是否有一种更简单的方法来复制文件夹及其所有内容,而无需手动执行一系列的fs。readir, fs。readfile, fs。writefile递归?
我只是想知道我是否错过了一个函数,理想情况下是这样工作的:
fs.copy("/path/to/source/folder", "/path/to/destination/folder");
关于这个历史问题。注意fs。Cp和fs。cpSync可以递归复制文件夹,在Node v16+中可用
是否有一种更简单的方法来复制文件夹及其所有内容,而无需手动执行一系列的fs。readir, fs。readfile, fs。writefile递归?
我只是想知道我是否错过了一个函数,理想情况下是这样工作的:
fs.copy("/path/to/source/folder", "/path/to/destination/folder");
关于这个历史问题。注意fs。Cp和fs。cpSync可以递归复制文件夹,在Node v16+中可用
当前回答
内联版本
node -e "const fs=require('fs');const p=require('path');function copy(src, dest) {if (!fs.existsSync(src)) {return;} if (fs.statSync(src).isFile()) {fs.copyFileSync(src, dest);}else{fs.mkdirSync(dest, {recursive: true});fs.readdirSync(src).forEach(f=>copy(p.join(src, f), p.join(dest, f)));}}const args=Array.from(process.argv); copy(args[args.length-2], args[args.length-1]);" dist temp\dest
或者节点16.x+
node -e "const fs=require('fs');const args=Array.from(process.argv); fs.cpSync(args[args.length-2], args[args.length-1], {recursive: true});"
在“节点14.20.0”上测试,但假设它在节点10.x上工作?
来自user8894303和pen的回答:https://stackoverflow.com/a/52338335/458321
如果在包中使用,请务必转义引号。json脚本
package.json:
"scripts": {
"rmrf": "node -e \"const fs=require('fs/promises');const args=Array.from(process.argv); Promise.allSettled(args.map(a => fs.rm(a, { recursive: true, force: true })));\"",
"cp": "node -e \"const fs=require('fs');const args=Array.from(process.argv);if (args.length>2){ fs.cpSync(args[args.length-2], args[args.length-1], {recursive: true});}else{console.log('args missing', args);}\""
"copy": "node -e \"const fs=require('fs');const p=require('path');function copy(src, dest) {if (!fs.existsSync(src)) {return;} if (fs.statSync(src).isFile()) {fs.copyFileSync(src, dest);}else{fs.mkdirSync(dest, {recursive: true});fs.readdirSync(src).forEach(f=>copy(p.join(src, f), p.join(dest, f)));}}const args=Array.from(process.argv);if (args.length>2){copy(args[args.length-2], args[args.length-1]);}else{console.log('args missing', args);}\"",
"mkdir": "node -e \"const fs=require('fs');const args=Array.from(process.argv);fs.mkdirSync(args[args.length-1],{recursive:true});\"",
"clean": "npm run rmrf -- temp && npm run mkdir -- temp && npm run copy -- dist temp"
}
注:RMRF脚本需要14.20节点。X还是12.20.x?
奖金:
deno eval "import { existsSync, mkdirSync, copyFileSync, readdirSync, statSync } from 'node:fs';import { join } from 'node:path';function copy(src, dest) {if (!existsSync(src)) {return;} if (statSync(src).isFile()) {copyFileSync(src, dest);}else{mkdirSync(dest, {recursive: true});readdirSync(src).forEach(f=>copy(join(src, f), join(dest, f)));}}const args=Array.from(Deno.args);copy(args[0], args[1]);" dist temp\dest -- --allow-read --allow-write
Deno支持-> NPM I Deno -bin支持节点中的Deno -bin
其他回答
Mallikarjun M,谢谢!
fs-extra做了这件事,如果你不提供一个回调,它甚至可以返回一个承诺!:)
const path = require('path')
const fs = require('fs-extra')
let source = path.resolve( __dirname, 'folderA')
let destination = path.resolve( __dirname, 'folderB')
fs.copy(source, destination)
.then(() => console.log('Copy completed!'))
