我得到了一个AsyncTask，应该检查对主机名的网络访问。但是doInBackground()永远不会超时。有人知道吗?
public class HostAvailabilityTask extends AsyncTask<String, Void, Boolean> {
private Main main;
public HostAvailabilityTask(Main main) {
this.main = main;
}
protected Boolean doInBackground(String... params) {
Main.Log("doInBackground() isHostAvailable():"+params[0]);
try {
return InetAddress.getByName(params[0]).isReachable(30);
} catch (UnknownHostException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
return false;
}
protected void onPostExecute(Boolean... result) {
Main.Log("onPostExecute()");
if(result[0] == false) {
main.setContentView(R.layout.splash);
return;
}
main.continueAfterHostCheck();
}
}
正如Android文档建议的那样，之后
getActiveNetworkInfo()在Android 10中已弃用。使用
而不是针对Android 10 (API级别)的应用程序的NetworkCallbacks
29)更高。
下面是我们目前检查网络连接的方法:
val cm = context.getSystemService(Context.CONNECTIVITY_SERVICE) as ConnectivityManager
val activeNetwork: NetworkInfo? = cm.activeNetworkInfo
val isConnected: Boolean = activeNetwork?.isConnectedOrConnecting == true
使用NetworkCallbacks检查网络连接的新方法
步骤1:
private lateinit var connectivityManager:ConnectivityManager
override fun onCreate(savedInstanceState: Bundle?) {
super.onCreate(savedInstanceState)
...
connectivityManager = getSystemService(Context.CONNECTIVITY_SERVICE) as ConnectivityManager
}
步骤2:创建回调:
private val callback = object : ConnectivityManager.NetworkCallback() {
override fun onAvailable(network: Network) {
super.onAvailable(network)
Timber.e("Network:onAvailable")
}
override fun onLost(network: Network) {
super.onLost(network)
Timber.e("Network:onLost")
}
}
步骤3:注册和取消注册回调:
private fun registerNetworkCallback() {
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.N) {
connectivityManager.registerDefaultNetworkCallback(callback)
} else {
// Old way to check network connection
}
}
override fun onStop() {
unRegisterNetworkCallback()
super.onStop()
}
private fun unRegisterNetworkCallback() {
connectivityManager.unregisterNetworkCallback(callback)
}
结帐更新详情如下链接:
https://developer.android.com/training/monitoring-device-state/connectivity-status-type
我已经应用了@Levit提供的解决方案，并创建了不会调用额外Http请求的函数。
它将解决无法解析主机的错误
public static boolean isInternetAvailable(Context context) {
ConnectivityManager cm = (ConnectivityManager) context.getSystemService(Context.CONNECTIVITY_SERVICE);
NetworkInfo activeNetwork = cm.getActiveNetworkInfo();
if (activeNetwork == null) return false;
switch (activeNetwork.getType()) {
case ConnectivityManager.TYPE_WIFI:
if ((activeNetwork.getState() == NetworkInfo.State.CONNECTED ||
activeNetwork.getState() == NetworkInfo.State.CONNECTING) &&
isInternet())
return true;
break;
case ConnectivityManager.TYPE_MOBILE:
if ((activeNetwork.getState() == NetworkInfo.State.CONNECTED ||
activeNetwork.getState() == NetworkInfo.State.CONNECTING) &&
isInternet())
return true;
break;
default:
return false;
}
return false;
}
private static boolean isInternet() {
Runtime runtime = Runtime.getRuntime();
try {
Process ipProcess = runtime.exec("/system/bin/ping -c 1 8.8.8.8");
int exitValue = ipProcess.waitFor();
Debug.i(exitValue + "");
return (exitValue == 0);
} catch (IOException | InterruptedException e) {
e.printStackTrace();
}
return false;
}
现在叫它，
if (!isInternetAvailable(getActivity())) {
//Show message
} else {
//Perfoem the api request
}
这里有一个简单的解决方案，以确保你的应用程序可以访问互联网:
static final String CHECK_INTERNET_ACCESS_URL = "https://www.google.com";
public static void isInternetAccessWorking(Context context) {
StringRequest stringRequest = new StringRequest(Request.Method.GET, CHECK_INTERNET_ACCESS_URL,
new Response.Listener<String>() {
@Override
public void onResponse(String response) {
// Internet access is OK
}
}, new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
// NO internet access
}
});
Volley.newRequestQueue(context).add(stringRequest);
}
这个解决方案使用Android的Volley库，必须在build.gradle中声明:
implementation 'com.android.volley:volley:1.1.1'
