我们可以像这样使用按钮进行同步:

示例#1 (Java)

@Override
public void onClick(final View view) {
    synchronized (view) {

        view.setEnabled(false);

        switch (view.getId()) {
            case R.id.id1:
                ...
                break;
            case R.id.id2:
                ...
                break;
                ...
        }

        new Handler().postDelayed(new Runnable() {

            @Override
            public void run() {
                view.setEnabled(true);
            }
        }, 1000);
    }
}

示例#2 (kotlin)使用synchronized

myButton.setOnClickListener { view ->
            synchronized(view) {
                view.isEnabled = false

                // do something

                view.postDelayed({ view.isEnabled = true }, 500L)
            }
        }

祝你好运)

    button.setOnClickListener(new OnClickListener() {
        @Override
        public void onClick(View view) {
            //to prevent double click
            button.setOnClickListener(null);
        }
    });

您也可以使用jake Wharton的rx绑定来实现这一点。下面是一个连续点击之间间隔2秒的例子:

RxView.clicks(btnSave)
                .throttleFirst(2000, TimeUnit.MILLISECONDS, AndroidSchedulers.mainThread())
                .subscribe(new Consumer<Object>() {
                    @Override
                    public void accept( Object v) throws Exception {
//handle onclick event here
                });

//注意:忽略对象v在这种情况下，我认为总是。

我的解决方案是

package com.shuai.view;

import android.os.SystemClock;
import android.view.View;

/**
 * 处理快速在某个控件上双击2次(或多次)会导致onClick被触发2次(或多次)的问题
 * 通过判断2次click事件的时间间隔进行过滤
 * 
 * 子类通过实现{@link #onSingleClick}响应click事件
 */
public abstract class OnSingleClickListener implements View.OnClickListener {
    /**
     * 最短click事件的时间间隔
     */
    private static final long MIN_CLICK_INTERVAL=600;
    /**
     * 上次click的时间
     */
    private long mLastClickTime;

    /**
     * click响应函数
     * @param v The view that was clicked.
     */
    public abstract void onSingleClick(View v);

    @Override
    public final void onClick(View v) {
        long currentClickTime=SystemClock.uptimeMillis();
        long elapsedTime=currentClickTime-mLastClickTime;
        //有可能2次连击，也有可能3连击，保证mLastClickTime记录的总是上次click的时间
        mLastClickTime=currentClickTime;

        if(elapsedTime<=MIN_CLICK_INTERVAL)
            return;

        onSingleClick(v);        
    }

}

用法类似于OnClickListener，但重写onSingleClick()代替:

mTextView.setOnClickListener(new OnSingleClickListener() {
            @Override
            public void onSingleClick(View v) {
                if (DEBUG)
                    Log.i("TAG", "onclick！");
            }
     };

防止点击乘法btns

使用:

private val disposables = CompositeDisposable()
private val clickInteractor = ClickInteractor(disposables)
...
button1.setOnClickListener{
     clickInteractor.click {
          Toast.makeText(context, "Btn1", Toast.LENGTH_LONG).show()
     }
}
button2.setOnClickListener{
     clickInteractor.click {
          Toast.makeText(context, "Btn2", Toast.LENGTH_LONG).show()
     }
}

ClickInteractor.kt:

class ClickInteractor constructor(disposables: CompositeDisposable) {
    private val performPublish = PublishSubject.create<ClickInteractorCallback>()

    init {
        performPublish
            .subscribeOn(Schedulers.io())
            .observeOn(Schedulers.io())
            .throttleFirst(1, TimeUnit.SECONDS, Schedulers.io())
            .observeOn(AndroidSchedulers.mainThread())
            .doOnNext { callback ->
                callback.invoke()
            }
            .retry()
            .execute(disposables)
    }

    fun click(callback: ClickInteractorCallback) {
        performPublish.onNext(callback)
    }
}

typealias ClickInteractorCallback = () -> Unit

这是我的解决方案:

if (waitDouble) {
    waitDouble = false;
    Thread thread = new Thread() {
        @Override
        public void run() {
            try {
                sleep(300);
                if (waitDouble == false) {
                    waitDouble = true;
                    singleClick();  //singleClick
                }
            } catch (InterruptedException e) {
                e.printStackTrace();
            }
        }
    };
    thread.start();
} else {//DoubleClick
    DoubleClick();
    waitDouble = true;
}

或者另一种解决方案:

public class NoDoubleClickUtils {
    private static long lastClickTime;
    private final static int SPACE_TIME = 500;

    public static void initLastClickTime() {
        lastClickTime = 0;
    }

    public synchronized static boolean isDoubleClick() {
        long currentTime = System.currentTimeMillis();
        boolean isClick2;
        if (currentTime - lastClickTime > SPACE_TIME) {
            isClick2 = false;
        } else {
            isClick2 = true;
        }
        lastClickTime = currentTime;
        return isClick2;
    }
}