我发现在使用Numpy处理大数据时，del对于伪手动内存管理非常有用。例如:

for image_name in large_image_set:
    large_image = io.imread(image_name)
    height, width, depth = large_image.shape
    large_mask = np.all(large_image == <some_condition>)
    # Clear memory, make space
    del large_image; gc.collect()

    large_processed_image = np.zeros((height, width, depth))
    large_processed_image[large_mask] = (new_value)
    io.imsave("processed_image.png", large_processed_image)

    # Clear memory, make space
    del large_mask, large_processed_image; gc.collect()

当Python GC无法跟上时，系统会疯狂地切换，这可能会导致脚本停止，而它在宽松的内存阈值下运行得非常流畅，从而在机器工作时留下了足够的空间来使用机器浏览和编码。

除非重新初始化，否则Del将从当前作用域删除变量。将其设置为None将其保留在当前范围内。

a = "python string"        
print(a)
del a
print(a)
a = "new python string"
print(a)

输出:

python string
Traceback (most recent call last):
  File "testing.py", line 4, in <module>
    print(a)
NameError: name 'a' is not defined

显式使用"del"也是比将变量赋值为None更好的实践。如果你试图删除一个不存在的变量，你会得到一个运行时错误，但如果你试图将一个不存在的变量设置为None, Python会无声地将一个新变量设置为None，让你想要删除的变量留在原来的位置。所以del会帮助你尽早发现错误

del is the equivalent of "unset" in many languages and as a cross reference point moving from another language to python.. people tend to look for commands that do the same thing that they used to do in their first language... also setting a var to "" or none doesn't really remove the var from scope..it just empties its value the name of the var itself would still be stored in memory...why?!? in a memory intensive script..keeping trash behind its just a no no and anyways...every language out there has some form of an "unset/delete" var function..why not python?

作为del可以用来做什么的例子，我发现它在这样的情况下很有用:

def f(a, b, c=3):
    return '{} {} {}'.format(a, b, c)

def g(**kwargs):
    if 'c' in kwargs and kwargs['c'] is None:
        del kwargs['c']

    return f(**kwargs)

# g(a=1, b=2, c=None) === '1 2 3'
# g(a=1, b=2) === '1 2 3'
# g(a=1, b=2, c=4) === '1 2 4'

这两个函数可以在不同的包/模块中，程序员不需要知道f中的参数c实际上有什么默认值。因此，通过将kwargs与del结合使用，您可以将其设置为None(或者在这种情况下也可以保留它)，从而说“I want the default value on c”。

你也可以这样做:

def g(a, b, c=None):
    kwargs = {'a': a,
              'b': b}
    if c is not None:
        kwargs['c'] = c

    return f(**kwargs)

然而，我发现前面的例子更加DRY和优雅。

del所做的部分(来自Python语言参考):

删除名称将从本地或全局名称空间删除该名称的绑定

将None赋值给名称不会删除名称与名称空间的绑定。

(我想关于移除名称绑定是否真的有用可能会有一些争论，但这是另一个问题。)