解决这个问题最简单的方法是只使用'fs'和'Path'模块和一些逻辑…

如果你只是想设置版本号，根文件夹中的所有文件都复制新名称，即" var v = '您的目录名'"

在文件名的前缀中添加带有文件名的内容。

var fs = require('fs-extra');
var path = require('path');

var c = 0;
var i = 0;
var v = "1.0.2";
var copyCounter = 0;
var directoryCounter = 0;
var directoryMakerCounter = 0;
var recursionCounter = -1;
var Flag = false;
var directoryPath = [];
var directoryName = [];
var directoryFileName = [];
var fileName;
var directoryNameStorer;
var dc = 0;
var route;

if (!fs.existsSync(v)) {
    fs.mkdirSync(v);
}

var basePath = path.join(__dirname, v);


function walk(dir) {

    fs.readdir(dir, function(err, items) {

        items.forEach(function(file) {

            file = path.resolve(dir, file);

            fs.stat(file, function(err, stat) {

                if(stat && stat.isDirectory()) {
                    directoryNameStorer = path.basename(file);
                    route = file;
                    route = route.replace("gd", v);

                    directoryFileName[directoryCounter] = route;
                    directoryPath[directoryCounter] = file;
                    directoryName[directoryCounter] = directoryNameStorer;

                    directoryCounter++;
                    dc++;

                    if (!fs.existsSync(basePath + "/" + directoryName[directoryMakerCounter])) {
                        fs.mkdirSync(directoryFileName[directoryMakerCounter]);
                        directoryMakerCounter++;
                    }
                }
                else {
                    fileName = path.basename(file);
                    if(recursionCounter >= 0) {
                        fs.copyFileSync(file, directoryFileName[recursionCounter] + "/" + v + "_" + fileName, err => {
                            if(err) return console.error(err);
                        });
                        copyCounter++;
                    }
                    else {
                        fs.copyFileSync(file, v + "/" + v + "_" + fileName, err => {
                            if(err) return console.error(err);
                        });
                        copyCounter++;
                    }
                }
                if(copyCounter + dc == items.length && directoryCounter > 0 && recursionCounter < directoryMakerCounter-1) {
                    console.log("COPY COUNTER:             " + copyCounter);
                    console.log("DC COUNTER:               " + dc);
                    recursionCounter++;
                    dc = 0;
                    copyCounter = 0;
                    console.log("ITEM DOT LENGTH:          " + items.length);
                    console.log("RECURSION COUNTER:        " + recursionCounter);
                    console.log("DIRECOTRY MAKER COUNTER:  " + directoryMakerCounter);
                    console.log(": START RECURSION:        " + directoryPath[recursionCounter]);
                    walk(directoryPath[recursionCounter]); //recursive call to copy sub-folder
                }
            })
        })
    });
}

walk('./gd', function(err, data) { // Just pass the root directory which you want to copy
    if(err)
        throw err;
    console.log("done");
})

从Node v16.7.0开始:

import { cp } from 'fs/promises';
await cp(
  new URL('../path/to/src/', import.meta.url),
  new URL('../path/to/dest/', import.meta.url), {
    recursive: true,
  }
);

注意使用递归:true。这可以防止ERR_FS_EISDIR错误。

阅读更多关于节点文件系统的文档

有一些模块支持复制文件夹及其内容。最流行的是wrench.js:

// Deep-copy an existing directory
wrench.copyDirSyncRecursive('directory_to_copy', 'location_where_copy_should_end_up');

一个替代方案是node-fs-extra:

fs.copy('/tmp/mydir', '/tmp/mynewdir', function (err) {
  if (err) {
    console.error(err);
  } else {
    console.log("success!");
  }
}); // Copies directory, even if it has subdirectories or files

这可能是一个可能的解决方案使用异步生成器函数和迭代等待循环。这个解决方案包括过滤掉一些目录的可能性，将它们作为可选的第三个数组参数传递。

import path from 'path';
import { readdir, copy } from 'fs-extra';

async function* getFilesRecursive(srcDir: string, excludedDir?: PathLike[]): AsyncGenerator<string> {
  const directoryEntries: Dirent[] = await readdir(srcDir, { withFileTypes: true });
  if (!directoryEntries.length) yield srcDir; // If the directory is empty, return the directory path.
  for (const entry of directoryEntries) {
    const fileName = entry.name;
      const sourcePath = resolvePath(`${srcDir}/${fileName}`);
      if (entry.isDirectory()) {
        if (!excludedDir?.includes(sourcePath)) {
          yield* getFilesRecursive(sourcePath, excludedDir);
        }
      } else {
        yield sourcePath;
      }
  }
}

然后:

for await (const filePath of getFilesRecursive(path, ['dir1', 'dir2'])) {
   await copy(filePath, filePath.replace(path, path2));
}

目前最上面的答案可以大大简化。

const path = require('path');
const fs = require('fs');

function recursiveCopySync(source, target) {
  if (fs.lstatSync(source).isDirectory()) {
    if (!fs.existsSync(target)) {
      fs.mkdirSync(target);
    }
    let files = fs.readdirSync(source);
    files.forEach((file) => {
      recursiveCopySync(path.join(source, file), path.join(target, file));
    });
  } else {
    if (fs.existsSync(source)) {
      fs.writeFileSync(target, fs.readFileSync(source));
    }
  }
}

对于没有fs的旧节点版本。cp，我在紧要关头使用这个来避免需要第三方库:

const fs = require("fs").promises;
const path = require("path");

const cp = async (src, dest) => {
  const lstat = await fs.lstat(src).catch(err => false);

  if (!lstat) {
    return;
  }
  else if (await lstat.isFile()) {
    await fs.copyFile(src, dest);
  }
  else if (await lstat.isDirectory()) {
    await fs.mkdir(dest).catch(err => {});

    for (const f of await fs.readdir(src)) {
      await cp(path.join(src, f), path.join(dest, f));
    }
  }
};

// sample usage
(async () => {
  const src = "foo";
  const dst = "bar";

  for (const f of await fs.readdir(src)) {
    await cp(path.join(src, f), path.join(dst, f));
  }
})();

相对于现有答案的优势(或区别):

异步 忽略符号链接 如果目录已经存在，则不抛出(如果不需要，则不捕获mkdir抛出) 相当简洁的