我得到了一个AsyncTask,应该检查对主机名的网络访问。但是doInBackground()永远不会超时。有人知道吗?

public class HostAvailabilityTask extends AsyncTask<String, Void, Boolean> {

    private Main main;

    public HostAvailabilityTask(Main main) {
        this.main = main;
    }

    protected Boolean doInBackground(String... params) {
        Main.Log("doInBackground() isHostAvailable():"+params[0]);

        try {
            return InetAddress.getByName(params[0]).isReachable(30); 
        } catch (UnknownHostException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }
        return false;       
    }

    protected void onPostExecute(Boolean... result) {
        Main.Log("onPostExecute()");

        if(result[0] == false) {
            main.setContentView(R.layout.splash);
            return;
        }

        main.continueAfterHostCheck();
    }   
}

当前回答

可以通过该方法检测网络可用性-

public static boolean isDeviceOnline(Context context) {
        boolean isConnectionAvail = false;
        try {
            ConnectivityManager cm = (ConnectivityManager) context
                    .getSystemService(Context.CONNECTIVITY_SERVICE);
            NetworkInfo netInfo = cm.getActiveNetworkInfo();
            return netInfo.isConnected();
        } catch (Exception e) {
            e.printStackTrace();
        }
        return isConnectionAvail;
    }

其他回答

不要忘记将这些权限添加到您的manifest:

<uses-permission android:name="android.permission.INTERNET" />
<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />

你也可以用下面的代码上网查看:

 public class CheckInternetConnection {
        public Context context = null;

        public CheckInternetConnection(Context ctx) {
            this.context = ctx;
        }

        public boolean CheckInternet() {
            return isOnline();
        }
        public Boolean isOnline() 
        {
            try {
                if(isNetAvailable(context))
                    return true;
                else
                {
                    try {
                        URL url = new URL("http://www.google.com");
                        HttpURLConnection urlc = (HttpURLConnection) url
                                .openConnection();
                        urlc.setRequestProperty("User-Agent", "Test");
                        urlc.setRequestProperty("Connection", "close");
                        urlc.setConnectTimeout(3000); // This is time limit if the
                        // connection time limit
                        try {
                            urlc.connect();
                            Log.e("TAG", " urlc ----------" + urlc.getResponseCode());
                            if (urlc.getResponseCode() == 200) {
                                return true;
                            }
                        }catch (Exception e){
                            e.printStackTrace();
                        }
                    } catch (MalformedURLException e1) {
                        e1.printStackTrace();
                    } catch (IOException e) {
                        e.printStackTrace();
                    }
                }
            }catch (Exception e){
                e.printStackTrace();
            }

            return false;        
        }

         public synchronized static boolean isNetAvailable(Context context){

             try{
             boolean isNetAvailable=false;
             if ( context != null )
             {
                 ConnectivityManager mgr = (ConnectivityManager) context.getSystemService(Context.CONNECTIVITY_SERVICE);
                 if ( mgr != null )
                 {
                     boolean mobileNetwork = false;
                     boolean wifiNetwork = false;
                     boolean wiMaxNetwork = false;

                     boolean mobileNetworkConnecetd = false;
                     boolean wifiNetworkConnecetd = false;
                     boolean wiMaxNetworkConnected = false;

                     NetworkInfo mobileInfo = mgr.getNetworkInfo(ConnectivityManager.TYPE_MOBILE);
                     NetworkInfo wifiInfo = mgr.getNetworkInfo(ConnectivityManager.TYPE_WIFI);
                     NetworkInfo wiMaxInfo = mgr.getNetworkInfo(ConnectivityManager.TYPE_WIMAX);

                     if ( mobileInfo != null )
                         mobileNetwork = mobileInfo.isAvailable();                   

                     if ( wifiInfo != null )
                         wifiNetwork = wifiInfo.isAvailable();

