什么是甲状腺?它们用于什么?
当前回答
此分類上一篇: tl;dr version
类型(obj)函数会给你一个对象的类型。
一个阶级的类型( )是它的甲型阶级。
使用甲状腺:
class Foo(object):
__metaclass__ = MyMetaClass
一个类的类是一个类的类 - 一个类的身体是转移到一个类的论点,它被用来构建一个类。
在这里,你可以阅读如何使用金属玻璃来自定义课堂建筑。
其他回答
类,在Python,是一个对象,和任何其他对象一样,它是一个例子“什么”。这个“什么”是所谓的MetaClass。这个MetaClass是一个特殊类型的类,创造了其他类的对象。因此,MetaClass负责创造新的类。
Class Name Tuple 具有由 Class A 继承的基类 词典具有所有类方法和类变量
另一种方式创建一个金属类是“金属类”的关键词,将金属类定义为一个简单的类,在继承类的参数中,通过金属类=金属类_名称。
Metaclass 可以在以下情况下具体使用:
在以对象为导向的编程中,一个代码类是一种类,其例子是类。 正如普通类定义某些对象的行为一样,一个代码类定义某些类的行为和其例子 这个术语的代码类简单地意味着用于创建类的东西。
其他人已经解释了金属玻璃是如何工作的,它们是如何适应Python类型系统的,这里有一个例子,它们可以用于什么。在我写的测试框架中,我想跟踪在哪个类被定义的顺序,以便我后来能够在这个顺序中安装它们,我发现使用金属玻璃最容易做到这一点。
class MyMeta(type):
counter = 0
def __init__(cls, name, bases, dic):
type.__init__(cls, name, bases, dic)
cls._order = MyMeta.counter
MyMeta.counter += 1
class MyType(object): # Python 2
__metaclass__ = MyMeta
class MyType(metaclass=MyMeta): # Python 3
pass
任何是 MyType 的子类,然后获得一个类属性 _ 命令,记录了类被定义的顺序。
# define a class
class SomeClass(object):
# ...
# some definition here ...
# ...
# create an instance of it
instance = SomeClass()
# then call the object as if it's a function
result = instance('foo', 'bar')
class SomeClass(object):
# ...
# some definition here ...
# ...
def __call__(self, foo, bar):
return bar + foo
但是,正如我们从以前的答案中看到的那样,一个类本身就是一个金属类的例子,所以当我们使用这个类作为一个金属类(即当我们创建一个例子时),我们实际上称它为金属类的 __call__() 方法。
class Meta_1(type):
def __call__(cls):
print "Meta_1.__call__() before creating an instance of ", cls
instance = super(Meta_1, cls).__call__()
print "Meta_1.__call__() about to return instance."
return instance
这是一个使用这个MetaClass的班级。
class Class_1(object):
__metaclass__ = Meta_1
def __new__(cls):
print "Class_1.__new__() before creating an instance."
instance = super(Class_1, cls).__new__(cls)
print "Class_1.__new__() about to return instance."
return instance
def __init__(self):
print "entering Class_1.__init__() for instance initialization."
super(Class_1,self).__init__()
print "exiting Class_1.__init__()."
现在,让我们创建一个类_1的例子。
instance = Class_1()
# Meta_1.__call__() before creating an instance of <class '__main__.Class_1'>.
# Class_1.__new__() before creating an instance.
# Class_1.__new__() about to return instance.
# entering Class_1.__init__() for instance initialization.
# exiting Class_1.__init__().
# Meta_1.__call__() about to return instance.
class type:
def __call__(cls, *args, **kwarg):
# ... maybe a few things done to cls here
# then we call __new__() on the class to create an instance
instance = cls.__new__(cls, *args, **kwargs)
# ... maybe a few things done to the instance here
# then we initialize the instance with its __init__() method
instance.__init__(*args, **kwargs)
# ... maybe a few more things done to instance here
# then we return it
return instance
从上述情况下,它表明,MetaClass的 __call__() 还有机会决定是否会最终对 Class_1.__new__() 或 Class_1.__init__() 进行呼叫。在执行过程中,它实际上可以返回没有被这些方法触摸的对象。
class Meta_2(type):
singletons = {}
def __call__(cls, *args, **kwargs):
if cls in Meta_2.singletons:
# we return the only instance and skip a call to __new__()
# and __init__()
print ("{} singleton returning from Meta_2.__call__(), "
"skipping creation of new instance.".format(cls))
return Meta_2.singletons[cls]
# else if the singleton isn't present we proceed as usual
print "Meta_2.__call__() before creating an instance."
instance = super(Meta_2, cls).__call__(*args, **kwargs)
Meta_2.singletons[cls] = instance
print "Meta_2.__call__() returning new instance."
return instance
class Class_2(object):
__metaclass__ = Meta_2
def __new__(cls, *args, **kwargs):
print "Class_2.__new__() before creating instance."
instance = super(Class_2, cls).__new__(cls)
print "Class_2.__new__() returning instance."
return instance
def __init__(self, *args, **kwargs):
print "entering Class_2.__init__() for initialization."
super(Class_2, self).__init__()
print "exiting Class_2.__init__()."
让我们来看看在重复试图创建类型Class_2的对象时会发生什么。
a = Class_2()
# Meta_2.__call__() before creating an instance.
# Class_2.__new__() before creating instance.
# Class_2.__new__() returning instance.
# entering Class_2.__init__() for initialization.
# exiting Class_2.__init__().
# Meta_2.__call__() returning new instance.
b = Class_2()
# <class '__main__.Class_2'> singleton returning from Meta_2.__call__(), skipping creation of new instance.
c = Class_2()
# <class '__main__.Class_2'> singleton returning from Meta_2.__call__(), skipping creation of new instance.
a is b is c # True
Python 类本身是它们的 meta 类的对象 - 例如。
默认的金属类,当您确定类时应用于:
class foo:
...
例如,假设您正在构建一个ORM访问数据库,并且您希望每个表中的记录来自一个类地图到该表(基于字段,业务规则等),一个可能的使用MetaClass是例如,连接池逻辑,由所有表中的记录的所有类共享。
当你定义甲型时,你可以分类类型,并且可以超越下列魔法方法来插入你的逻辑。
class somemeta(type):
__new__(mcs, name, bases, clsdict):
"""
mcs: is the base metaclass, in this case type.
name: name of the new class, as provided by the user.
bases: tuple of base classes
clsdict: a dictionary containing all methods and attributes defined on class
you must return a class object by invoking the __new__ constructor on the base metaclass.
ie:
return type.__call__(mcs, name, bases, clsdict).
in the following case:
class foo(baseclass):
__metaclass__ = somemeta
an_attr = 12
def bar(self):
...
@classmethod
def foo(cls):
...
arguments would be : ( somemeta, "foo", (baseclass, baseofbase,..., object), {"an_attr":12, "bar": <function>, "foo": <bound class method>}
you can modify any of these values before passing on to type
"""
return type.__call__(mcs, name, bases, clsdict)
def __init__(self, name, bases, clsdict):
"""
called after type has been created. unlike in standard classes, __init__ method cannot modify the instance (cls) - and should be used for class validaton.
"""
pass
def __prepare__():
"""
returns a dict or something that can be used as a namespace.
the type will then attach methods and attributes from class definition to it.
call order :
somemeta.__new__ -> type.__new__ -> type.__init__ -> somemeta.__init__
"""
return dict()
def mymethod(cls):
""" works like a classmethod, but for class objects. Also, my method will not be visible to instances of cls.
"""
pass
无论如何,这两种是最常用的<unk>子,甲板是强大的,上面没有附近和完整的用途列表用于甲板。
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