我用TextFormField收集用户输入,当用户按下FloatingActionButton表示他们已经完成时,我想解散屏幕上的键盘。

如何让键盘自动消失?

import 'package:flutter/material.dart';

class MyHomePage extends StatefulWidget {
  MyHomePageState createState() => new MyHomePageState();
}

class MyHomePageState extends State<MyHomePage> {
  TextEditingController _controller = new TextEditingController();

  @override
  Widget build(BuildContext context) {
    return new Scaffold(
      appBar: new AppBar(),
      floatingActionButton: new FloatingActionButton(
        child: new Icon(Icons.send),
        onPressed: () {
          setState(() {
            // send message
            // dismiss on screen keyboard here
            _controller.clear();
          });
        },
      ),
      body: new Container(
        alignment: FractionalOffset.center,
        padding: new EdgeInsets.all(20.0),
        child: new TextFormField(
          controller: _controller,
          decoration: new InputDecoration(labelText: 'Example Text'),
        ),
      ),
    );
  }
}

class MyApp extends StatelessWidget {
  @override
  Widget build(BuildContext context) {
    return new MaterialApp(
      home: new MyHomePage(),
    );
  }
}

void main() {
  runApp(new MyApp());
}

当前回答

你也可以为你的文本域声明一个focusNode,当你完成时,你可以在那个focusNode上调用unfocus方法 然后处理它

class MyHomePage extends StatefulWidget {
  MyHomePageState createState() => new MyHomePageState();
}

class MyHomePageState extends State<MyHomePage> {
  TextEditingController _controller = new TextEditingController();

/// declare focus
  final FocusNode _titleFocus = FocusNode();

  @override
  void dispose() {
    _titleFocus.dispose();
  }

  @override
  Widget build(BuildContext context) {
    return new Scaffold(
      appBar: new AppBar(),
      floatingActionButton: new FloatingActionButton(
        child: new Icon(Icons.send),
        onPressed: () {
          setState(() {
            // send message
            // dismiss on screen keyboard here

            _titleFocus.unfocus();
            _controller.clear();
          });
        },
      ),
      body: new Container(
        alignment: FractionalOffset.center,
        padding: new EdgeInsets.all(20.0),
        child: new TextFormField(
          controller: _controller,
          focusNode: _titleFocus,
          decoration: new InputDecoration(labelText: 'Example Text'),
        ),
      ),
    );
  }
}

其他回答

以上的解决方案都不适合我。

Flutter的意思是 把你的小部件在新手势检测器()上,点击将隐藏键盘和onTap使用FocusScope.of(context)。新FocusNode requestFocus (())

class Home extends StatelessWidget {
@override
  Widget build(BuildContext context) {
    var widget = new MaterialApp(
        home: new Scaffold(
            body: new Container(
                height:500.0,
                child: new GestureDetector(
                    onTap: () {
                        FocusScope.of(context).requestFocus(new FocusNode());
                    },
                    child: new Container(
                        color: Colors.white,
                        child:  new Column(
                            mainAxisAlignment:  MainAxisAlignment.center,
                            crossAxisAlignment: CrossAxisAlignment.center,

                            children: [
                                new TextField( ),
                                new Text("Test"),                                
                            ],
                        )
                    )
                )
            )
        ),
    );

    return widget;
}}

这可能会简化情况。下面的代码只在键盘打开时才会工作

if(FocusScope.of(context).isFirstFocus) {
 FocusScope.of(context).requestFocus(new FocusNode());
}

======解散键盘后,点击TextField =======

 @override
  Widget build(BuildContext context) {
    return GestureDetector(
      onTap: () => FocusScope.of(context).unfocus(),  //this will dismiss keyboard
      child: Scaffold(
        body: SafeArea(
               .........

======滚动屏幕时关闭键盘=======

ListView(
            keyboardDismissBehavior: ScrollViewKeyboardDismissBehavior.onDrag, //this will dismiss
            children: [
               ..........

SingleChildScrollView小部件也有这个属性。

总之,这是Flutter 1.17的工作解决方案:

像这样包装你的Widget:

GestureDetector(
        onTap: FocusScope.of(context).unfocus,
        child: YourWidget(),
);

FocusScope.of(context).unfocus()在与过滤后的listView一起使用时有一个缺点。 除了这么多细节和简洁,使用https://pub.dev/packages/keyboard_dismisser中的keyboard_disser包将解决所有问题。