在安卓系统中防止双击按钮的最佳方法是什么?
当前回答
我们可以像这样使用按钮进行同步:
示例#1 (Java)
@Override
public void onClick(final View view) {
synchronized (view) {
view.setEnabled(false);
switch (view.getId()) {
case R.id.id1:
...
break;
case R.id.id2:
...
break;
...
}
new Handler().postDelayed(new Runnable() {
@Override
public void run() {
view.setEnabled(true);
}
}, 1000);
}
}
示例#2 (kotlin)使用synchronized
myButton.setOnClickListener { view ->
synchronized(view) {
view.isEnabled = false
// do something
view.postDelayed({ view.isEnabled = true }, 500L)
}
}
祝你好运)
其他回答
这是我的解决方案:
if (waitDouble) {
waitDouble = false;
Thread thread = new Thread() {
@Override
public void run() {
try {
sleep(300);
if (waitDouble == false) {
waitDouble = true;
singleClick(); //singleClick
}
} catch (InterruptedException e) {
e.printStackTrace();
}
}
};
thread.start();
} else {//DoubleClick
DoubleClick();
waitDouble = true;
}
或者另一种解决方案:
public class NoDoubleClickUtils {
private static long lastClickTime;
private final static int SPACE_TIME = 500;
public static void initLastClickTime() {
lastClickTime = 0;
}
public synchronized static boolean isDoubleClick() {
long currentTime = System.currentTimeMillis();
boolean isClick2;
if (currentTime - lastClickTime > SPACE_TIME) {
isClick2 = false;
} else {
isClick2 = true;
}
lastClickTime = currentTime;
return isClick2;
}
}
我希望这能帮助你,把代码放在你的事件处理程序。
// --------------------------------------------------------------------------------
boolean hasTag = null != which.getTag( R.id.preventing_double_click_tag );
if ( hasTag ) {
// Do not handle again...
return;
} else {
which.setTag( R.id.action, Boolean.TRUE );
which.postDelayed( new Runnable() {
@Override
public void run() {
which.setTag( R.id.action, null );
Log.d( "onActin", " The preventing double click tag was removed." );
}
}, 2000 );
}
对于任何使用数据绑定的用户:
@BindingAdapter("onClickWithDebounce")
fun onClickWithDebounce(view: View, listener: android.view.View.OnClickListener) {
view.setClickWithDebounce {
listener.onClick(view)
}
}
object LastClickTimeSingleton {
var lastClickTime: Long = 0
}
fun View.setClickWithDebounce(action: () -> Unit) {
setOnClickListener(object : View.OnClickListener {
override fun onClick(v: View) {
if (SystemClock.elapsedRealtime() - LastClickTimeSingleton.lastClickTime < 500L) return
else action()
LastClickTimeSingleton.lastClickTime = SystemClock.elapsedRealtime()
}
})
}
<androidx.appcompat.widget.AppCompatButton
..
android:text="@string/signup_signin"
app:onClickWithDebounce="@{() -> viewModel.onSignUpClicked()}"
... />
Kotlin扩展,允许简洁的内联代码和变量双击等待时间
fun View.setDoubleClickListener(listener: View.OnClickListener, waitMillis : Long = 1000) {
var lastClickTime = 0L
setOnClickListener { view ->
if (System.currentTimeMillis() > lastClickTime + waitMillis) {
listener.onClick(view)
lastClickTime = System.currentTimeMillis()
}
}
}
用法:
anyView.setNoDoubleClickListener(View.OnClickListener { v ->
// do stuff
})
Or
anyView.setNoDoubleClickListener(View.OnClickListener { v ->
// do stuff
}, 1500)
如果有人还在寻找一个简短的答案,你可以使用下面的代码
private static long mLastClickTime = 0;
if (SystemClock.elapsedRealtime() - mLastClickTime < 1000) { // 1000 = 1second
return;
}
mLastClickTime = SystemClock.elapsedRealtime();
当用户在1秒内单击View时,这段代码将进入if语句,然后返回;将被启动,而进一步的代码将不会被启动。
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