const isHTMLElementInView = (element: HTMLElement) => {
  const rect = element?.getBoundingClientRect()

  if (!rect) return
  return rect.top <= window.innerHeight && rect.bottom >= 0
 }

这个函数检查元素是否在垂直水平的视口中。

我有同样的问题，并通过使用getBoundingClientRect()来解决。

这段代码完全是“通用的”，只需要写一次就可以工作(你不需要为你想知道的每个元素都写出来)。

这段代码只检查它在视口中是否垂直，而不是水平。在本例中，变量(array)'elements'保存了所有你要检查的垂直在视口中的元素，所以在任何地方抓取任何你想要的元素并将它们存储在那里。

for循环遍历每个元素并检查它是否垂直地位于视口中。这段代码在用户每次滚动时执行!如果getBoudingClientRect()。Top小于viewport的3/4(元素在viewport中的四分之一)，它注册为“在viewport中”。

因为代码是通用的，你会想知道“哪个”元素在视口中。要找出这一点，可以通过自定义属性、节点名、id、类名等确定。

这是我的代码(如果它不起作用，请告诉我;它已在Internet Explorer 11、Firefox 40.0.3、Chrome Version 45.0.2454.85 m、Opera 31.0.1889.174和Edge with Windows 10(还没有Safari)上测试……

// Scrolling handlers...
window.onscroll = function(){
  var elements = document.getElementById('whatever').getElementsByClassName('whatever');
  for(var i = 0; i != elements.length; i++)
  {
   if(elements[i].getBoundingClientRect().top <= window.innerHeight*0.75 &&
      elements[i].getBoundingClientRect().top > 0)
   {
      console.log(elements[i].nodeName + ' ' +
                  elements[i].className + ' ' +
                  elements[i].id +
                  ' is in the viewport; proceed with whatever code you want to do here.');
   }
};

/**
 * Returns Element placement information in Viewport
 * @link https://stackoverflow.com/a/70476497/2453148
 *
 * @typedef {object} ViewportInfo - Whether the element is…
 * @property {boolean} isInViewport - fully or partially in the viewport
 * @property {boolean} isPartiallyInViewport - partially in the viewport
 * @property {boolean} isInsideViewport - fully inside viewport
 * @property {boolean} isAroundViewport - completely covers the viewport
 * @property {boolean} isOnEdge - intersects the edge of viewport
 * @property {boolean} isOnTopEdge - intersects the top edge
 * @property {boolean} isOnRightEdge - intersects the right edge
 * @property {boolean} isOnBottomEdge - is intersects the bottom edge
 * @property {boolean} isOnLeftEdge - is intersects the left edge
 *
 * @param el Element
 * @return {Object} ViewportInfo
 */
function getElementViewportInfo(el) {

    let result = {};

    let rect = el.getBoundingClientRect();
    let windowHeight = window.innerHeight || document.documentElement.clientHeight;
    let windowWidth  = window.innerWidth || document.documentElement.clientWidth;

    let insideX = rect.left >= 0 && rect.left + rect.width <= windowWidth;
    let insideY = rect.top >= 0 && rect.top + rect.height <= windowHeight;

    result.isInsideViewport = insideX && insideY;

    let aroundX = rect.left < 0 && rect.left + rect.width > windowWidth;
    let aroundY = rect.top < 0 && rect.top + rect.height > windowHeight;

    result.isAroundViewport = aroundX && aroundY;

    let onTop    = rect.top < 0 && rect.top + rect.height > 0;
    let onRight  = rect.left < windowWidth && rect.left + rect.width > windowWidth;
    let onLeft   = rect.left < 0 && rect.left + rect.width > 0;
    let onBottom = rect.top < windowHeight && rect.top + rect.height > windowHeight;

    let onY = insideY || aroundY || onTop || onBottom;
    let onX = insideX || aroundX || onLeft || onRight;

    result.isOnTopEdge    = onTop && onX;
    result.isOnRightEdge  = onRight && onY;
    result.isOnBottomEdge = onBottom && onX;
    result.isOnLeftEdge   = onLeft && onY;

    result.isOnEdge = result.isOnLeftEdge || result.isOnRightEdge ||
        result.isOnTopEdge || result.isOnBottomEdge;

    let isInX =
        insideX || aroundX || result.isOnLeftEdge || result.isOnRightEdge;
    let isInY =
        insideY || aroundY || result.isOnTopEdge || result.isOnBottomEdge;

    result.isInViewport = isInX && isInY;

    result.isPartiallyInViewport =
        result.isInViewport && result.isOnEdge;

    return result;
}

下面是检查给定元素在其父元素中是否完全可见的代码片段:

export const visibleInParentViewport = (el) => {
  const elementRect = el.getBoundingClientRect();
  const parentRect = el.parentNode.getBoundingClientRect();

  return (
    elementRect.top >= parentRect.top &&
    elementRect.right >= parentRect.left &&
    elementRect.top + elementRect.height <= parentRect.bottom &&
    elementRect.left + elementRect.width <= parentRect.right
  );
}

对于类似的挑战，我非常喜欢这个要点，它为scrollIntoViewIfNeeded()暴露了一个填充。

所有必要的功夫都需要回答这个问题:

var parent = this.parentNode,
    parentComputedStyle = window.getComputedStyle(parent, null),
    parentBorderTopWidth = parseInt(parentComputedStyle.getPropertyValue('border-top-width')),
    parentBorderLeftWidth = parseInt(parentComputedStyle.getPropertyValue('border-left-width')),
    overTop = this.offsetTop - parent.offsetTop < parent.scrollTop,
    overBottom = (this.offsetTop - parent.offsetTop + this.clientHeight - parentBorderTopWidth) > (parent.scrollTop + parent.clientHeight),
    overLeft = this.offsetLeft - parent.offsetLeft < parent.scrollLeft,
    overRight = (this.offsetLeft - parent.offsetLeft + this.clientWidth - parentBorderLeftWidth) > (parent.scrollLeft + parent.clientWidth),
    alignWithTop = overTop && !overBottom;

这指的是你想知道的元素，例如，overTop或overBottom -你只需要得到漂移…

下面是一个函数，它告诉你一个元素在父元素的当前视口中是否可见:

function inParentViewport(el, pa) {
    if (typeof jQuery === "function"){
        if (el instanceof jQuery)
            el = el[0];
        if (pa instanceof jQuery)
            pa = pa[0];
    }

    var e = el.getBoundingClientRect();
    var p = pa.getBoundingClientRect();

    return (
        e.bottom >= p.top &&
        e.right >= p.left &&
        e.top <= p.bottom &&
        e.left <= p.right
    );
}