在给函数使用原始变量时，更好的做法是什么:
unsigned long x = 4;
void func1(unsigned long& val) {
val = 5;
}
func1(x);
or:
void func2(unsigned long* val) {
*val = 5;
}
func2(&x);
勒夫:有什么理由选择一个而不是另一个吗?
当前回答
通过const引用传递，除非有原因你希望改变/保留你传递的内容。
在大多数情况下，这将是最有效的方法。
确保对不想更改的每个形参都使用const，因为这不仅可以防止您在函数中做一些愚蠢的事情，还可以很好地向其他用户指示函数对传入的值做了什么。这包括当你只想改变所指向的对象时，创建一个const指针…
其他回答
通过const引用传递，除非有原因你希望改变/保留你传递的内容。
在大多数情况下，这将是最有效的方法。
确保对不想更改的每个形参都使用const，因为这不仅可以防止您在函数中做一些愚蠢的事情，还可以很好地向其他用户指示函数对传入的值做了什么。这包括当你只想改变所指向的对象时，创建一个const指针…
这最终是主观的。到目前为止的讨论是有用的，但我不认为有一个正确或决定性的答案。这在很大程度上取决于风格指南和您当时的需求。
While there are some different capabilities (whether or not something can be NULL) with a pointer, the largest practical difference for an output parameter is purely syntax. Google's C++ Style Guide (https://google.github.io/styleguide/cppguide.html#Reference_Arguments), for example, mandates only pointers for output parameters, and allows only references that are const. The reasoning is one of readability: something with value syntax should not have pointer semantic meaning. I'm not suggesting that this is necessarily right or wrong, but I think the point here is that it's a matter of style, not of correctness.
指针
A pointer is a variable that holds a memory address. A pointer declaration consists of a base type, an *, and the variable name. A pointer can point to any number of variables in lifetime A pointer that does not currently point to a valid memory location is given the value null (Which is zero) BaseType* ptrBaseType; BaseType objBaseType; ptrBaseType = &objBaseType; The & is a unary operator that returns the memory address of its operand. Dereferencing operator (*) is used to access the value stored in the variable which pointer points to. int nVar = 7; int* ptrVar = &nVar; int nVar2 = *ptrVar;
参考
A reference (&) is like an alias to an existing variable. A reference (&) is like a constant pointer that is automatically dereferenced. It is usually used for function argument lists and function return values. A reference must be initialized when it is created. Once a reference is initialized to an object, it cannot be changed to refer to another object. You cannot have NULL references. A const reference can refer to a const int. It is done with a temporary variable with value of the const int i = 3; //integer declaration int * pi = &i; //pi points to the integer i int& ri = i; //ri is refers to integer i – creation of reference and initialization
可以时使用引用，必要时使用指针。 来自c++常见问题:“什么时候应该使用引用，什么时候应该使用指针?”
如果你要修改变量的值，你应该传递一个指针。 尽管在技术上传递引用或指针是相同的，但在用例中传递指针更具有可读性，因为它“通告”了函数将更改值的事实。
