我写了这个函数用于在目录之间递归地复制(copyFileSync)或移动(renameSync)文件:

// Copy files
copyDirectoryRecursiveSync(sourceDir, targetDir);
// Move files
copyDirectoryRecursiveSync(sourceDir, targetDir, true);


function copyDirectoryRecursiveSync(source, target, move) {
    if (!fs.lstatSync(source).isDirectory())
        return;

    var operation = move ? fs.renameSync : fs.copyFileSync;
    fs.readdirSync(source).forEach(function (itemName) {
        var sourcePath = path.join(source, itemName);
        var targetPath = path.join(target, itemName);

        if (fs.lstatSync(sourcePath).isDirectory()) {
            fs.mkdirSync(targetPath);
            copyDirectoryRecursiveSync(sourcePath, targetPath);
        }
        else {
            operation(sourcePath, targetPath);
        }
    });
}

内联版本

node -e "const fs=require('fs');const p=require('path');function copy(src, dest) {if (!fs.existsSync(src)) {return;} if (fs.statSync(src).isFile()) {fs.copyFileSync(src, dest);}else{fs.mkdirSync(dest, {recursive: true});fs.readdirSync(src).forEach(f=>copy(p.join(src, f), p.join(dest, f)));}}const args=Array.from(process.argv); copy(args[args.length-2], args[args.length-1]);" dist temp\dest

或者节点16.x+

node -e "const fs=require('fs');const args=Array.from(process.argv); fs.cpSync(args[args.length-2], args[args.length-1], {recursive: true});" 

在“节点14.20.0”上测试，但假设它在节点10.x上工作?

来自user8894303和pen的回答:https://stackoverflow.com/a/52338335/458321

如果在包中使用，请务必转义引号。json脚本

package.json:

  "scripts": {
    "rmrf": "node -e \"const fs=require('fs/promises');const args=Array.from(process.argv); Promise.allSettled(args.map(a => fs.rm(a, { recursive: true, force: true })));\"",
    "cp": "node -e \"const fs=require('fs');const args=Array.from(process.argv);if (args.length>2){ fs.cpSync(args[args.length-2], args[args.length-1], {recursive: true});}else{console.log('args missing', args);}\""
    "copy": "node -e \"const fs=require('fs');const p=require('path');function copy(src, dest) {if (!fs.existsSync(src)) {return;} if (fs.statSync(src).isFile()) {fs.copyFileSync(src, dest);}else{fs.mkdirSync(dest, {recursive: true});fs.readdirSync(src).forEach(f=>copy(p.join(src, f), p.join(dest, f)));}}const args=Array.from(process.argv);if (args.length>2){copy(args[args.length-2], args[args.length-1]);}else{console.log('args missing', args);}\"",
    "mkdir": "node -e \"const fs=require('fs');const args=Array.from(process.argv);fs.mkdirSync(args[args.length-1],{recursive:true});\"",
    "clean": "npm run rmrf -- temp && npm run mkdir -- temp && npm run copy -- dist temp"
  }

注:RMRF脚本需要14.20节点。X还是12.20.x?

奖金:

deno eval "import { existsSync, mkdirSync, copyFileSync, readdirSync, statSync } from 'node:fs';import { join } from 'node:path';function copy(src, dest) {if (!existsSync(src)) {return;} if (statSync(src).isFile()) {copyFileSync(src, dest);}else{mkdirSync(dest, {recursive: true});readdirSync(src).forEach(f=>copy(join(src, f), join(dest, f)));}}const args=Array.from(Deno.args);copy(args[0], args[1]);" dist temp\dest -- --allow-read --allow-write

Deno支持-> NPM I Deno -bin支持节点中的Deno -bin

如果你在Linux上，性能不是问题，你可以使用child_process模块中的exec函数来执行一个Bash命令:

const { exec } = require('child_process');
exec('cp -r source dest', (error, stdout, stderr) => {...});

在某些情况下，我发现这个解决方案比下载整个模块甚至使用fs模块更简洁。

对于没有fs的旧节点版本。cp，我在紧要关头使用这个来避免需要第三方库:

const fs = require("fs").promises;
const path = require("path");

const cp = async (src, dest) => {
  const lstat = await fs.lstat(src).catch(err => false);

  if (!lstat) {
    return;
  }
  else if (await lstat.isFile()) {
    await fs.copyFile(src, dest);
  }
  else if (await lstat.isDirectory()) {
    await fs.mkdir(dest).catch(err => {});

    for (const f of await fs.readdir(src)) {
      await cp(path.join(src, f), path.join(dest, f));
    }
  }
};

// sample usage
(async () => {
  const src = "foo";
  const dst = "bar";

  for (const f of await fs.readdir(src)) {
    await cp(path.join(src, f), path.join(dst, f));
  }
})();

相对于现有答案的优势(或区别):

异步 忽略符号链接 如果目录已经存在，则不抛出(如果不需要，则不捕获mkdir抛出) 相当简洁的

这是我个人的做法:

function copyFolderSync(from, to) {
    fs.mkdirSync(to);
    fs.readdirSync(from).forEach(element => {
        if (fs.lstatSync(path.join(from, element)).isFile()) {
            fs.copyFileSync(path.join(from, element), path.join(to, element));
        } else {
            copyFolderSync(path.join(from, element), path.join(to, element));
        }
    });
}

它适用于文件夹和文件。

对于Linux/Unix操作系统，可以使用shell语法

const shell = require('child_process').execSync;

const src = `/path/src`;
const dist = `/path/dist`;

shell(`mkdir -p ${dist}`);
shell(`cp -r ${src}/* ${dist}`);

就是这样!