我试图使用Directory.GetFiles()方法检索多种类型的文件列表,如mp3的和jpg的。以下两种方法我都试过了,但都没有成功:
Directory.GetFiles("C:\\path", "*.mp3|*.jpg", SearchOption.AllDirectories);
Directory.GetFiles("C:\\path", "*.mp3;*.jpg", SearchOption.AllDirectories);
有没有办法一次就能搞定?
我试图使用Directory.GetFiles()方法检索多种类型的文件列表,如mp3的和jpg的。以下两种方法我都试过了,但都没有成功:
Directory.GetFiles("C:\\path", "*.mp3|*.jpg", SearchOption.AllDirectories);
Directory.GetFiles("C:\\path", "*.mp3;*.jpg", SearchOption.AllDirectories);
有没有办法一次就能搞定?
当前回答
或者你可以直接将扩展名字符串转换为string ^
vector <string> extensions = { "*.mp4", "*.avi", "*.flv" };
for (int i = 0; i < extensions.size(); ++i)
{
String^ ext = gcnew String(extensions[i].c_str());;
String^ path = "C:\\Users\\Eric\\Videos";
array<String^>^files = Directory::GetFiles(path,ext);
Console::WriteLine(ext);
cout << " " << (files->Length) << endl;
}
其他回答
或者你可以直接将扩展名字符串转换为string ^
vector <string> extensions = { "*.mp4", "*.avi", "*.flv" };
for (int i = 0; i < extensions.size(); ++i)
{
String^ ext = gcnew String(extensions[i].c_str());;
String^ path = "C:\\Users\\Eric\\Videos";
array<String^>^files = Directory::GetFiles(path,ext);
Console::WriteLine(ext);
cout << " " << (files->Length) << endl;
}
对于。net 4.0及更高版本,
var files = Directory.EnumerateFiles("C:\\path", "*.*", SearchOption.AllDirectories)
.Where(s => s.EndsWith(".mp3") || s.EndsWith(".jpg"));
对于。net的早期版本,
var files = Directory.GetFiles("C:\\path", "*.*", SearchOption.AllDirectories)
.Where(s => s.EndsWith(".mp3") || s.EndsWith(".jpg"));
编辑:请阅读评论。Paul Farry提出的改进,以及Christian提出的记忆/性能问题。K点都很重要。
只是找到了另一种方法。仍然不是一次操作,而是把它扔出去,看看其他人是怎么想的。
private void getFiles(string path)
{
foreach (string s in Array.FindAll(Directory.GetFiles(path, "*", SearchOption.AllDirectories), predicate_FileMatch))
{
Debug.Print(s);
}
}
private bool predicate_FileMatch(string fileName)
{
if (fileName.EndsWith(".mp3"))
return true;
if (fileName.EndsWith(".jpg"))
return true;
return false;
}
在。net 2.0中(没有Linq):
public static List<string> GetFilez(string path, System.IO.SearchOption opt, params string[] patterns)
{
List<string> filez = new List<string>();
foreach (string pattern in patterns)
{
filez.AddRange(
System.IO.Directory.GetFiles(path, pattern, opt)
);
}
// filez.Sort(); // Optional
return filez; // Optional: .ToArray()
}
然后使用它:
foreach (string fn in GetFilez(path
, System.IO.SearchOption.AllDirectories
, "*.xml", "*.xml.rels", "*.rels"))
{}
我有同样的问题,找不到正确的解决方案,所以我写了一个函数叫GetFiles:
/// <summary>
/// Get all files with a specific extension
/// </summary>
/// <param name="extensionsToCompare">string list of all the extensions</param>
/// <param name="Location">string of the location</param>
/// <returns>array of all the files with the specific extensions</returns>
public string[] GetFiles(List<string> extensionsToCompare, string Location)
{
List<string> files = new List<string>();
foreach (string file in Directory.GetFiles(Location))
{
if (extensionsToCompare.Contains(file.Substring(file.IndexOf('.')+1).ToLower())) files.Add(file);
}
files.Sort();
return files.ToArray();
}
这个函数只调用Directory.Getfiles()一次。
例如,像这样调用函数:
string[] images = GetFiles(new List<string>{"jpg", "png", "gif"}, "imageFolder");
编辑:要获得一个具有多个扩展名的文件,请使用这个文件:
/// <summary>
/// Get the file with a specific name and extension
/// </summary>
/// <param name="filename">the name of the file to find</param>
/// <param name="extensionsToCompare">string list of all the extensions</param>
/// <param name="Location">string of the location</param>
/// <returns>file with the requested filename</returns>
public string GetFile( string filename, List<string> extensionsToCompare, string Location)
{
foreach (string file in Directory.GetFiles(Location))
{
if (extensionsToCompare.Contains(file.Substring(file.IndexOf('.') + 1).ToLower()) &&& file.Substring(Location.Length + 1, (file.IndexOf('.') - (Location.Length + 1))).ToLower() == filename)
return file;
}
return "";
}
例如,像这样调用函数:
string image = GetFile("imagename", new List<string>{"jpg", "png", "gif"}, "imageFolder");