是否可以在ES6类中创建私有属性?

举个例子。 如何阻止访问instance.property?

class Something {
  constructor(){
    this.property = "test";
  }
}

var instance = new Something();
console.log(instance.property); //=> "test"

当前回答

这里,myThing变量是私有的,是闭包的一部分:

class Person {
  constructor() {

    var myThing = "Hello World";

    return {
      thing: myThing,
      sayThing: this.sayThing
    }
  }

  sayThing() {
    console.log(this.thing);
  }
}

var person = new Person();

console.log(person);

其他回答

是的-你可以创建封装的属性,但它没有与访问修饰符(公共|私有)至少不是与ES6。

下面是一个简单的例子,如何用ES6完成:

用类词创建类

2在构造函数内部使用let OR const保留字声明块作用域变量->因为它们是块作用域,所以不能从外部访问(封装)

为了允许对这些变量进行一些访问控制(setter |getter),你可以在它的构造函数中使用:this.methodName=function(){}语法声明实例方法

"use strict";
    class Something{
        constructor(){
            //private property
            let property="test";
            //private final (immutable) property
            const property2="test2";
            //public getter
            this.getProperty2=function(){
                return property2;
            }
            //public getter
            this.getProperty=function(){
                return property;
            }
            //public setter
            this.setProperty=function(prop){
                property=prop;
            }
        }
    }

现在让我们检查一下:

var s=new Something();
    console.log(typeof s.property);//undefined 
    s.setProperty("another");//set to encapsulated `property`
    console.log(s.getProperty());//get encapsulated `property` value
    console.log(s.getProperty2());//get encapsulated immutable `property2` value

Yes totally can, and pretty easily too. This is done by exposing your private variables and functions by returning the prototype object graph in the constructor. This is nothing new, but take a bit of js foo to understand the elegance of it. This way does not use global scoped, or weakmaps. It is a form of reflection built into the language. Depending on how you leverage this; one can either force an exception which interrupts the call stack, or bury the exception as an undefined. This is demonstarted below, and can read more about these features here

class Clazz { constructor() { var _level = 1 function _private(x) { return _level * x; } return { level: _level, public: this.private, public2: function(x) { return _private(x); }, public3: function(x) { return _private(x) * this.public(x); }, }; } private(x) { return x * x; } } var clazz = new Clazz(); console.log(clazz._level); //undefined console.log(clazz._private); // undefined console.log(clazz.level); // 1 console.log(clazz.public(1)); //1 console.log(clazz.public2(2)); //2 console.log(clazz.public3(3)); //27 console.log(clazz.private(0)); //error

在JS中获得真正隐私的唯一方法是通过作用域,因此不可能有一个属性是this的成员,只能在组件内部访问。在ES6中存储真正私有数据的最佳方法是使用WeakMap。

const privateProp1 = new WeakMap();
const privateProp2 = new WeakMap();

class SomeClass {
  constructor() {
    privateProp1.set(this, "I am Private1");
    privateProp2.set(this, "I am Private2");

    this.publicVar = "I am public";
    this.publicMethod = () => {
      console.log(privateProp1.get(this), privateProp2.get(this))
    };        
  }

  printPrivate() {
    console.log(privateProp1.get(this));
  }
}

显然,这可能是一个缓慢的,肯定是丑陋的,但它确实提供了隐私。

请记住,即使这样也不是完美的,因为Javascript是动态的。有人仍然可以这样做

var oldSet = WeakMap.prototype.set;
WeakMap.prototype.set = function(key, value){
    // Store 'this', 'key', and 'value'
    return oldSet.call(this, key, value);
};

为了在值被存储时捕获它们,所以如果你想格外小心的话,你需要捕获一个对.set和.get的本地引用来显式使用,而不是依赖于可覆盖的原型。

const {set: WMSet, get: WMGet} = WeakMap.prototype;

const privateProp1 = new WeakMap();
const privateProp2 = new WeakMap();

class SomeClass {
  constructor() {
    WMSet.call(privateProp1, this, "I am Private1");
    WMSet.call(privateProp2, this, "I am Private2");

    this.publicVar = "I am public";
    this.publicMethod = () => {
      console.log(WMGet.call(privateProp1, this), WMGet.call(privateProp2, this))
    };        
  }

  printPrivate() {
    console.log(WMGet.call(privateProp1, this));
  }
}

更新:看别人的回答,这个已经过时了。

简单的回答,不,ES6类不支持私有属性。

但是你可以模仿这种行为,不将新属性附加到对象,而是将它们保存在类构造函数中,并使用getter和setter来获取隐藏的属性。注意,在类的每个新实例上重新定义getter和setter。

ES6

class Person {
    constructor(name) {
        var _name = name
        this.setName = function(name) { _name = name; }
        this.getName = function() { return _name; }
    }
}

ES5

function Person(name) {
    var _name = name
    this.setName = function(name) { _name = name; }
    this.getName = function() { return _name; }
}

大多数答案要么说不可能,要么要求你使用WeakMap或Symbol,这是ES6的特性,可能需要腻子。然而,还有另一种方法!看看这个:

// 1. Create closure var SomeClass = function() { // 2. Create `key` inside a closure var key = {}; // Function to create private storage var private = function() { var obj = {}; // return Function to access private storage using `key` return function(testkey) { if(key === testkey) return obj; // If `key` is wrong, then storage cannot be accessed console.error('Cannot access private properties'); return undefined; }; }; var SomeClass = function() { // 3. Create private storage this._ = private(); // 4. Access private storage using the `key` this._(key).priv_prop = 200; }; SomeClass.prototype.test = function() { console.log(this._(key).priv_prop); // Using property from prototype }; return SomeClass; }(); // Can access private property from within prototype var instance = new SomeClass(); instance.test(); // `200` logged // Cannot access private property from outside of the closure var wrong_key = {}; instance._(wrong_key); // undefined; error logged

我称这个方法为accessor pattern。基本思想是我们有一个闭包,闭包中有一个键,我们创建一个私有对象(在构造函数中),只有当你拥有键时才能访问它。

如果你感兴趣,你可以在我的文章中阅读更多有关这方面的内容。使用此方法,可以为每个对象创建不能在闭包外部访问的属性。因此,你可以在构造函数或原型中使用它们,但不能在其他任何地方使用。我还没有在任何地方见过这种方法,但我认为它真的很强大。