在。net中检查Internet连接的最快和最有效的方法是什么?


当前回答

多线程版本的ping:

  using System;
  using System.Collections.Generic;
  using System.Diagnostics;
  using System.Net.NetworkInformation;
  using System.Threading;


  namespace OnlineCheck
  {
      class Program
      {

          static bool isOnline = false;

          static void Main(string[] args)
          {
              List<string> ipList = new List<string> {
                  "1.1.1.1", // Bad ip
                  "2.2.2.2",
                  "4.2.2.2",
                  "8.8.8.8",
                  "9.9.9.9",
                  "208.67.222.222",
                  "139.130.4.5"
                  };

              int timeOut = 1000 * 5; // Seconds


              List<Thread> threadList = new List<Thread>();

              foreach (string ip in ipList)
              {

                  Thread threadTest = new Thread(() => IsOnline(ip));
                  threadList.Add(threadTest);
                  threadTest.Start();
              }

              Stopwatch stopwatch = Stopwatch.StartNew();

              while (!isOnline && stopwatch.ElapsedMilliseconds <= timeOut)
              {
                   Thread.Sleep(10); // Cooldown the CPU
              }

              foreach (Thread thread in threadList)
              { 
                  thread.Abort(); // We love threads, don't we?
              }


              Console.WriteLine("Am I online: " + isOnline.ToYesNo());
              Console.ReadKey();
          }

          static bool Ping(string host, int timeout = 3000, int buffer = 32)
          {
              bool result = false;

              try
              {
                  Ping ping = new Ping();                
                  byte[] byteBuffer = new byte[buffer];                
                  PingOptions options = new PingOptions();
                  PingReply reply = ping.Send(host, timeout, byteBuffer, options);
                  result = (reply.Status == IPStatus.Success);
              }
              catch (Exception ex)
              {

              }

              return result;
          }

          static void IsOnline(string host)
          {
              isOnline =  Ping(host) || isOnline;
          }
      }

      public static class BooleanExtensions
      {
          public static string ToYesNo(this bool value)
          {
              return value ? "Yes" : "No";
          }
      }
  }

其他回答

public static bool CheckForInternetConnection(int timeoutMs = 10000, string url = null)
{
    try
    {
        url ??= CultureInfo.InstalledUICulture switch
        {
            { Name: var n } when n.StartsWith("fa") => // Iran
                "http://www.aparat.com",
            { Name: var n } when n.StartsWith("zh") => // China
                "http://www.baidu.com",
            _ =>
                "http://www.gstatic.com/generate_204",
        };

        var request = (HttpWebRequest)WebRequest.Create(url);
        request.KeepAlive = false;
        request.Timeout = timeoutMs;
        using (var response = (HttpWebResponse)request.GetResponse())
            return true;
    }
    catch
    {
        return false;
    }
}

尽量避免通过捕获异常来测试连接。因为我们真的预料到有时我们可能会失去网络连接。

 if (NetworkInterface.GetIsNetworkAvailable() &&
     new Ping().Send(new IPAddress(new byte[] { 8, 8, 8, 8 }),2000).Status == IPStatus.Success)
 //is online
 else
 //is offline

根据@ChaosPandion的回答,为了尽可能确保结果是正确的,你可以像其他人指出的那样,包括多个大网站。但是,这应该异步完成,以避免太长的等待时间。此外,WebRequest、HttpWebRequest和HttpWebResponse类现在已经过时,应该被HttpClient取代。以下示例考虑了上述因素:

public static async Task<bool> CheckForInternetConnection(TimeSpan? timeoutMs = null, List<string> urls = null)
{
    if (timeoutMs == null)
    {
        timeoutMs = TimeSpan.FromSeconds(10);
    }

    var culture = CultureInfo.InstalledUICulture;
    if (urls == null)
    {
        urls = new List<string>();

        if (culture.Name.StartsWith("fa"))      // Iran
            urls.Add("http://www.aparat.com");
        else if (culture.Name.StartsWith("zh")) // China
            urls.Add("http://www.baidu.com");
        else
        {
            urls.Add("https://www.apple.com/");
            urls.Add("https://www.gstatic.com/generate_204");
        }
    }

    var client = new HttpClient();
    client.Timeout = (TimeSpan)timeoutMs;
    List<Task<string>> tasks = new List<Task<string>>();
    int unresponsiveUrlCount = 0;

    foreach (var url in urls)
    {   
        tasks.Add(client.GetStringAsync(url));             
    }

    Task aggregationTask = null;
    try
    {
        aggregationTask = Task.WhenAll(tasks);
        await aggregationTask;
    }
    catch (Exception)
    {  
        if (aggregationTask?.Exception?.InnerExceptions != null && aggregationTask.Exception.InnerExceptions.Any())
        {
            foreach (var innerEx in aggregationTask.Exception.InnerExceptions)
            {
                unresponsiveUrlCount++;
            }
        }      
    }

    return unresponsiveUrlCount < urls.Count;
}

该方法检查列表中的所有url,如果它们都不可访问,则返回false。我已经添加了苹果的url,因为在我的情况下,它加载相当快,但它可以替换为任何url。

如果你想在网络/连接发生变化时通知用户/采取行动。 使用NLM API:

https://msdn.microsoft.com/en-us/library/ee264321.aspx http://www.codeproject.com/Articles/34650/How-to-use-the-Windows-NLM-API-to-get-notified-of

我在我的3g路由器/调制解调器上的那些方法上有问题,因为如果互联网断开连接,路由器将页面重定向到它的响应页面,所以你仍然得到一个蒸汽,你的代码认为有互联网。 苹果(或其他)有一个热点删除页面,总是返回特定的响应。下面的示例返回“Success”响应。所以你会完全确定你可以连接互联网,并得到真实的回应!

public static bool CheckForInternetConnection()
{
    try
    {       
        using (var webClient = new WebClient())
        using (var stream = webClient.OpenRead("http://captive.apple.com/hotspot-detect.html"))
        {
            if (stream != null)
            {
                //return true;
                stream.ReadTimeout = 1000;
                using (var reader = new StreamReader(stream, Encoding.UTF8, false))
                {
                    string line;
                    while ((line = reader.ReadLine()) != null)
                    {
                        if (line == "<HTML><HEAD><TITLE>Success</TITLE></HEAD><BODY>Success</BODY></HTML>")
                        {
                            return true;
                        }
                        Console.WriteLine(line);
                    }
                }

            }
            return false;
        }
    }
    catch
    {

    }
    return false;
}