是否可以在ES6类中创建私有属性?
举个例子。 如何阻止访问instance.property?
class Something {
constructor(){
this.property = "test";
}
}
var instance = new Something();
console.log(instance.property); //=> "test"
是否可以在ES6类中创建私有属性?
举个例子。 如何阻止访问instance.property?
class Something {
constructor(){
this.property = "test";
}
}
var instance = new Something();
console.log(instance.property); //=> "test"
当前回答
我们可以使用getter和setter来模拟类的私有属性。
eg 1
class FootballClub {
constructor (cname, cstadium, ccurrentmanager) {
this.name = cname;
this._stadium = cstadium; // we will treat this prop as private and give getter and setter for this.
this.currmanager = ccurrentmanager;
}
get stadium( ) {
return this._stadium.toUpperCase();
}
}
let club = new FootballClub("Arsenal", "Emirates" , "Arteta")
console.log(club);
//FootballClub {
// name: 'Arsenal',
// _stadium: 'Emirates',
// currmanager: 'Arteta'
// }
console.log( club.stadium ); // EMIRATES
club.stadium = "Highbury"; // TypeError: Cannot set property stadium of #<FootballClub> which has only a getter
在上面的例子中,我们没有给出stadium的setter方法,因此我们不能为它设置一个新值。在接下来的例子中,为体育场添加了一个setter
eg 2
class FootballClub {
constructor (cname, cstadium, ccurrentmanager) {
this.name = cname;
this._stadium = cstadium; // we will treat this prop as private and give getter and setter for this.
this.currmanager = ccurrentmanager;
}
get stadium( ) {
return this._stadium.toUpperCase();
}
set stadium(val) {
this._stadium = val;
}
}
let club = new FootballClub("Arsenal", "Emirates" , "Arteta")
console.log(club.stadium); // EMIRATES
club.stadium = "Emirates Stadium";
console.log(club.stadium); // EMIRATES STADIUM
其他回答
现在大多数浏览器都支持私有类特性。
class Something {
#property;
constructor(){
this.#property = "test";
}
#privateMethod() {
return 'hello world';
}
getPrivateMessage() {
return this.#property;
}
}
const instance = new Something();
console.log(instance.property); //=> undefined
console.log(instance.privateMethod); //=> undefined
console.log(instance.getPrivateMessage()); //=> test
console.log(instance.#property); //=> Syntax error
来这个派对很晚,但我在搜索中碰到了OP问题,所以… 是的,您可以通过将类声明包装在闭包中来拥有私有属性
这里有一个我如何在这个代码依赖中拥有私有方法的例子。在下面的代码片段中,Subscribable类有两个“私有”函数process和processCallbacks。任何属性都可以以这种方式添加,并且通过使用闭包将它们保持为私有。如果关注点被很好地分离,并且Javascript不需要通过添加更多的语法而变得臃肿,当闭包整齐地完成工作时,隐私是一个罕见的需求。
const Subscribable = (function(){
const process = (self, eventName, args) => {
self.processing.set(eventName, setTimeout(() => processCallbacks(self, eventName, args)))};
const processCallbacks = (self, eventName, args) => {
if (self.callingBack.get(eventName).length > 0){
const [nextCallback, ...callingBack] = self.callingBack.get(eventName);
self.callingBack.set(eventName, callingBack);
process(self, eventName, args);
nextCallback(...args)}
else {
delete self.processing.delete(eventName)}};
return class {
constructor(){
this.callingBack = new Map();
this.processing = new Map();
this.toCallbacks = new Map()}
subscribe(eventName, callback){
const callbacks = this.unsubscribe(eventName, callback);
this.toCallbacks.set(eventName, [...callbacks, callback]);
return () => this.unsubscribe(eventName, callback)} // callable to unsubscribe for convenience
unsubscribe(eventName, callback){
let callbacks = this.toCallbacks.get(eventName) || [];
callbacks = callbacks.filter(subscribedCallback => subscribedCallback !== callback);
if (callbacks.length > 0) {
this.toCallbacks.set(eventName, callbacks)}
else {
this.toCallbacks.delete(eventName)}
return callbacks}
emit(eventName, ...args){
this.callingBack.set(eventName, this.toCallbacks.get(eventName) || []);
if (!this.processing.has(eventName)){
process(this, eventName, args)}}}})();
我喜欢这种方法,因为它很好地分离了关注点,并保持了真正的私密性。唯一的缺点是需要使用'self'(或类似的东西)在私有内容中引用'this'。
答案是“不”。但是你可以像这样创建对属性的私有访问:
使用模块。模块中的所有内容都是私有的,除非使用export关键字将其设为公有。 在模块内部,使用函数闭包:http://www.kirupa.com/html5/closures_in_javascript.htm
(可以使用符号来确保隐私的建议在ES6规范的早期版本中是正确的,但现在不再是这样:https://mail.mozilla.org/pipermail/es-discuss/2014-January/035604.html和https://stackoverflow.com/a/22280202/1282216。有关符号和隐私的详细讨论,请参阅:https://curiosity-driven.org/private-properties-in-javascript)
就我个人而言,我喜欢绑定操作符::的建议,然后将其与@d13提到的解决方案结合起来,但现在坚持使用@d13的答案,在这里您为类使用export关键字,并将私有函数放在模块中。
还有一个棘手的解决方案,这里没有提到,下面是更实用的方法,将允许它在类中拥有所有的私有道具/方法。
Private.js
export const get = state => key => state[key];
export const set = state => (key,value) => { state[key] = value; }
. js
import { get, set } from './utils/Private'
export default class Test {
constructor(initialState = {}) {
const _set = this.set = set(initialState);
const _get = this.get = get(initialState);
this.set('privateMethod', () => _get('propValue'));
}
showProp() {
return this.get('privateMethod')();
}
}
let one = new Test({ propValue: 5});
let two = new Test({ propValue: 8});
two.showProp(); // 8
one.showProp(); // 5
请对此提出意见。
我用这个模式,它总是对我有效
class Test { constructor(data) { class Public { constructor(prv) { // public function (must be in constructor on order to access "prv" variable) connectToDb(ip) { prv._db(ip, prv._err); } } // public function w/o access to "prv" variable log() { console.log("I'm logging"); } } // private variables this._data = data; this._err = function(ip) { console.log("could not connect to "+ip); } } // private function _db(ip, err) { if(!!ip) { console.log("connected to "+ip+", sending data '"+this.data+"'"); return true; } else err(ip); } } var test = new Test(10), ip = "185.167.210.49"; test.connectToDb(ip); // true test.log(); // I'm logging test._err(ip); // undefined test._db(ip, function() { console.log("You have got hacked!"); }); // undefined