我创建了一些自定义元素,并希望以编程方式将它们放置在右上角(距离上边缘n个像素,距离右边缘m个像素)。因此,我需要获得屏幕宽度和屏幕高度,然后设置位置:
int px = screenWidth - m;
int py = screenHeight - n;
如何在主活动中获取screenWidth和screenHeight?
我创建了一些自定义元素,并希望以编程方式将它们放置在右上角(距离上边缘n个像素,距离右边缘m个像素)。因此,我需要获得屏幕宽度和屏幕高度,然后设置位置:
int px = screenWidth - m;
int py = screenHeight - n;
如何在主活动中获取screenWidth和screenHeight?
当前回答
一种方法是:
Display display = getWindowManager().getDefaultDisplay();
int width = display.getWidth();
int height = display.getHeight();
它已被弃用,您应该尝试以下代码。前两行代码提供DisplayMetrics对象。此对象包含高度像素、宽度像素等字段。
DisplayMetrics metrics = new DisplayMetrics();
getWindowManager().getDefaultDisplay().getMetrics(metrics);
int height = metrics.heightPixels;
int width = metrics.widthPixels;
Api级别30更新
final WindowMetrics metrics = windowManager.getCurrentWindowMetrics();
// Gets all excluding insets
final WindowInsets windowInsets = metrics.getWindowInsets();
Insets insets = windowInsets.getInsetsIgnoringVisibility(WindowInsets.Type.navigationBars()
| WindowInsets.Type.displayCutout());
int insetsWidth = insets.right + insets.left;
int insetsHeight = insets.top + insets.bottom;
// Legacy size that Display#getSize reports
final Rect bounds = metrics.getBounds();
final Size legacySize = new Size(bounds.width() - insetsWidth,
bounds.height() - insetsHeight);
其他回答
首先获取视图(例如,通过findViewById()),然后可以对视图本身使用getWidth()。
现在在Api 30级别上,应该这样做
final WindowMetrics metrics = windowManager.getCurrentWindowMetrics();
// Gets all excluding insets
final WindowInsets windowInsets = metrics.getWindowInsets();
Insets insets = windowInsets.getInsetsIgnoreVisibility(WindowInsets.Type.navigationBars()
| WindowInsets.Type.displayCutout());
int insetsWidth = insets.right + insets.left;
int insetsHeight = insets.top + insets.bottom;
// Legacy size that Display#getSize reports
final Rect bounds = metrics.getBounds();
final Size legacySize = new Size(bounds.width() - insetsWidth,
bounds.height() - insetsHeight);
如果Display类不工作,则上面的答案将不起作用,那么您可以通过下面的方法获得宽度和高度。
private static final int WIDTH_INDEX = 0;
private static final int HEIGHT_INDEX = 1;
public static int[] getScreenSize(Context context) {
int[] widthHeight = new int[2];
widthHeight[WIDTH_INDEX] = 0;
widthHeight[HEIGHT_INDEX] = 0;
try {
WindowManager windowManager = (WindowManager) context.getSystemService(Context.WINDOW_SERVICE);
Display display = windowManager.getDefaultDisplay();
Point size = new Point();
display.getSize(size);
widthHeight[WIDTH_INDEX] = size.x;
widthHeight[HEIGHT_INDEX] = size.y;
if (!isScreenSizeRetrieved(widthHeight))
{
DisplayMetrics metrics = new DisplayMetrics();
display.getMetrics(metrics);
widthHeight[0] = metrics.widthPixels;
widthHeight[1] = metrics.heightPixels;
}
// Last defense. Use deprecated API that was introduced in lower than API 13
if (!isScreenSizeRetrieved(widthHeight)) {
widthHeight[0] = display.getWidth(); // deprecated
widthHeight[1] = display.getHeight(); // deprecated
}
} catch (Exception e) {
e.printStackTrace();
}
return widthHeight;
}
private static boolean isScreenSizeRetrieved(int[] widthHeight) {
return widthHeight[WIDTH_INDEX] != 0 && widthHeight[HEIGHT_INDEX] != 0;
}
这不是OP的答案,因为他希望以真实像素显示尺寸。我想要“设备无关像素”的尺寸,并从这里汇总答案https://stackoverflow.com/a/17880012/253938在这里https://stackoverflow.com/a/6656774/253938我想到了这个:
DisplayMetrics displayMetrics = Resources.getSystem().getDisplayMetrics();
int dpHeight = (int)(displayMetrics.heightPixels / displayMetrics.density + 0.5);
int dpWidth = (int)(displayMetrics.widthPixels / displayMetrics.density + 0.5);
科特林
fun getScreenHeight(activity: Activity): Int {
val metrics = DisplayMetrics()
activity.windowManager.defaultDisplay.getMetrics(metrics)
return metrics.heightPixels
}
fun getScreenWidth(activity: Activity): Int {
val metrics = DisplayMetrics()
activity.windowManager.defaultDisplay.getMetrics(metrics)
return metrics.widthPixels
}