我试图使用Directory.GetFiles()方法检索多种类型的文件列表,如mp3的和jpg的。以下两种方法我都试过了,但都没有成功:
Directory.GetFiles("C:\\path", "*.mp3|*.jpg", SearchOption.AllDirectories);
Directory.GetFiles("C:\\path", "*.mp3;*.jpg", SearchOption.AllDirectories);
有没有办法一次就能搞定?
我试图使用Directory.GetFiles()方法检索多种类型的文件列表,如mp3的和jpg的。以下两种方法我都试过了,但都没有成功:
Directory.GetFiles("C:\\path", "*.mp3|*.jpg", SearchOption.AllDirectories);
Directory.GetFiles("C:\\path", "*.mp3;*.jpg", SearchOption.AllDirectories);
有没有办法一次就能搞定?
当前回答
如果你使用VB。NET(或将依赖导入到你的c#项目中),实际上存在一个方便的方法,允许过滤多个扩展:
Microsoft.VisualBasic.FileIO.FileSystem.GetFiles("C:\\path", Microsoft.VisualBasic.FileIO.SearchOption.SearchAllSubDirectories, new string[] {"*.mp3", "*.jpg"});
在VB。NET可以通过My-namespace访问:
My.Computer.FileSystem.GetFiles("C:\path", FileIO.SearchOption.SearchAllSubDirectories, {"*.mp3", "*.jpg"})
不幸的是,这些方便的方法不支持像Directory.EnumerateFiles()那样的惰性求值变体。
其他回答
另一种使用Linq的方式,但是不需要返回所有内容并在内存中过滤。
var files = Directory.GetFiles("C:\\path", "*.mp3", SearchOption.AllDirectories).Union(Directory.GetFiles("C:\\path", "*.jpg", SearchOption.AllDirectories));
它实际上是对GetFiles()的2次调用,但我认为这与问题的精神是一致的,并以一个可枚举的形式返回它们。
下面的函数搜索多个以逗号分隔的模式。你也可以指定一个排除,例如:"!web。Config”将搜索所有文件并排除“web.config”。模式可以混合使用。
private string[] FindFiles(string directory, string filters, SearchOption searchOption)
{
if (!Directory.Exists(directory)) return new string[] { };
var include = (from filter in filters.Split(new char[] { ',' }, StringSplitOptions.RemoveEmptyEntries) where !string.IsNullOrEmpty(filter.Trim()) select filter.Trim());
var exclude = (from filter in include where filter.Contains(@"!") select filter);
include = include.Except(exclude);
if (include.Count() == 0) include = new string[] { "*" };
var rxfilters = from filter in exclude select string.Format("^{0}$", filter.Replace("!", "").Replace(".", @"\.").Replace("*", ".*").Replace("?", "."));
Regex regex = new Regex(string.Join("|", rxfilters.ToArray()));
List<Thread> workers = new List<Thread>();
List<string> files = new List<string>();
foreach (string filter in include)
{
Thread worker = new Thread(
new ThreadStart(
delegate
{
string[] allfiles = Directory.GetFiles(directory, filter, searchOption);
if (exclude.Count() > 0)
{
lock (files)
files.AddRange(allfiles.Where(p => !regex.Match(p).Success));
}
else
{
lock (files)
files.AddRange(allfiles);
}
}
));
workers.Add(worker);
worker.Start();
}
foreach (Thread worker in workers)
{
worker.Join();
}
return files.ToArray();
}
用法:
foreach (string file in FindFiles(@"D:\628.2.11", @"!*.config, !*.js", SearchOption.AllDirectories))
{
Console.WriteLine(file);
}
或者你可以直接将扩展名字符串转换为string ^
vector <string> extensions = { "*.mp4", "*.avi", "*.flv" };
for (int i = 0; i < extensions.size(); ++i)
{
String^ ext = gcnew String(extensions[i].c_str());;
String^ path = "C:\\Users\\Eric\\Videos";
array<String^>^files = Directory::GetFiles(path,ext);
Console::WriteLine(ext);
cout << " " << (files->Length) << endl;
}
/// <summary>
/// Returns the names of files in a specified directories that match the specified patterns using LINQ
/// </summary>
/// <param name="srcDirs">The directories to seach</param>
/// <param name="searchPatterns">the list of search patterns</param>
/// <param name="searchOption"></param>
/// <returns>The list of files that match the specified pattern</returns>
public static string[] GetFilesUsingLINQ(string[] srcDirs,
string[] searchPatterns,
SearchOption searchOption = SearchOption.AllDirectories)
{
var r = from dir in srcDirs
from searchPattern in searchPatterns
from f in Directory.GetFiles(dir, searchPattern, searchOption)
select f;
return r.ToArray();
}
这个怎么样:
private static string[] GetFiles(string sourceFolder, string filters, System.IO.SearchOption searchOption)
{
return filters.Split('|').SelectMany(filter => System.IO.Directory.GetFiles(sourceFolder, filter, searchOption)).ToArray();
}
我在这里(评论中)找到了它:http://msdn.microsoft.com/en-us/library/wz42302f.aspx