present(destinationVC, animated: true, completion: {
})
//push
nav?.pushViewController(destinationVC, animated: true)
}
其他回答
对于那些使用@akashivsky的答案来实例化UIViewController的人来说，有一个异常:
致命错误:类使用了未实现的初始化式'init(coder:)'
快速提示:
手动实现所需的初始化?(coder aDecoder: NSCoder)在你的目标UIViewController，你试图实例化
required init?(coder aDecoder: NSCoder) {
super.init(coder: aDecoder)
}
如果你需要更多的描述，请参考我在这里的回答
这个链接有两个实现:
迅速:
let viewController:UIViewController = UIStoryboard(name: "Main", bundle: nil).instantiateViewControllerWithIdentifier("ViewController") as UIViewController
self.presentViewController(viewController, animated: false, completion: nil)
Objective - C
UIViewController *viewController = [[UIStoryboard storyboardWithName:@"MainStoryboard" bundle:nil] instantiateViewControllerWithIdentifier:@"ViewController"];
这个链接有在同一个故事板中初始化视图控制器的代码
/*
Helper to Switch the View based on StoryBoard
@param StoryBoard ID as String
*/
func switchToViewController(identifier: String) {
let viewController = self.storyboard?.instantiateViewControllerWithIdentifier(identifier) as! UIViewController
self.navigationController?.setViewControllers([viewController], animated: false)
}
如果你有一个Viewcontroller没有使用任何storyboard/Xib，你可以像下面这样调用这个特定的VC:
let vcInstance : UIViewController = yourViewController()
self.present(vcInstance, animated: true, completion: nil)
我使用这个助手:
struct Storyboard<T: UIViewController> {
static var storyboardName: String {
return String(describing: T.self)
}
static var viewController: T {
let storyboard = UIStoryboard(name: "Main", bundle: nil)
guard let vc = storyboard.instantiateViewController(withIdentifier: Self.storyboardName) as? T else {
fatalError("Could not get controller from Storyboard: \(Self.storyboardName)")
}
return vc
}
}
用法(故事板ID必须匹配UIViewController类名)
let myVC = Storyboard.viewController as MyViewController
如果你想以模态方式呈现它，你应该有如下所示的东西:
let vc = self.storyboard!.instantiateViewControllerWithIdentifier("YourViewControllerID")
self.showDetailViewController(vc as! YourViewControllerClassName, sender: self)
