我有同样的问题，找不到正确的解决方案，所以我写了一个函数叫GetFiles:

/// <summary>
/// Get all files with a specific extension
/// </summary>
/// <param name="extensionsToCompare">string list of all the extensions</param>
/// <param name="Location">string of the location</param>
/// <returns>array of all the files with the specific extensions</returns>
public string[] GetFiles(List<string> extensionsToCompare, string Location)
{
    List<string> files = new List<string>();
    foreach (string file in Directory.GetFiles(Location))
    {
        if (extensionsToCompare.Contains(file.Substring(file.IndexOf('.')+1).ToLower())) files.Add(file);
    }
    files.Sort();
    return files.ToArray();
}

这个函数只调用Directory.Getfiles()一次。

例如，像这样调用函数:

string[] images = GetFiles(new List<string>{"jpg", "png", "gif"}, "imageFolder");

编辑:要获得一个具有多个扩展名的文件，请使用这个文件:

/// <summary>
    /// Get the file with a specific name and extension
    /// </summary>
    /// <param name="filename">the name of the file to find</param>
    /// <param name="extensionsToCompare">string list of all the extensions</param>
    /// <param name="Location">string of the location</param>
    /// <returns>file with the requested filename</returns>
    public string GetFile( string filename, List<string> extensionsToCompare, string Location)
    {
        foreach (string file in Directory.GetFiles(Location))
        {
            if (extensionsToCompare.Contains(file.Substring(file.IndexOf('.') + 1).ToLower()) &&& file.Substring(Location.Length + 1, (file.IndexOf('.') - (Location.Length + 1))).ToLower() == filename) 
                return file;
        }
        return "";
    }

例如，像这样调用函数:

string image = GetFile("imagename", new List<string>{"jpg", "png", "gif"}, "imageFolder");

如果你使用VB。NET(或将依赖导入到你的c#项目中)，实际上存在一个方便的方法，允许过滤多个扩展:

Microsoft.VisualBasic.FileIO.FileSystem.GetFiles("C:\\path", Microsoft.VisualBasic.FileIO.SearchOption.SearchAllSubDirectories, new string[] {"*.mp3", "*.jpg"});

在VB。NET可以通过My-namespace访问:

My.Computer.FileSystem.GetFiles("C:\path", FileIO.SearchOption.SearchAllSubDirectories, {"*.mp3", "*.jpg"})

不幸的是，这些方便的方法不支持像Directory.EnumerateFiles()那样的惰性求值变体。

只是找到了另一种方法。仍然不是一次操作，而是把它扔出去，看看其他人是怎么想的。

private void getFiles(string path)
{
    foreach (string s in Array.FindAll(Directory.GetFiles(path, "*", SearchOption.AllDirectories), predicate_FileMatch))
    {
        Debug.Print(s);
    }
}

private bool predicate_FileMatch(string fileName)
{
    if (fileName.EndsWith(".mp3"))
        return true;
    if (fileName.EndsWith(".jpg"))
        return true;
    return false;
}

Let

var set = new HashSet<string>(
    new[] { ".mp3", ".jpg" },
    StringComparer.OrdinalIgnoreCase); // ignore case
var dir = new DirectoryInfo(path);

Then

dir.EnumerateFiles("*.*", SearchOption.AllDirectories)
   .Where(f => set.Contains(f.Extension));

or

from file in dir.EnumerateFiles("*.*", SearchOption.AllDirectories)
from ext in set // makes sense only if it's just IEnumerable<string> or similar
where String.Equals(ext, file.Extension, StringComparison.OrdinalIgnoreCase)
select file;

或者你可以直接将扩展名字符串转换为string ^

vector <string>  extensions = { "*.mp4", "*.avi", "*.flv" };
for (int i = 0; i < extensions.size(); ++i)
{
     String^ ext = gcnew String(extensions[i].c_str());;
     String^ path = "C:\\Users\\Eric\\Videos";
     array<String^>^files = Directory::GetFiles(path,ext);
     Console::WriteLine(ext);
     cout << " " << (files->Length) << endl;
}

让你想要的扩展名为一个字符串，即“.mp3.jpg.wma.wmf”，然后检查每个文件是否包含你想要的扩展名。 这适用于。net 2.0，因为它不使用LINQ。

string myExtensions=".jpg.mp3";

string[] files=System.IO.Directory.GetFiles("C:\myfolder");

foreach(string file in files)
{
   if(myExtensions.ToLower().contains(System.IO.Path.GetExtension(s).ToLower()))
   {
      //this file has passed, do something with this file

   }
}

这种方法的优点是你可以添加或删除扩展，而不需要编辑代码，即添加png图像，只需写myExtensions=".jpg.mp3.png"。