在安卓系统中防止双击按钮的最佳方法是什么?
当前回答
我们可以像这样使用按钮进行同步:
示例#1 (Java)
@Override
public void onClick(final View view) {
synchronized (view) {
view.setEnabled(false);
switch (view.getId()) {
case R.id.id1:
...
break;
case R.id.id2:
...
break;
...
}
new Handler().postDelayed(new Runnable() {
@Override
public void run() {
view.setEnabled(true);
}
}, 1000);
}
}
示例#2 (kotlin)使用synchronized
myButton.setOnClickListener { view ->
synchronized(view) {
view.isEnabled = false
// do something
view.postDelayed({ view.isEnabled = true }, 500L)
}
}
祝你好运)
其他回答
Kotlin创建类SafeClickListener
class SafeClickListener(
private var defaultInterval: Int = 1000,
private val onSafeCLick: (View) -> Unit
) : View.OnClickListener {
private var lastTimeClicked: Long = 0 override fun onClick(v: View) {
if (SystemClock.elapsedRealtime() - lastTimeClicked < defaultInterval) {
return
}
lastTimeClicked = SystemClock.elapsedRealtime()
onSafeCLick(v)
}
}
在baseClass或else中创建一个函数
fun View.setSafeOnClickListener(onSafeClick: (View) -> Unit) {val safeClickListener = SafeClickListener {
onSafeClick(it)
}
setOnClickListener(safeClickListener)
}
并使用按钮点击
btnSubmit.setSafeOnClickListener {
showSettingsScreen()
}
对我来说,只有记住时间戳并检查它(距离上次点击超过1秒)才有帮助。
只有2步,你可以在你的应用程序的任何地方使用它。
步骤1。创建一个单例管理器[避免多次点击]
package com.im.av.mediator;
import android.os.SystemClock;
import java.util.HashMap;
/**
* Created by ShuHeng on 16/6/1.
*/
public class ClickManager {
private HashMap<Integer,Long> laskClickTimeMap=new HashMap<Integer,Long>();
public volatile static ClickManager mInstance =null;
public static ClickManager getInstance(){
if (mInstance == null) {
synchronized(ClickManager.class) {
if (mInstance == null) {
mInstance = new ClickManager();
}
}
}
return mInstance;
}
public boolean isClickable1s(Integer key){
Long keyLong = laskClickTimeMap.get(key);
if(keyLong==null){
laskClickTimeMap.put(key,SystemClock.elapsedRealtime());
return true;
}else{
if (SystemClock.elapsedRealtime() - keyLong.longValue() < 1000){
return false;
}else{
laskClickTimeMap.put(key,new Long(SystemClock.elapsedRealtime()));
return true;
}
}
}
}
步骤2。添加一行,避免多次单击。
@Override
public void onClick(View v) {
// TODO Auto-generated method stub
int id = v.getId();
if (id == R.id.iv_back) {
if(!ClickManager.getInstance().isClickable1s(R.id.iv_back))return;
//do something
} else if (id == R.id.iv_light) {
if(!ClickManager.getInstance().isClickable1s(R.id.iv_light))return;
//do something
} else if (id == R.id.iv_camerarotate) {
if(!ClickManager.getInstance().isClickable1s(R.id.iv_camerarotate))return;
//do something
} else if (id == R.id.btn_delete_last_clip) {
if(!ClickManager.getInstance().isClickable1s(R.id.btn_delete_last_clip))return;
//do something
} else if (id == R.id.iv_ok) {
if(!ClickManager.getInstance().isClickable1s(R.id.iv_ok))return;
//do something
}
}
这是我的解决方案:
if (waitDouble) {
waitDouble = false;
Thread thread = new Thread() {
@Override
public void run() {
try {
sleep(300);
if (waitDouble == false) {
waitDouble = true;
singleClick(); //singleClick
}
} catch (InterruptedException e) {
e.printStackTrace();
}
}
};
thread.start();
} else {//DoubleClick
DoubleClick();
waitDouble = true;
}
或者另一种解决方案:
public class NoDoubleClickUtils {
private static long lastClickTime;
private final static int SPACE_TIME = 500;
public static void initLastClickTime() {
lastClickTime = 0;
}
public synchronized static boolean isDoubleClick() {
long currentTime = System.currentTimeMillis();
boolean isClick2;
if (currentTime - lastClickTime > SPACE_TIME) {
isClick2 = false;
} else {
isClick2 = true;
}
lastClickTime = currentTime;
return isClick2;
}
}
具有Kotlin扩展功能:
fun View.onSingleClick(action: (v: View) -> Unit) {
setOnClickListener(object : View.OnClickListener {
override fun onClick(v: View) {
isClickable = false
action(v)
postDelayed({ isClickable = true }, 700)
}
})
}
用法:
button.onSingleClick { myAction() }
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