如何使用PHP5类创建单例类?


当前回答

简单的例子:

final class Singleton
{
    private static $instance = null;

    private function __construct(){}

    private function __clone(){}

    private function __wakeup(){}

    public static function get_instance()
    {
        if ( static::$instance === null ) {
            static::$instance = new static();
        }
        return static::$instance;
    }
}

希望有帮助。

其他回答

这篇文章涵盖了相当广泛的主题: http://www.phptherightway.com/pages/Design-Patterns.html#singleton

Note the following: The constructor __construct() is declared as protected to prevent creating a new instance outside of the class via the new operator. The magic method __clone() is declared as private to prevent cloning of an instance of the class via the clone operator. The magic method __wakeup() is declared as private to prevent unserializing of an instance of the class via the global function unserialize(). A new instance is created via late static binding in the static creation method getInstance() with the keyword static. This allows the subclassing of the class Singleton in the example.

数据库类,检查是否有任何现有的数据库实例,它将返回先前的实例。

   class Database {  
        public static $instance;  
         public static function getInstance(){  
            if(!isset(Database::$instance) ) {  
                Database::$instance = new Database();  
            }  
           return Database::$instance;  
         }  
         private function __cunstruct() {  
           /* private and cant create multiple objects */  
         }  
         public function getQuery(){  
            return "Test Query Data";  
         }  
    }  
    $dbObj = Database::getInstance();  
    $dbObj2 = Database::getInstance();  
    var_dump($dbObj);  
    var_dump($dbObj2);  


/* 
After execution you will get following output: 

object(Database)[1] 
object(Database)[1] 

*/  

Ref http://www.phptechi.com/php-singleton-design-patterns-example.html

/**
 * Singleton class
 *
 */
final class UserFactory
{
    private static $inst = null;

    // Prevent cloning and de-serializing
    private function __clone(){}
    private function __wakeup(){}


    /**
     * Call this method to get singleton
     *
     * @return UserFactory
     */
    public static function Instance()
    {
        if ($inst === null) {
            $inst = new UserFactory();
        }
        return $inst;
    }
    
    /**
     * Private ctor so nobody else can instantiate it
     *
     */
    private function __construct()
    {
        
    }
}

使用方法:

$fact = UserFactory::Instance();
$fact2 = UserFactory::Instance();

$fact == $fact2;

But:

$fact = new UserFactory()

抛出错误。

参见http://php.net/manual/en/language.variables.scope.php#language.variables.scope.static了解静态变量的作用域以及为什么设置static $inst = null;的工作原理。

你可能应该添加一个私有的__clone()方法来禁止克隆实例。

private function __clone() {}

如果您不包含此方法,则可能出现以下情况

$inst1=UserFactory::Instance(); // to stick with the example provided above
$inst2=clone $inst1;

现在$inst1 !== $inst2 -它们不再是同一个实例了。

我同意第一个答案,但我也会将类声明为final,这样它就不能被扩展,因为扩展单例违背了单例模式。此外,实例变量应该是私有的,这样就不能直接访问它。还要将__clone方法设为私有,这样就不能克隆单例对象。

下面是一些示例代码。

/**
 * Singleton class
 *
 */
final class UserFactory
{
    private static $_instance = null;

    /**
     * Private constructor
     *
     */
    private function __construct() {}

    /**
     * Private clone method
     *
     */
     private function __clone() {}

    /**
     * Call this method to get singleton
     *
     * @return UserFactory
     */
    public static function getInstance()
    {
        if (self::$_instance === null) {
            self::$_instance = new UserFactory();
        }
        return self::$_instance;
    }
}

示例使用

$user_factory = UserFactory::getInstance();

这阻止你做什么(这将违反单例模式..

你不能这么做!

$user_factory = UserFactory::$_instance;

class SecondUserFactory extends UserFactory { }