我试图用多个其他单词替换字符串中的多个单词。字符串是“我有一只猫,一只狗和一只山羊。”

然而,这并不会产生“我有一只狗、一只山羊和一只猫”,而是产生“我有一只猫、一只猫和一只猫”。是否有可能在JavaScript中同时用多个其他字符串替换多个字符串,以便产生正确的结果?

var str = "I have a cat, a dog, and a goat.";
str = str.replace(/cat/gi, "dog");
str = str.replace(/dog/gi, "goat");
str = str.replace(/goat/gi, "cat");

//this produces "I have a cat, a cat, and a cat"
//but I wanted to produce the string "I have a dog, a goat, and a cat".

当前回答

    var str = "I have a cat, a dog, and a goat.";

    str = str.replace(/goat/i, "cat");
    // now str = "I have a cat, a dog, and a cat."

    str = str.replace(/dog/i, "goat");
    // now str = "I have a cat, a goat, and a cat."

    str = str.replace(/cat/i, "dog");
    // now str = "I have a dog, a goat, and a cat."

其他回答

通过使用原型函数,我们可以通过传递对象的键和值以及可替换的文本轻松地进行替换

String.prototype.replaceAll =函数(obj keydata =“关键”){ const键= keydata.split(关键); 返回Object.entries (obj) .reduce((,(关键,val)) = > a.replace(“${键[0]}${关键}${键[1]}',val),) } Const data=' hidden dv SDC sd ${yathin} ${ok}' console.log (data.replaceAll ({yathin: 12,好的:“嗨”},“${关键}”))

你可以试试这个。买不聪明。

var str = "我有一只猫,一只狗,和一只山羊。"; console.log (str); str = str.replace(/cat/gi, "XXX"); console.log (str); STR = STR .replace(/goat/gi, "cat"); console.log (str); STR = STR .replace(/dog/gi, "goat"); console.log (str); str = str.replace(/XXX/gi, "dog"); console.log (str); 把: 我有一只狗,一只山羊和一只猫。

这个解决方案可以只替换整个单词——例如,当搜索“猫”时,“catch”、“ducat”或“locator”将找不到。这可以通过对正则表达式中每个单词前后的单词字符使用负向后查找(?<!\w)和负向前查找(?!\w)来实现:

(?<!\w)(cathy|cat|ducat|locator|catch)(?!\w)

JSFiddle demo: http://jsfiddle.net/mfkv9r8g/1/

使用我的replace-once包,您可以执行以下操作:

const replaceOnce = require('replace-once')

var str = 'I have a cat, a dog, and a goat.'
var find = ['cat', 'dog', 'goat']
var replace = ['dog', 'goat', 'cat']
replaceOnce(str, find, replace, 'gi')
//=> 'I have a dog, a goat, and a cat.'
String.prototype.replaceSome = function() {
    var replaceWith = Array.prototype.pop.apply(arguments),
        i = 0,
        r = this,
        l = arguments.length;
    for (;i<l;i++) {
        r = r.replace(arguments[i],replaceWith);
    }
    return r;
}

/* 字符串的replaceSome方法 它需要尽可能多的参数,然后替换所有参数 我们指定的最后一个参数 2013年版权保存:Max Ahmed 这是一个例子:

var string = "[hello i want to 'replace x' with eat]";
var replaced = string.replaceSome("]","[","'replace x' with","");
document.write(string + "<br>" + replaced); // returns hello i want to eat (without brackets)

*/

jsFiddle: http://jsfiddle.net/CPj89/