                     if(wiMaxInfo != null)
                         wiMaxNetwork = wiMaxInfo.isAvailable();

                     if(wifiNetwork == true)
                         wifiNetworkConnecetd = wifiInfo.isConnectedOrConnecting();
                     if(mobileNetwork == true)
                         mobileNetworkConnecetd = mobileInfo.isConnectedOrConnecting();
                     if(wiMaxNetwork == true)
                         wiMaxNetworkConnected = wiMaxInfo.isConnectedOrConnecting();

                     isNetAvailable = ( mobileNetworkConnecetd || wifiNetworkConnecetd || wiMaxNetworkConnected );
                 }
             }
             return isNetAvailable;
             }catch(NullPointerException e)
             {
                 return false;
             }catch(Exception e)
             {
                 return false;
             }
         }


    }

我已经应用了@Levit提供的解决方案,并创建了不会调用额外Http请求的函数。

它将解决无法解析主机的错误

public static boolean isInternetAvailable(Context context) {
    ConnectivityManager cm = (ConnectivityManager) context.getSystemService(Context.CONNECTIVITY_SERVICE);
    NetworkInfo activeNetwork = cm.getActiveNetworkInfo();
    if (activeNetwork == null) return false;

    switch (activeNetwork.getType()) {
        case ConnectivityManager.TYPE_WIFI:
            if ((activeNetwork.getState() == NetworkInfo.State.CONNECTED ||
                    activeNetwork.getState() == NetworkInfo.State.CONNECTING) &&
                    isInternet())
                return true;
            break;
        case ConnectivityManager.TYPE_MOBILE:
            if ((activeNetwork.getState() == NetworkInfo.State.CONNECTED ||
                    activeNetwork.getState() == NetworkInfo.State.CONNECTING) &&
                    isInternet())
                return true;
            break;
        default:
            return false;
    }
    return false;
}

private static boolean isInternet() {

    Runtime runtime = Runtime.getRuntime();
    try {
        Process ipProcess = runtime.exec("/system/bin/ping -c 1 8.8.8.8");
        int exitValue = ipProcess.waitFor();
        Debug.i(exitValue + "");
        return (exitValue == 0);
    } catch (IOException | InterruptedException e) {
        e.printStackTrace();
    }

    return false;
}

现在叫它,

if (!isInternetAvailable(getActivity())) {
     //Show message
} else {
     //Perfoem the api request
}

这里有一个简单的解决方案,以确保你的应用程序可以访问互联网:

static final String CHECK_INTERNET_ACCESS_URL = "https://www.google.com";

public static void isInternetAccessWorking(Context context) {

    StringRequest stringRequest = new StringRequest(Request.Method.GET, CHECK_INTERNET_ACCESS_URL,
            new Response.Listener<String>() {
                @Override
                public void onResponse(String response) {
                    // Internet access is OK
                }
            }, new Response.ErrorListener() {
        @Override
        public void onErrorResponse(VolleyError error) {
            // NO internet access
        }
    });

    Volley.newRequestQueue(context).add(stringRequest);
}

这个解决方案使用Android的Volley库,必须在build.gradle中声明:

implementation 'com.android.volley:volley:1.1.1'

如果设备处于飞行模式(或者假设在没有可用网络的其他情况下),cm.getActiveNetworkInfo()将为空,因此您需要添加一个空检查。

修改(Eddie的解决方案)如下:

public boolean isOnline() {
    ConnectivityManager cm =
        (ConnectivityManager) getSystemService(Context.CONNECTIVITY_SERVICE);
    NetworkInfo netInfo = cm.getActiveNetworkInfo();
    return netInfo != null && netInfo.isConnectedOrConnecting();
}

在AndroidManifest.xml中添加以下权限:

<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />

还有一点,如果你在给定的时间点绝对需要一个网络连接,那么使用netInfo.isConnected()而不是netInfo.isConnectedOrConnecting可能会更好。不过,我想这取决于个人用例。