在安卓系统中防止双击按钮的最佳方法是什么?
当前回答
下面是一个OnClickListener代理,它可以根据qezt的答案阻止连续的单击。
import android.os.SystemClock;
import android.view.View;
public class MultiClickGuard implements View.OnClickListener {
private long mLastClickTime;
private final int mThresholdMillis;
private final View.OnClickListener mListener;
public MultiClickGuard(View.OnClickListener listener, int thresholdMillis) {
if (listener == null) {
throw new NullPointerException("Null OnClickListener");
}
if (thresholdMillis < 0) {
throw new IllegalArgumentException("Negative click threshold: " + thresholdMillis);
}
mListener = listener;
mThresholdMillis = thresholdMillis;
}
@Override
public void onClick(View v) {
// Using a time threshold to prevent successive clicks.
if (SystemClock.elapsedRealtime() - mLastClickTime < mThresholdMillis) {
return;
}
mLastClickTime = SystemClock.elapsedRealtime();
// Forward the click event to the *real* listener.
mListener.onClick(v);
}
}
用法示例
button.setOnClickListener(new MultiClickGuard(new View.OnClickListener() {
@Override
public void onClick(View v) {
// do something
}
}, 1000));
button.setOnClickListener(new MultiClickGuard(v -> {...}, 1000));
button.setOnClickListener(new MultiClickGuard(v -> doSomething(), 1000));
在试图阻止启动一个活动的多个实例的情况下,考虑指定启动模式:理解任务和返回堆栈,这是可靠的方式。
如果您试图阻止打开一个对话框片段的多个实例,您可以检查片段管理器是否已经包含了对话框,例如getSupportFragmentManager(). findfragmentbytag (tag)。
其他回答
试试这个,它是有效的:
mButton.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
mSlotLayout.setEnabled(false);
// do your work here
Timer buttonTimer = new Timer();
buttonTimer.schedule(new TimerTask() {
@Override
public void run() {
runOnUiThread(new Runnable() {
@Override
public void run() {
mButton.setEnabled(true);
}
});
}
}, 500); // delay button enable for 0.5 sec
}
});
我希望这能帮助你,把代码放在你的事件处理程序。
// --------------------------------------------------------------------------------
boolean hasTag = null != which.getTag( R.id.preventing_double_click_tag );
if ( hasTag ) {
// Do not handle again...
return;
} else {
which.setTag( R.id.action, Boolean.TRUE );
which.postDelayed( new Runnable() {
@Override
public void run() {
which.setTag( R.id.action, null );
Log.d( "onActin", " The preventing double click tag was removed." );
}
}, 2000 );
}
我的解决方案是尝试使用一个布尔变量:
public class Blocker {
private static final int DEFAULT_BLOCK_TIME = 1000;
private boolean mIsBlockClick;
/**
* Block any event occurs in 1000 millisecond to prevent spam action
* @return false if not in block state, otherwise return true.
*/
public boolean block(int blockInMillis) {
if (!mIsBlockClick) {
mIsBlockClick = true;
new Handler().postDelayed(new Runnable() {
@Override
public void run() {
mIsBlockClick = false;
}
}, blockInMillis);
return false;
}
return true;
}
public boolean block() {
return block(DEFAULT_BLOCK_TIME);
}
}
并使用如下:
view.setOnClickListener(new View.OnClickListener() {
private Blocker mBlocker = new Blocker();
@Override
public void onClick(View v) {
if (!mBlocker.block(block-Time-In-Millis)) {
// do your action
}
}
});
更新:Kotlin解决方案,使用视图扩展
fun View.safeClick(listener: View.OnClickListener, blockInMillis: Long = 500) {
var lastClickTime: Long = 0
this.setOnClickListener {
if (SystemClock.elapsedRealtime() - lastClickTime < blockInMillis) return@setOnClickListener
lastClickTime = SystemClock.elapsedRealtime()
listener.onClick(this)
}
}
在Java中有一个本地debounce click监听器
view.setOnClickListener(new DebouncedOnClickListener(1000) { //in milisecs
@Override
public void onDebouncedClick(View v) {
//action
}
});
这是我的解决方案:
if (waitDouble) {
waitDouble = false;
Thread thread = new Thread() {
@Override
public void run() {
try {
sleep(300);
if (waitDouble == false) {
waitDouble = true;
singleClick(); //singleClick
}
} catch (InterruptedException e) {
e.printStackTrace();
}
}
};
thread.start();
} else {//DoubleClick
DoubleClick();
waitDouble = true;
}
或者另一种解决方案:
public class NoDoubleClickUtils {
private static long lastClickTime;
private final static int SPACE_TIME = 500;
public static void initLastClickTime() {
lastClickTime = 0;
}
public synchronized static boolean isDoubleClick() {
long currentTime = System.currentTimeMillis();
boolean isClick2;
if (currentTime - lastClickTime > SPACE_TIME) {
isClick2 = false;
} else {
isClick2 = true;
}
lastClickTime = currentTime;
return isClick2;
}
}
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