我试图使用python模拟包来模拟python请求模块。让我在下面的场景中工作的基本调用是什么?
在views.py中，我有一个函数，它每次都以不同的响应进行各种request .get()调用
def myview(request):
res1 = requests.get('aurl')
res2 = request.get('burl')
res3 = request.get('curl')
在我的测试类中，我想做类似的事情，但不能确定确切的方法调用
步骤1:
# Mock the requests module
# when mockedRequests.get('aurl') is called then return 'a response'
# when mockedRequests.get('burl') is called then return 'b response'
# when mockedRequests.get('curl') is called then return 'c response'
步骤2:
调用我的视图
步骤3:
验证响应包含'a response'， 'b response'， 'c response'
我如何完成第1步(模拟请求模块)?
我使用requests-mock为单独的模块编写测试:
# module.py
import requests
class A():
def get_response(self, url):
response = requests.get(url)
return response.text
测试:
# tests.py
import requests_mock
import unittest
from module import A
class TestAPI(unittest.TestCase):
@requests_mock.mock()
def test_get_response(self, m):
a = A()
m.get('http://aurl.com', text='a response')
self.assertEqual(a.get_response('http://aurl.com'), 'a response')
m.get('http://burl.com', text='b response')
self.assertEqual(a.get_response('http://burl.com'), 'b response')
m.get('http://curl.com', text='c response')
self.assertEqual(a.get_response('http://curl.com'), 'c response')
if __name__ == '__main__':
unittest.main()
下面是一个带有请求响应类的解决方案。恕我直言，它更干净。
import json
from unittest.mock import patch
from requests.models import Response
def mocked_requests_get(*args, **kwargs):
response_content = None
request_url = kwargs.get('url', None)
if request_url == 'aurl':
response_content = json.dumps('a response')
elif request_url == 'burl':
response_content = json.dumps('b response')
elif request_url == 'curl':
response_content = json.dumps('c response')
response = Response()
response.status_code = 200
response._content = str.encode(response_content)
return response
@mock.patch('requests.get', side_effect=mocked_requests_get)
def test_fetch(self, mock_get):
response = requests.get(url='aurl')
assert ...
我将演示如何通过将真正的请求与返回相同数据的假请求交换来将编程逻辑与实际的外部库分离。在你看来，如果外部api调用，那么这个过程是最好的
import pytest
from unittest.mock import patch
from django.test import RequestFactory
@patch("path(projectname.appname.filename).requests.post")
def test_mock_response(self, mock_get, rf: RequestFactory):
mock_get.return_value.ok = Mock(ok=True)
mock_get.return_value.status_code = 400
mock_get.return_value.json.return_value = {you can define here dummy response}
request = rf.post("test/", data=self.payload)
response = view_name_view(request)
expected_response = {
"success": False,
"status": "unsuccessful",
}
assert response.data == expected_response
assert response.status_code == 400
我将添加这些信息，因为我很难弄清楚如何模拟异步api调用。
以下是我模拟异步调用所做的工作。
这是我想测试的函数
async def get_user_info(headers, payload):
return await httpx.AsyncClient().post(URI, json=payload, headers=headers)
您仍然需要MockResponse类
class MockResponse:
def __init__(self, json_data, status_code):
self.json_data = json_data
self.status_code = status_code
def json(self):
return self.json_data
添加MockResponseAsync类
class MockResponseAsync:
def __init__(self, json_data, status_code):
self.response = MockResponse(json_data, status_code)
async def getResponse(self):
return self.response
下面是测试。这里重要的是，我之前创建了响应，因为init函数不能是异步的，对getResponse的调用是异步的，所以它都签出了。
@pytest.mark.asyncio
@patch('httpx.AsyncClient')
async def test_get_user_info_valid(self, mock_post):
"""test_get_user_info_valid"""
# Given
token_bd = "abc"
username = "bob"
payload = {
'USERNAME': username,
'DBNAME': 'TEST'
}
headers = {
'Authorization': 'Bearer ' + token_bd,
'Content-Type': 'application/json'
}
async_response = MockResponseAsync("", 200)
mock_post.return_value.post.return_value = async_response.getResponse()
# When
await api_bd.get_user_info(headers, payload)
# Then
mock_post.return_value.post.assert_called_once_with(
URI, json=payload, headers=headers)
如果你有更好的方法告诉我，不过我觉得这样很干净。
