在安卓系统中防止双击按钮的最佳方法是什么?
当前回答
I found none of these suggestions works if the onClick method doesn't return immediately. The touch event is queued by Android and the next onClick is called only after the first one is finished. (Since this is done on the one UI thread this is really normal.) I needed to use the time when the the onClick function is finished + one boolean variable to mark whether the given onClick is running. Both these marker attributes are static to avoid any onClickListener to run at the same time. (If user clicks on another button) You can simple replace your OnClickListener to this class and instead of implementing the onClick method you need to implement the abstract oneClick() method.
abstract public class OneClickListener implements OnClickListener {
private static boolean started = false;
private static long lastClickEndTime = 0;
/* (non-Javadoc)
* @see android.view.View.OnClickListener#onClick(android.view.View)
*/
@Override
final public void onClick(final View v) {
if(started || SystemClock.elapsedRealtime()-lastClickEndTime <1000 ){
Log.d(OneClickListener.class.toString(), "Rejected double click, " + new Date().toString() );
return;
}
Log.d(OneClickListener.class.toString(), "One click, start: " + new Date().toString() );
try{
started = true;
oneClick(v);
}finally{
started = false;
lastClickEndTime = SystemClock.elapsedRealtime();
Log.d(OneClickListener.class.toString(), "One click, end: " + new Date().toString() );
}
}
abstract protected void oneClick(View v);
}
其他回答
我的解决方案是尝试使用一个布尔变量:
public class Blocker {
private static final int DEFAULT_BLOCK_TIME = 1000;
private boolean mIsBlockClick;
/**
* Block any event occurs in 1000 millisecond to prevent spam action
* @return false if not in block state, otherwise return true.
*/
public boolean block(int blockInMillis) {
if (!mIsBlockClick) {
mIsBlockClick = true;
new Handler().postDelayed(new Runnable() {
@Override
public void run() {
mIsBlockClick = false;
}
}, blockInMillis);
return false;
}
return true;
}
public boolean block() {
return block(DEFAULT_BLOCK_TIME);
}
}
并使用如下:
view.setOnClickListener(new View.OnClickListener() {
private Blocker mBlocker = new Blocker();
@Override
public void onClick(View v) {
if (!mBlocker.block(block-Time-In-Millis)) {
// do your action
}
}
});
更新:Kotlin解决方案,使用视图扩展
fun View.safeClick(listener: View.OnClickListener, blockInMillis: Long = 500) {
var lastClickTime: Long = 0
this.setOnClickListener {
if (SystemClock.elapsedRealtime() - lastClickTime < blockInMillis) return@setOnClickListener
lastClickTime = SystemClock.elapsedRealtime()
listener.onClick(this)
}
}
加上Jim的回答,代码可以变得更简洁:
fun View.setOnSingleClick(onClick: () -> Unit) {
var lastClickTime = 0L
setOnClickListener {
if (currentTimeMillis() > lastClickTime + 750) onClick()
lastClickTime = currentTimeMillis()
}
}
用法:
aView.setOnSingleClick { }
我需要与片段一起工作,只是放一个标志来控制点击:我只想要第一个,其他的不能访问监听器
private boolean flag = true;
...
@Override
public void onClick(View view) {
...
if (flag) {
...
listener.onFragmentInteraction(Constants.MY_FRAGMENT, bundle);
flag = false;
}
...
}
希望对大家有用,有不正确的地方请指正
似乎设置你的点击监听器在onResume和空他们在onPause也有技巧。
我用两个类来解决这个问题,一个类似于@jinshiyi11的答案,另一个是基于显式点击,在这里你只能点击一个按钮一次,如果你想要另一次点击,你必须显式地指出它。
/**
* Listener que sólo permite hacer click una vez, para poder hacer click
* posteriormente se necesita indicar explicitamente.
*
* @author iberck
*/
public abstract class OnExplicitClickListener implements View.OnClickListener {
// you can perform a click only once time
private boolean canClick = true;
@Override
public synchronized void onClick(View v) {
if (canClick) {
canClick = false;
onOneClick(v);
}
}
public abstract void onOneClick(View v);
public synchronized void enableClick() {
canClick = true;
}
public synchronized void disableClick() {
canClick = false;
}
}
使用示例:
OnExplicitClickListener clickListener = new OnExplicitClickListener() {
public void onOneClick(View v) {
Log.d("example", "explicit click");
...
clickListener.enableClick();
}
}
button.setOnClickListener(clickListener);
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