使用进度库!

pip install progress

下面是我编写的一个自定义子类，用于将ETA/流逝时间格式化为更好读的格式:

import datetime
from progress.bar import IncrementalBar


class ProgressBar(IncrementalBar):
    '''
    My custom progress bar that:
       - Show %, count, elapsed, eta
       - Time is shown in H:M:S format
    '''

    message = 'Progress'
    suffix  = '%(percent).1f%% (%(index)d/%(max)d) -- %(elapsed_min)s (eta: %(eta_min)s)'

    def formatTime(self, seconds):
        return str(datetime.timedelta(seconds=seconds))

    @property
    def elapsed_min(self):
        return self.formatTime(self.elapsed)

    @property
    def eta_min(self):
        return self.formatTime(self.eta)

if __name__=='__main__':
    counter = 120
    bar     = ProgressBar('Processing', max=counter)

    for i in range(counter):
        bar.next()
        time.sleep(1)

    bar.finish()

我想我有点晚了，但这应该适用于使用当前版本的python 3的人，因为这使用了“f-strings”，正如python 3.6 PEP 498中介绍的那样:

Code

from numpy import interp

class Progress:
    def __init__(self, value, end, title='Downloading',buffer=20):
        self.title = title
        #when calling in a for loop it doesn't include the last number
        self.end = end -1
        self.buffer = buffer
        self.value = value
        self.progress()

    def progress(self):
        maped = int(interp(self.value, [0, self.end], [0, self.buffer]))
        print(f'{self.title}: [{"#"*maped}{"-"*(self.buffer - maped)}]{self.value}/{self.end} {((self.value/self.end)*100):.2f}%', end='\r')

例子

#some loop that does perfroms a task
for x in range(21)  #set to 21 to include until 20
    Progress(x, 21)

输出

Downloading: [########------------] 8/20 40.00%

使用os_sys lib:

我在许多类型的条形图中使用它，例如:

from os_sys.progress import bar as Bar
bar = Bar('progresing: ', max=20)
for i in range(20):
    #do somthing
    bar.next()
bar.finish()

你的输出将是:

procesing:  |######                          | 2/10

请在os_sys的描述中阅读更多信息

from IPython.display import clear_output
progress_bar=u"\u001b[7m Loading: "
for i in range(100):
    clear_output(wait=True)
    progress_bar+=u"\u001b[7m "
    print(progress_bar+str(i+1)+"%")
    time.sleep(0.03) #you can change the speed

输出

这是我的简单解决方案:

import time

def progress(_cur, _max):
    p = round(100*_cur/_max)
    b = f"Progress: {p}% - ["+"."*int(p/5)+" "*(20-int(p/5))+"]"
    print(b, end="\r")

# USAGE:
for i in range(0,101):
    time.sleep(0.1) 
    progress(i,100)

print("..."*5, end="\r")
print("Done")

在这里寻找等效的解决方案后，我只是为我的需求做了一个简单的进度类。我想我应该把它贴出来。

from __future__ import print_function
import sys
import re


class ProgressBar(object):
    DEFAULT = 'Progress: %(bar)s %(percent)3d%%'
    FULL = '%(bar)s %(current)d/%(total)d (%(percent)3d%%) %(remaining)d to go'

    def __init__(self, total, width=40, fmt=DEFAULT, symbol='=',
                 output=sys.stderr):
        assert len(symbol) == 1

        self.total = total
        self.width = width
        self.symbol = symbol
        self.output = output
        self.fmt = re.sub(r'(?P<name>%\(.+?\))d',
            r'\g<name>%dd' % len(str(total)), fmt)

        self.current = 0

    def __call__(self):
        percent = self.current / float(self.total)
        size = int(self.width * percent)
        remaining = self.total - self.current
        bar = '[' + self.symbol * size + ' ' * (self.width - size) + ']'

        args = {
            'total': self.total,
            'bar': bar,
            'current': self.current,
            'percent': percent * 100,
            'remaining': remaining
        }
        print('\r' + self.fmt % args, file=self.output, end='')

    def done(self):
        self.current = self.total
        self()
        print('', file=self.output)

例子:

from time import sleep

progress = ProgressBar(80, fmt=ProgressBar.FULL)

for x in xrange(progress.total):
    progress.current += 1
    progress()
    sleep(0.1)
progress.done()

将打印以下内容:

[========] 17/80 (21%) 63