是否有一种更简单的方法来复制文件夹及其所有内容,而无需手动执行一系列的fs。readir, fs。readfile, fs。writefile递归?

我只是想知道我是否错过了一个函数,理想情况下是这样工作的:

fs.copy("/path/to/source/folder", "/path/to/destination/folder");

关于这个历史问题。注意fs。Cp和fs。cpSync可以递归复制文件夹,在Node v16+中可用


当前回答

我创建了一个小的工作示例,只需几个步骤就可以将源文件夹复制到另一个目标文件夹(基于shift66使用ncp的答案):

步骤1 -安装ncp模块:

npm install ncp --save

步骤2 -创建copy.js(修改srcPath和destPath变量为你需要的任何变量):

var path = require('path');
var ncp = require('ncp').ncp;

ncp.limit = 16;

var srcPath = path.dirname(require.main.filename); // Current folder
var destPath = '/path/to/destination/folder'; // Any destination folder

console.log('Copying files...');
ncp(srcPath, destPath, function (err) {
  if (err) {
    return console.error(err);
  }
  console.log('Copying files complete.');
});

第三步——跑步

node copy.js

其他回答

有一些模块支持复制文件夹及其内容。最流行的是wrench.js:

// Deep-copy an existing directory
wrench.copyDirSyncRecursive('directory_to_copy', 'location_where_copy_should_end_up');

一个替代方案是node-fs-extra:

fs.copy('/tmp/mydir', '/tmp/mynewdir', function (err) {
  if (err) {
    console.error(err);
  } else {
    console.log("success!");
  }
}); // Copies directory, even if it has subdirectories or files

Mallikarjun M,谢谢!

fs-extra做了这件事,如果你不提供一个回调,它甚至可以返回一个承诺!:)

const path = require('path')
const fs = require('fs-extra')

let source = path.resolve( __dirname, 'folderA')
let destination = path.resolve( __dirname, 'folderB')

fs.copy(source, destination)
  .then(() => console.log('Copy completed!'))
  .catch( err => {
    console.log('An error occurred while copying the folder.')
    return console.error(err)
  })

打印稿版本

async function copyDir(source: string, destination: string): Promise<any> {
  const directoryEntries = await readdir(source, { withFileTypes: true });
  await mkdir(destination, { recursive: true });

  return Promise.all(
    directoryEntries.map(async (entry) => {
      const sourcePath = path.join(source, entry.name);
      const destinationPath = path.join(destination, entry.name);

      return entry.isDirectory()
        ? copyDir(sourcePath, destinationPath)
        : copyFile(sourcePath, destinationPath);
    })
  );
}

我是这样做的:

let fs = require('fs');
let path = require('path');

然后:

let filePath = // Your file path

let fileList = []
    var walkSync = function(filePath, filelist)
    {
        let files = fs.readdirSync(filePath);
        filelist = filelist || [];
        files.forEach(function(file)
        {
            if (fs.statSync(path.join(filePath, file)).isDirectory())
            {
                filelist = walkSync(path.join(filePath, file), filelist);
            }
            else
            {
                filelist.push(path.join(filePath, file));
            }
        });

        // Ignore hidden files
        filelist = filelist.filter(item => !(/(^|\/)\.[^\/\.]/g).test(item));

        return filelist;
    };

然后调用该方法:

This.walkSync(filePath, fileList)

下面是一个递归复制目录及其内容到另一个目录的函数:

const fs = require("fs")
const path = require("path")

/**
 * Look ma, it's cp -R.
 * @param {string} src  The path to the thing to copy.
 * @param {string} dest The path to the new copy.
 */
var copyRecursiveSync = function(src, dest) {
  var exists = fs.existsSync(src);
  var stats = exists && fs.statSync(src);
  var isDirectory = exists && stats.isDirectory();
  if (isDirectory) {
    fs.mkdirSync(dest);
    fs.readdirSync(src).forEach(function(childItemName) {
      copyRecursiveSync(path.join(src, childItemName),
                        path.join(dest, childItemName));
    });
  } else {
    fs.copyFileSync(src, dest);
  }
};