如何在Python中将彩色文本输出到终端?


当前回答

我已经将joeld的答案打包到一个模块中,该模块具有全局函数,我可以在代码中的任何地方使用这些函数。

文件:log.py

def enable():
    HEADER = '\033[95m'
    OKBLUE = '\033[94m'
    OKGREEN = '\033[92m'
    WARNING = '\033[93m'
    FAIL = '\033[91m'
    ENDC = '\033[0m'
    BOLD = "\033[1m"

def disable():
    HEADER = ''
    OKBLUE = ''
    OKGREEN = ''
    WARNING = ''
    FAIL = ''
    ENDC = ''

def infog(msg):
    print(OKGREEN + msg + ENDC)

def info(msg):
    print(OKBLUE + msg + ENDC)

def warn(msg):
    print(WARNING + msg + ENDC)

def err(msg):
    print(FAIL + msg + ENDC)

enable()

使用方法如下:

import log
log.info("Hello, World!")
log.err("System Error")

其他回答

https://raw.github.com/fabric/fabric/master/fabric/colors.py

"""
.. versionadded:: 0.9.2

Functions for wrapping strings in ANSI color codes.

Each function within this module returns the input string ``text``, wrapped
with ANSI color codes for the appropriate color.

For example, to print some text as green on supporting terminals::

    from fabric.colors import green

    print(green("This text is green!"))

Because these functions simply return modified strings, you can nest them::

    from fabric.colors import red, green

    print(red("This sentence is red, except for " + \
          green("these words, which are green") + "."))

If ``bold`` is set to ``True``, the ANSI flag for bolding will be flipped on
for that particular invocation, which usually shows up as a bold or brighter
version of the original color on most terminals.
"""


def _wrap_with(code):

    def inner(text, bold=False):
        c = code
        if bold:
            c = "1;%s" % c
        return "\033[%sm%s\033[0m" % (c, text)
    return inner

red = _wrap_with('31')
green = _wrap_with('32')
yellow = _wrap_with('33')
blue = _wrap_with('34')
magenta = _wrap_with('35')
cyan = _wrap_with('36')
white = _wrap_with('37')

耶!另一个版本

虽然我觉得这个答案很有用,但我做了一些修改。此GitHub Gist是结果

用法

print colors.draw("i'm yellow", bold=True, fg_yellow=True)

此外,还可以包装常用用法:

print colors.error('sorry, ')

https://gist.github.com/Jossef/0ee20314577925b4027f

根据乔尔德的回答,这简直太简单了:

class PrintInColor:
    RED = '\033[91m'
    GREEN = '\033[92m'
    YELLOW = '\033[93m'
    LIGHT_PURPLE = '\033[94m'
    PURPLE = '\033[95m'
    END = '\033[0m'

    @classmethod
    def red(cls, s, **kwargs):
        print(cls.RED + s + cls.END, **kwargs)

    @classmethod
    def green(cls, s, **kwargs):
        print(cls.GREEN + s + cls.END, **kwargs)

    @classmethod
    def yellow(cls, s, **kwargs):
        print(cls.YELLOW + s + cls.END, **kwargs)

    @classmethod
    def lightPurple(cls, s, **kwargs):
        print(cls.LIGHT_PURPLE + s + cls.END, **kwargs)

    @classmethod
    def purple(cls, s, **kwargs):
        print(cls.PURPLE + s + cls.END, **kwargs)

那么就

PrintInColor.red('hello', end=' ')
PrintInColor.green('world')

另一个包装Python3打印功能的PyPI模块:

https://pypi.python.org/pypi/colorprint

如果您也可以从__future_import-print中使用,它可以在Python2.x中使用。下面是模块PyPI页面中的Python 2示例:

from __future__ import print_function
from colorprint import *

print('Hello', 'world', color='blue', end='', sep=', ')
print('!', color='red', format=['bold', 'blink'])

它输出“你好,世界!”,单词为蓝色,感叹号为粗体红色并闪烁。

# Pure Python 3.x demo, 256 colors
# Works with bash under Linux and MacOS

fg = lambda text, color: "\33[38;5;" + str(color) + "m" + text + "\33[0m"
bg = lambda text, color: "\33[48;5;" + str(color) + "m" + text + "\33[0m"

def print_six(row, format, end="\n"):
    for col in range(6):
        color = row*6 + col - 2
        if color>=0:
            text = "{:3d}".format(color)
            print (format(text,color), end=" ")
        else:
            print(end="    ")   # four spaces
    print(end=end)

for row in range(0, 43):
    print_six(row, fg, " ")
    print_six(row, bg)

# Simple usage: print(fg("text", 160))

在线试用