是否有一种更简单的方法来复制文件夹及其所有内容,而无需手动执行一系列的fs。readir, fs。readfile, fs。writefile递归?
我只是想知道我是否错过了一个函数,理想情况下是这样工作的:
fs.copy("/path/to/source/folder", "/path/to/destination/folder");
关于这个历史问题。注意fs。Cp和fs。cpSync可以递归复制文件夹,在Node v16+中可用
是否有一种更简单的方法来复制文件夹及其所有内容,而无需手动执行一系列的fs。readir, fs。readfile, fs。writefile递归?
我只是想知道我是否错过了一个函数,理想情况下是这样工作的:
fs.copy("/path/to/source/folder", "/path/to/destination/folder");
关于这个历史问题。注意fs。Cp和fs。cpSync可以递归复制文件夹,在Node v16+中可用
当前回答
从Node v16.7.0开始:
import { cp } from 'fs/promises';
await cp(
new URL('../path/to/src/', import.meta.url),
new URL('../path/to/dest/', import.meta.url), {
recursive: true,
}
);
注意使用递归:true。这可以防止ERR_FS_EISDIR错误。
阅读更多关于节点文件系统的文档
其他回答
目前最上面的答案可以大大简化。
const path = require('path');
const fs = require('fs');
function recursiveCopySync(source, target) {
if (fs.lstatSync(source).isDirectory()) {
if (!fs.existsSync(target)) {
fs.mkdirSync(target);
}
let files = fs.readdirSync(source);
files.forEach((file) => {
recursiveCopySync(path.join(source, file), path.join(target, file));
});
} else {
if (fs.existsSync(source)) {
fs.writeFileSync(target, fs.readFileSync(source));
}
}
}
解决这个问题最简单的方法是只使用'fs'和'Path'模块和一些逻辑…
如果你只是想设置版本号,根文件夹中的所有文件都复制新名称,即" var v = '您的目录名'"
在文件名的前缀中添加带有文件名的内容。
var fs = require('fs-extra');
var path = require('path');
var c = 0;
var i = 0;
var v = "1.0.2";
var copyCounter = 0;
var directoryCounter = 0;
var directoryMakerCounter = 0;
var recursionCounter = -1;
var Flag = false;
var directoryPath = [];
var directoryName = [];
var directoryFileName = [];
var fileName;
var directoryNameStorer;
var dc = 0;
var route;
if (!fs.existsSync(v)) {
fs.mkdirSync(v);
}
var basePath = path.join(__dirname, v);
function walk(dir) {
fs.readdir(dir, function(err, items) {
items.forEach(function(file) {
file = path.resolve(dir, file);
fs.stat(file, function(err, stat) {
if(stat && stat.isDirectory()) {
directoryNameStorer = path.basename(file);
route = file;
route = route.replace("gd", v);
directoryFileName[directoryCounter] = route;
directoryPath[directoryCounter] = file;
directoryName[directoryCounter] = directoryNameStorer;
directoryCounter++;
dc++;
if (!fs.existsSync(basePath + "/" + directoryName[directoryMakerCounter])) {
fs.mkdirSync(directoryFileName[directoryMakerCounter]);
directoryMakerCounter++;
}
}
else {
fileName = path.basename(file);
if(recursionCounter >= 0) {
fs.copyFileSync(file, directoryFileName[recursionCounter] + "/" + v + "_" + fileName, err => {
if(err) return console.error(err);
});
copyCounter++;
}
else {
fs.copyFileSync(file, v + "/" + v + "_" + fileName, err => {
if(err) return console.error(err);
});
copyCounter++;
}
}
if(copyCounter + dc == items.length && directoryCounter > 0 && recursionCounter < directoryMakerCounter-1) {
console.log("COPY COUNTER: " + copyCounter);
console.log("DC COUNTER: " + dc);
recursionCounter++;
dc = 0;
copyCounter = 0;
console.log("ITEM DOT LENGTH: " + items.length);
console.log("RECURSION COUNTER: " + recursionCounter);
console.log("DIRECOTRY MAKER COUNTER: " + directoryMakerCounter);
console.log(": START RECURSION: " + directoryPath[recursionCounter]);
walk(directoryPath[recursionCounter]); //recursive call to copy sub-folder
}
})
})
});
}
walk('./gd', function(err, data) { // Just pass the root directory which you want to copy
if(err)
throw err;
console.log("done");
})
下面是一个递归复制目录及其内容到另一个目录的函数:
const fs = require("fs")
const path = require("path")
/**
* Look ma, it's cp -R.
* @param {string} src The path to the thing to copy.
* @param {string} dest The path to the new copy.
*/
var copyRecursiveSync = function(src, dest) {
var exists = fs.existsSync(src);
var stats = exists && fs.statSync(src);
var isDirectory = exists && stats.isDirectory();
if (isDirectory) {
fs.mkdirSync(dest);
fs.readdirSync(src).forEach(function(childItemName) {
copyRecursiveSync(path.join(src, childItemName),
path.join(dest, childItemName));
});
} else {
fs.copyFileSync(src, dest);
}
};
我是这样做的:
let fs = require('fs');
let path = require('path');
然后:
let filePath = // Your file path
let fileList = []
var walkSync = function(filePath, filelist)
{
let files = fs.readdirSync(filePath);
filelist = filelist || [];
files.forEach(function(file)
{
if (fs.statSync(path.join(filePath, file)).isDirectory())
{
filelist = walkSync(path.join(filePath, file), filelist);
}
else
{
filelist.push(path.join(filePath, file));
}
});
// Ignore hidden files
filelist = filelist.filter(item => !(/(^|\/)\.[^\/\.]/g).test(item));
return filelist;
};
然后调用该方法:
This.walkSync(filePath, fileList)
这是我个人的做法:
function copyFolderSync(from, to) {
fs.mkdirSync(to);
fs.readdirSync(from).forEach(element => {
if (fs.lstatSync(path.join(from, element)).isFile()) {
fs.copyFileSync(path.join(from, element), path.join(to, element));
} else {
copyFolderSync(path.join(from, element), path.join(to, element));
}
});
}
它适用于文件夹和文件。