我试图使用Directory.GetFiles()方法检索多种类型的文件列表,如mp3的和jpg的。以下两种方法我都试过了,但都没有成功:

Directory.GetFiles("C:\\path", "*.mp3|*.jpg", SearchOption.AllDirectories);
Directory.GetFiles("C:\\path", "*.mp3;*.jpg", SearchOption.AllDirectories);

有没有办法一次就能搞定?


当前回答

我不能使用. where方法,因为我在. net Framework 2.0中编程(Linq只在. net Framework 3.5+中被支持)。

下面的代码不区分大小写(因此.cab或.cab也会被列出)。

string[] ext = new string[2] { "*.CAB", "*.MSU" };

foreach (string found in ext)
{
    string[] extracted = Directory.GetFiles("C:\\test", found, System.IO.SearchOption.AllDirectories);

    foreach (string file in extracted)
    {
        Console.WriteLine(file);
    }
}

其他回答

Let

var set = new HashSet<string>(
    new[] { ".mp3", ".jpg" },
    StringComparer.OrdinalIgnoreCase); // ignore case
var dir = new DirectoryInfo(path);

Then

dir.EnumerateFiles("*.*", SearchOption.AllDirectories)
   .Where(f => set.Contains(f.Extension));

or

from file in dir.EnumerateFiles("*.*", SearchOption.AllDirectories)
from ext in set // makes sense only if it's just IEnumerable<string> or similar
where String.Equals(ext, file.Extension, StringComparison.OrdinalIgnoreCase)
select file;

我不能使用. where方法,因为我在. net Framework 2.0中编程(Linq只在. net Framework 3.5+中被支持)。

下面的代码不区分大小写(因此.cab或.cab也会被列出)。

string[] ext = new string[2] { "*.CAB", "*.MSU" };

foreach (string found in ext)
{
    string[] extracted = Directory.GetFiles("C:\\test", found, System.IO.SearchOption.AllDirectories);

    foreach (string file in extracted)
    {
        Console.WriteLine(file);
    }
}

或者你可以直接将扩展名字符串转换为string ^

vector <string>  extensions = { "*.mp4", "*.avi", "*.flv" };
for (int i = 0; i < extensions.size(); ++i)
{
     String^ ext = gcnew String(extensions[i].c_str());;
     String^ path = "C:\\Users\\Eric\\Videos";
     array<String^>^files = Directory::GetFiles(path,ext);
     Console::WriteLine(ext);
     cout << " " << (files->Length) << endl;
}

还有一个下降解决方案,似乎没有任何内存或性能开销,而且相当优雅:

string[] filters = new[]{"*.jpg", "*.png", "*.gif"};
string[] filePaths = filters.SelectMany(f => Directory.GetFiles(basePath, f)).ToArray();

在。net 2.0中(没有Linq):

public static List<string> GetFilez(string path, System.IO.SearchOption opt,  params string[] patterns)
{
    List<string> filez = new List<string>();
    foreach (string pattern in patterns)
    {
        filez.AddRange(
            System.IO.Directory.GetFiles(path, pattern, opt)
        );
    }


    // filez.Sort(); // Optional
    return filez; // Optional: .ToArray()
}

然后使用它:

foreach (string fn in GetFilez(path
                             , System.IO.SearchOption.AllDirectories
                             , "*.xml", "*.xml.rels", "*.rels"))
{}