我试图用多个其他单词替换字符串中的多个单词。字符串是“我有一只猫,一只狗和一只山羊。”

然而,这并不会产生“我有一只狗、一只山羊和一只猫”,而是产生“我有一只猫、一只猫和一只猫”。是否有可能在JavaScript中同时用多个其他字符串替换多个字符串,以便产生正确的结果?

var str = "I have a cat, a dog, and a goat.";
str = str.replace(/cat/gi, "dog");
str = str.replace(/dog/gi, "goat");
str = str.replace(/goat/gi, "cat");

//this produces "I have a cat, a cat, and a cat"
//but I wanted to produce the string "I have a dog, a goat, and a cat".

当前回答

在这个实例中,这可能不能满足您的确切需求,但我发现这是一种有用的方法,可以替换字符串中的多个参数,作为通用解决方案。它将替换参数的所有实例,无论它们被引用了多少次:

String.prototype.fmt = function (hash) {
        var string = this, key; for (key in hash) string = string.replace(new RegExp('\\{' + key + '\\}', 'gm'), hash[key]); return string
}

你可以这样调用它:

var person = '{title} {first} {last}'.fmt({ title: 'Agent', first: 'Jack', last: 'Bauer' });
// person = 'Agent Jack Bauer'

其他回答

我扩展了一下@本麦考密克斯。他的工作规则字符串,但不如果我转义字符或通配符。我是这么做的

str = "[curl] 6: blah blah 234433 blah blah";
mapObj = {'\\[curl] *': '', '\\d: *': ''};


function replaceAll (str, mapObj) {

    var arr = Object.keys(mapObj),
        re;

    $.each(arr, function (key, value) {
        re = new RegExp(value, "g");
        str = str.replace(re, function (matched) {
            return mapObj[value];
        });
    });

    return str;

}
replaceAll(str, mapObj)

返回"blah blah 234433 blah blah"

这样它将匹配mapObj中的键,而不是匹配的单词'

<!DOCTYPE html>
<html>
<body>



<p id="demo">Mr Blue 
has a           blue house and a blue car.</p>

<button onclick="myFunction()">Try it</button>

<script>
function myFunction() {
    var str = document.getElementById("demo").innerHTML;
    var res = str.replace(/\n| |car/gi, function myFunction(x){

if(x=='\n'){return x='<br>';}
if(x==' '){return x='&nbsp';}
if(x=='car'){return x='BMW'}
else{return x;}//must need



});

    document.getElementById("demo").innerHTML = res;
}
</script>

</body>
</html>

这招对我很管用:

String.prototype.replaceAll = function(search, replacement) {
    var target = this;
    return target.replace(new RegExp(search, 'g'), replacement);
};

function replaceAll(str, map){
    for(key in map){
        str = str.replaceAll(key, map[key]);
    }
    return str;
}

//testing...
var str = "bat, ball, cat";
var map = {
    'bat' : 'foo',
    'ball' : 'boo',
    'cat' : 'bar'
};
var new = replaceAll(str, map);
//result: "foo, boo, bar"

试试我的解决方案。请随意改进

函数multiReplace(字符串,regex,替换){ 返回str.replace(regex, function(x) { //检查替换键以防止错误,如果为false则返回原始值 return Object.keys(replace).includes(x) ?替换[x]: x; }); } var str = "我有一只猫,一只狗,和一只山羊。"; //(json)使用value替换键 Var替换= { “猫”:“狗”, “狗”:“山羊”, “山羊”:“猫”, } console.log(multiReplace(str, /Cat|dog|goat/g, replace))

const str = '感谢为Stack Overflow贡献一个答案!' Const substr = ['for', 'to'] 函数boldString(str, substr) { 让boldStr boldStr = str 字符串的子串。映射(e => { const strRegExp = new RegExp(e, 'g'); boldStr = boldStr。替换(strRegExp ' <强> $ {e} < / >强'); } ) 返回boldStr }