如果有人还在寻找一个简短的答案，你可以使用下面的代码

 private static long mLastClickTime = 0;
  if (SystemClock.elapsedRealtime() - mLastClickTime < 1000) { // 1000 = 1second
         return;
    }
 mLastClickTime = SystemClock.elapsedRealtime();

当用户在1秒内单击View时，这段代码将进入if语句，然后返回;将被启动，而进一步的代码将不会被启动。

你可以使用这种方法。通过使用后延迟，你可以照顾双击事件。

void debounceEffectForClick(查看视图){

    view.setClickable(false);

    view.postDelayed(new Runnable() {
        @Override
        public void run() {
            view.setClickable(true);

        }
    }, 500);
}

如果点击按钮，你正在打开一个新的片段，只需添加android:clickable="true"到正在打开的新片段的根视图。

I found none of these suggestions works if the onClick method doesn't return immediately. The touch event is queued by Android and the next onClick is called only after the first one is finished. (Since this is done on the one UI thread this is really normal.) I needed to use the time when the the onClick function is finished + one boolean variable to mark whether the given onClick is running. Both these marker attributes are static to avoid any onClickListener to run at the same time. (If user clicks on another button) You can simple replace your OnClickListener to this class and instead of implementing the onClick method you need to implement the abstract oneClick() method.

    abstract public class OneClickListener implements OnClickListener {

    private static boolean started = false;
    private static long lastClickEndTime = 0;

    /* (non-Javadoc)
     * @see android.view.View.OnClickListener#onClick(android.view.View)
     */
    @Override
    final public void onClick(final View v) {
        if(started || SystemClock.elapsedRealtime()-lastClickEndTime <1000 ){
            Log.d(OneClickListener.class.toString(), "Rejected double click, " + new Date().toString() );
            return; 
        }
        Log.d(OneClickListener.class.toString(), "One click, start: " + new Date().toString() );
        try{
            started = true;
            oneClick(v);
        }finally{
            started = false;
            lastClickEndTime = SystemClock.elapsedRealtime();
            Log.d(OneClickListener.class.toString(), "One click, end: " + new Date().toString() );
        }
    }

    abstract protected void oneClick(View v);
}

当UI线程阻塞时，单击事件队列。对于按钮单击事件，请尽快将其更改为后台任务，以避免单击事件在彼此后面排队。

在activity类中声明一个volatile boolean或lock:

private volatile boolean saving = false;

创建一个onClickListener按钮，通过保存和启动一个后台任务来完成工作:

saveButton.setOnClickListener(new View.OnClickListener() {

    @Override
    public void onClick(View view) {
        if (!saving) {
            saving = true;
            new SaveAsyncTask().execute();
        }
    }
});

创建一个内部的SaveAsyncTask类来在后台完成工作:

class SaveAsyncTask extends AsyncTask {

    @Override
    protected Object doInBackground(Object[] objects) {
        // Do something here, simulate a 3 second task
        SystemClock.sleep(3000);
        saving = false;
        return null;
    }
}

我用两个类来解决这个问题，一个类似于@jinshiyi11的答案，另一个是基于显式点击，在这里你只能点击一个按钮一次，如果你想要另一次点击，你必须显式地指出它。

/**
 * Listener que sólo permite hacer click una vez, para poder hacer click
 * posteriormente se necesita indicar explicitamente.
 *
 * @author iberck
 */
public abstract class OnExplicitClickListener implements View.OnClickListener {

    // you can perform a click only once time
    private boolean canClick = true;

    @Override
    public synchronized void onClick(View v) {
        if (canClick) {
            canClick = false;
            onOneClick(v);
        }
    }

    public abstract void onOneClick(View v);

    public synchronized void enableClick() {
        canClick = true;
    }

    public synchronized void disableClick() {
        canClick = false;
    }
}

使用示例:

OnExplicitClickListener clickListener = new OnExplicitClickListener() {
    public void onOneClick(View v) {
        Log.d("example", "explicit click");
        ...
        clickListener.enableClick();    
    }
}
button.setOnClickListener(clickListener);