Path.Combine很方便,但是.NET框架中是否有类似的URL函数?
我正在寻找这样的语法:
Url.Combine("http://MyUrl.com/", "/Images/Image.jpg")
这将返回:
"http://MyUrl.com/Images/Image.jpg"
Path.Combine很方便,但是.NET框架中是否有类似的URL函数?
我正在寻找这样的语法:
Url.Combine("http://MyUrl.com/", "/Images/Image.jpg")
这将返回:
"http://MyUrl.com/Images/Image.jpg"
当前回答
我的通用解决方案:
public static string Combine(params string[] uriParts)
{
string uri = string.Empty;
if (uriParts != null && uriParts.Any())
{
char[] trims = new char[] { '\\', '/' };
uri = (uriParts[0] ?? string.Empty).TrimEnd(trims);
for (int i = 1; i < uriParts.Length; i++)
{
uri = string.Format("{0}/{1}", uri.TrimEnd(trims), (uriParts[i] ?? string.Empty).TrimStart(trims));
}
}
return uri;
}
其他回答
Path.Combine("Http://MyUrl.com/", "/Images/Image.jpg").Replace("\\", "/")
我发现UriBuilder在这种情况下工作得很好:
UriBuilder urlb = new UriBuilder("http", _serverAddress, _webPort, _filePath);
Uri url = urlb.Uri;
return url.AbsoluteUri;
有关更多构造函数和文档,请参阅UriBuilder类-MSDN。
最近,Combine方法被添加到Energy.Core包中,所以您可能希望使用它来连接URL部分。
string url;
url = Energy.Base.Url.Combine("https://www.youtube.com", "watch?v=NHCgbs3TcYg");
Console.WriteLine(url);
url = Energy.Base.Url.Combine("https://www.youtube.com", "watch?v=NHCgbs3TcYg", "t=150");
Console.WriteLine(url);
此外,它将识别参数部分,因此它将按照您的预期工作(用斜线连接路径,用&符号连接参数)。
https://www.youtube.com/watch?v=NHCgbs3TcYghttps://www.youtube.com/watch?v=NHCgbs3TcYg&t=150
Energy.Base.Url类文档
NuGet图库上的软件包
代码示例
我使用此代码来解决问题:
string[] brokenBaseUrl = Context.Url.TrimEnd('/').Split('/');
string[] brokenRootFolderPath = RootFolderPath.Split('/');
for (int x = 0; x < brokenRootFolderPath.Length; x++)
{
//if url doesn't already contain member, append it to the end of the string with / in front
if (!brokenBaseUrl.Contains(brokenRootFolderPath[x]))
{
if (x == 0)
{
RootLocationUrl = Context.Url.TrimEnd('/');
}
else
{
RootLocationUrl += String.Format("/{0}", brokenRootFolderPath[x]);
}
}
}
这可能是一个合适的简单解决方案:
public static string Combine(string uri1, string uri2)
{
uri1 = uri1.TrimEnd('/');
uri2 = uri2.TrimStart('/');
return string.Format("{0}/{1}", uri1, uri2);
}