.catch( err => {
console.log('An error occurred while copying the folder.')
return console.error(err)
})
从Node v16.7.0开始:
import { cp } from 'fs/promises';
await cp(
new URL('../path/to/src/', import.meta.url),
new URL('../path/to/dest/', import.meta.url), {
recursive: true,
}
);
注意使用递归:true。这可以防止ERR_FS_EISDIR错误。
阅读更多关于节点文件系统的文档
使用 shelljs
npm i -D shelljs
const bash = require('shelljs');
bash.cp("-rf", "/path/to/source/folder", "/path/to/destination/folder");
我尝试了fs-extra和copy-dir来递归地复制文件夹。但我希望它能
正常工作(copy-dir抛出一个不合理的错误) 在过滤器中提供两个参数:filepath和filetype (fs-extra不告诉文件类型) 有从目录到子目录的检查和从目录到文件的检查吗
所以我自己写了:
// Node.js module for Node.js 8.6+
var path = require("path");
var fs = require("fs");
function copyDirSync(src, dest, options) {
var srcPath = path.resolve(src);
var destPath = path.resolve(dest);
if(path.relative(srcPath, destPath).charAt(0) != ".")
throw new Error("dest path must be out of src path");
var settings = Object.assign(Object.create(copyDirSync.options), options);
copyDirSync0(srcPath, destPath, settings);
function copyDirSync0(srcPath, destPath, settings) {
var files = fs.readdirSync(srcPath);
if (!fs.existsSync(destPath)) {
fs.mkdirSync(destPath);
}else if(!fs.lstatSync(destPath).isDirectory()) {
if(settings.overwrite)
throw new Error(`Cannot overwrite non-directory '${destPath}' with directory '${srcPath}'.`);
return;
}
files.forEach(function(filename) {
var childSrcPath = path.join(srcPath, filename);
var childDestPath = path.join(destPath, filename);
var type = fs.lstatSync(childSrcPath).isDirectory() ? "directory" : "file";
if(!settings.filter(childSrcPath, type))
return;
if (type == "directory") {
copyDirSync0(childSrcPath, childDestPath, settings);
} else {
fs.copyFileSync(childSrcPath, childDestPath, settings.overwrite ? 0 : fs.constants.COPYFILE_EXCL);
if(!settings.preserveFileDate)
fs.futimesSync(childDestPath, Date.now(), Date.now());
}
});
}
}
copyDirSync.options = {
overwrite: true,
preserveFileDate: true,
filter: function(filepath, type) {
return true;
}
};
还有一个类似的函数mkdirs,它是mkdirp的替代:
function mkdirsSync(dest) {
var destPath = path.resolve(dest);
mkdirsSync0(destPath);
function mkdirsSync0(destPath) {
var parentPath = path.dirname(destPath);
if(parentPath == destPath)
throw new Error(`cannot mkdir ${destPath}, invalid root`);
if (!fs.existsSync(destPath)) {
mkdirsSync0(parentPath);
fs.mkdirSync(destPath);
}else if(!fs.lstatSync(destPath).isDirectory()) {
throw new Error(`cannot mkdir ${destPath}, a file already exists there`);
}
}
}
我创建了一个小的工作示例,只需几个步骤就可以将源文件夹复制到另一个目标文件夹(基于shift66使用ncp的答案):
步骤1 -安装ncp模块:
npm install ncp --save
步骤2 -创建copy.js(修改srcPath和destPath变量为你需要的任何变量):
var path = require('path');
var ncp = require('ncp').ncp;
ncp.limit = 16;
var srcPath = path.dirname(require.main.filename); // Current folder
var destPath = '/path/to/destination/folder'; // Any destination folder
console.log('Copying files...');
ncp(srcPath, destPath, function (err) {
if (err) {
return console.error(err);
}
console.log('Copying files complete.');
});
第三步——跑步
node copy.js