问题
我开始看看Swift编程语言，不知为何我不能正确地从特定的UIStoryboard输入一个UIViewController的初始化。
在Objective-C中，我简单地写:
UIStoryboard *storyboard = [UIStoryboard storyboardWithName:@"StoryboardName" bundle:nil];
UIViewController *viewController = [storyboard instantiateViewControllerWithIdentifier:@"ViewControllerID"];
[self presentViewController:viewController animated:YES completion:nil];
有人能帮助我如何在斯威夫特上实现这一点吗?
当前回答
如果你有一个Viewcontroller没有使用任何storyboard/Xib，你可以像下面这样调用这个特定的VC:
let vcInstance : UIViewController = yourViewController()
self.present(vcInstance, animated: true, completion: nil)
其他回答
guard let vc = storyboard?.instantiateViewController(withIdentifier: "add") else { return }
vc.modalPresentationStyle = .fullScreen
present(vc, animated: true, completion: nil)
// "Main" is name of .storybord file "
let mainStoryboard: UIStoryboard = UIStoryboard(name: "Main", bundle: nil)
// "MiniGameView" is the ID given to the ViewController in the interfacebuilder
// MiniGameViewController is the CLASS name of the ViewController.swift file acosiated to the ViewController
var setViewController = mainStoryboard.instantiateViewControllerWithIdentifier("MiniGameView") as MiniGameViewController
var rootViewController = self.window!.rootViewController
rootViewController?.presentViewController(setViewController, animated: false, completion: nil)
当我把它放在AppDelegate时，这工作得很好
斯威夫特5
let vc = self.storyboard!.instantiateViewController(withIdentifier: "CVIdentifier")
self.present(vc, animated: true, completion: nil)
对于那些使用@akashivsky的答案来实例化UIViewController的人来说，有一个异常:
致命错误:类使用了未实现的初始化式'init(coder:)'
快速提示:
手动实现所需的初始化?(coder aDecoder: NSCoder)在你的目标UIViewController，你试图实例化
required init?(coder aDecoder: NSCoder) {
super.init(coder: aDecoder)
}
如果你需要更多的描述，请参考我在这里的回答
我想建议一种更简洁的方法。当我们有多个故事板时，这将很有用
1.用你所有的故事板创建一个结构
struct Storyboard {
static let main = "Main"
static let login = "login"
static let profile = "profile"
static let home = "home"
}
2. 创建一个UIStoryboard扩展，如下所示
extension UIStoryboard {
@nonobjc class var main: UIStoryboard {
return UIStoryboard(name: Storyboard.main, bundle: nil)
}
@nonobjc class var journey: UIStoryboard {
return UIStoryboard(name: Storyboard.login, bundle: nil)
}
@nonobjc class var quiz: UIStoryboard {
return UIStoryboard(name: Storyboard.profile, bundle: nil)
}
@nonobjc class var home: UIStoryboard {
return UIStoryboard(name: Storyboard.home, bundle: nil)
}
}
将故事板标识符作为类名，并使用下面的代码进行实例化
let loginVc = UIStoryboard.login.instantiateViewController(withIdentifier: "\(LoginViewController.self)") as! LoginViewController
