我如何才能最好地编写一个查询,从总共600k中随机选择10行?
当前回答
我需要一个查询从一个相当大的表中返回大量随机行。这是我想到的。首先获取最大记录id:
SELECT MAX(id) FROM table_name;
然后将该值代入:
SELECT * FROM table_name WHERE id > FLOOR(RAND() * max) LIMIT n;
Where max is the maximum record id in the table and n is the number of rows you want in your result set. The assumption is that there are no gaps in the record id's although I doubt it would affect the result if there were (haven't tried it though). I also created this stored procedure to be more generic; pass in the table name and number of rows to be returned. I'm running MySQL 5.5.38 on Windows 2008, 32GB, dual 3GHz E5450, and on a table with 17,361,264 rows it's fairly consistent at ~.03 sec / ~11 sec to return 1,000,000 rows. (times are from MySQL Workbench 6.1; you could also use CEIL instead of FLOOR in the 2nd select statement depending on your preference)
DELIMITER $$
USE [schema name] $$
DROP PROCEDURE IF EXISTS `random_rows` $$
CREATE PROCEDURE `random_rows`(IN tab_name VARCHAR(64), IN num_rows INT)
BEGIN
SET @t = CONCAT('SET @max=(SELECT MAX(id) FROM ',tab_name,')');
PREPARE stmt FROM @t;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
SET @t = CONCAT(
'SELECT * FROM ',
tab_name,
' WHERE id>FLOOR(RAND()*@max) LIMIT ',
num_rows);
PREPARE stmt FROM @t;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
END
$$
then
CALL [schema name].random_rows([table name], n);
其他回答
另一个简单的解决方案是对行进行排名,并随机获取其中之一,有了这个解决方案,你将不需要在表中有任何基于“Id”的列。
SELECT d.* FROM (
SELECT t.*, @rownum := @rownum + 1 AS rank
FROM mytable AS t,
(SELECT @rownum := 0) AS r,
(SELECT @cnt := (SELECT RAND() * (SELECT COUNT(*) FROM mytable))) AS n
) d WHERE rank >= @cnt LIMIT 10;
您可以根据需要更改限制值,以便访问尽可能多的行,但大多数情况下是连续的值。
然而,如果你不想要连续的随机值,那么你可以获取一个更大的样本并从中随机选择。就像……
SELECT * FROM (
SELECT d.* FROM (
SELECT c.*, @rownum := @rownum + 1 AS rank
FROM buildbrain.`commits` AS c,
(SELECT @rownum := 0) AS r,
(SELECT @cnt := (SELECT RAND() * (SELECT COUNT(*) FROM buildbrain.`commits`))) AS rnd
) d
WHERE rank >= @cnt LIMIT 10000
) t ORDER BY RAND() LIMIT 10;
SELECT
*
FROM
table_with_600k_rows
WHERE
RAND( )
ORDER BY
id DESC
LIMIT 30;
Id是主键,按Id排序, 解释table_with_600k_rows,发现该行不扫描整个表
这非常快,而且是100%随机的,即使你有间隙。
将SELECT Count(*)中可用的行数计算为rows FROM TABLE 选择10个不同的随机数a_1,a_2,…,a_10在0到x之间 SELECT * FROM TABLE LIMIT 1 offset a_i for i=1,…,10
我在Bill Karwin的《SQL反模式》一书中发现了这个破解方法。
我使用了Riedsio发布的http://jan.kneschke.de/projects/mysql/order-by-rand/(我使用了返回一个或多个随机值的存储过程的情况):
DROP TEMPORARY TABLE IF EXISTS rands;
CREATE TEMPORARY TABLE rands ( rand_id INT );
loop_me: LOOP
IF cnt < 1 THEN
LEAVE loop_me;
END IF;
INSERT INTO rands
SELECT r1.id
FROM random AS r1 JOIN
(SELECT (RAND() *
(SELECT MAX(id)
FROM random)) AS id)
AS r2
WHERE r1.id >= r2.id
ORDER BY r1.id ASC
LIMIT 1;
SET cnt = cnt - 1;
END LOOP loop_me;
在这篇文章中,他通过维护一个表(使用触发器等)解决了id中的间隙导致不那么随机的结果的问题。参见文章); 我通过向表中添加另一列来解决这个问题,用连续的数字填充,从1开始(编辑:此列添加到运行时由子查询创建的临时表中,不影响永久表):
DROP TEMPORARY TABLE IF EXISTS rands;
CREATE TEMPORARY TABLE rands ( rand_id INT );
loop_me: LOOP
IF cnt < 1 THEN
LEAVE loop_me;
END IF;
SET @no_gaps_id := 0;
INSERT INTO rands
SELECT r1.id
FROM (SELECT id, @no_gaps_id := @no_gaps_id + 1 AS no_gaps_id FROM random) AS r1 JOIN
(SELECT (RAND() *
(SELECT COUNT(*)
FROM random)) AS id)
AS r2
WHERE r1.no_gaps_id >= r2.id
ORDER BY r1.no_gaps_id ASC
LIMIT 1;
SET cnt = cnt - 1;
END LOOP loop_me;
在文章中,我可以看到他花了很大的精力来优化代码;我不知道我的改变是否/有多大影响性能,但对我来说非常好。
这里有一个改变游戏规则的方法,可能对许多人有帮助;
我有一个有200k行的表,有连续的id,我需要选择N个随机行,所以我选择根据表中最大的id生成随机值,我创建了这个脚本来找出哪个是最快的操作:
logTime();
query("SELECT COUNT(id) FROM tbl");
logTime();
query("SELECT MAX(id) FROM tbl");
logTime();
query("SELECT id FROM tbl ORDER BY id DESC LIMIT 1");
logTime();
结果如下:
计数:36.8418693542479毫秒 Max: 0.241041183472 ms 订单:0.216960906982毫秒
根据这个结果,order desc是得到最大id的最快操作, 以下是我对这个问题的回答:
SELECT GROUP_CONCAT(n SEPARATOR ',') g FROM (
SELECT FLOOR(RAND() * (
SELECT id FROM tbl ORDER BY id DESC LIMIT 1
)) n FROM tbl LIMIT 10) a
...
SELECT * FROM tbl WHERE id IN ($result);
供您参考:从一个200k表中随机获得10行,我花了1.78 ms(包括php方面的所有操作)
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