在。net 2.0中(没有Linq):

public static List<string> GetFilez(string path, System.IO.SearchOption opt,  params string[] patterns)
{
    List<string> filez = new List<string>();
    foreach (string pattern in patterns)
    {
        filez.AddRange(
            System.IO.Directory.GetFiles(path, pattern, opt)
        );
    }


    // filez.Sort(); // Optional
    return filez; // Optional: .ToArray()
}

然后使用它:

foreach (string fn in GetFilez(path
                             , System.IO.SearchOption.AllDirectories
                             , "*.xml", "*.xml.rels", "*.rels"))
{}

下面是一种获得过滤文件的简单而优雅的方法

var allowedFileExtensions = ".csv,.txt";


var files = Directory.EnumerateFiles(@"C:\MyFolder", "*.*", SearchOption.TopDirectoryOnly)
                .Where(s => allowedFileExtensions.IndexOf(Path.GetExtension(s)) > -1).ToArray(); 

Nop……我相信你必须拨打尽可能多的你想要的文件类型。

我会自己创建一个函数，在我需要的扩展字符串上使用数组，然后迭代该数组，进行所有必要的调用。该函数将返回与我发送的扩展名匹配的文件的通用列表。

希望能有所帮助。

我不知道哪种解决方案更好，但我用这个:

String[] ext = "*.ext1|*.ext2".Split('|');

            List<String> files = new List<String>();
            foreach (String tmp in ext)
            {
                files.AddRange(Directory.GetFiles(dir, tmp, SearchOption.AllDirectories));
            }

没有。试试下面的方法:

List<string> _searchPatternList = new List<string>();
    ...
    List<string> fileList = new List<string>();
    foreach ( string ext in _searchPatternList )
    {
        foreach ( string subFile in Directory.GetFiles( folderName, ext  )
        {
            fileList.Add( subFile );
        }
    }

    // Sort alpabetically
    fileList.Sort();

    // Add files to the file browser control    
    foreach ( string fileName in fileList )
    {
        ...;
    }

摘自:http://blogs.msdn.com/markda/archive/2006/04/20/580075.aspx

Let

var set = new HashSet<string>(
    new[] { ".mp3", ".jpg" },
    StringComparer.OrdinalIgnoreCase); // ignore case
var dir = new DirectoryInfo(path);

Then

dir.EnumerateFiles("*.*", SearchOption.AllDirectories)
   .Where(f => set.Contains(f.Extension));

or

from file in dir.EnumerateFiles("*.*", SearchOption.AllDirectories)
from ext in set // makes sense only if it's just IEnumerable<string> or similar
where String.Equals(ext, file.Extension, StringComparison.OrdinalIgnoreCase)
select file;