谁有一个快速的方法去重复在c#的泛型列表?
当前回答
使用HashSet可以很容易地做到这一点。
List<int> listWithDuplicates = new List<int> { 1, 2, 1, 2, 3, 4, 5 };
HashSet<int> hashWithoutDuplicates = new HashSet<int> ( listWithDuplicates );
List<int> listWithoutDuplicates = hashWithoutDuplicates.ToList();
其他回答
在Java中(我认为c#或多或少是相同的):
list = new ArrayList<T>(new HashSet<T>(list))
如果你真的想改变原来的列表:
List<T> noDupes = new ArrayList<T>(new HashSet<T>(list));
list.clear();
list.addAll(noDupes);
为了保持顺序,只需将HashSet替换为LinkedHashSet。
也许您应该考虑使用HashSet。
从MSDN链接:
using System;
using System.Collections.Generic;
class Program
{
static void Main()
{
HashSet<int> evenNumbers = new HashSet<int>();
HashSet<int> oddNumbers = new HashSet<int>();
for (int i = 0; i < 5; i++)
{
// Populate numbers with just even numbers.
evenNumbers.Add(i * 2);
// Populate oddNumbers with just odd numbers.
oddNumbers.Add((i * 2) + 1);
}
Console.Write("evenNumbers contains {0} elements: ", evenNumbers.Count);
DisplaySet(evenNumbers);
Console.Write("oddNumbers contains {0} elements: ", oddNumbers.Count);
DisplaySet(oddNumbers);
// Create a new HashSet populated with even numbers.
HashSet<int> numbers = new HashSet<int>(evenNumbers);
Console.WriteLine("numbers UnionWith oddNumbers...");
numbers.UnionWith(oddNumbers);
Console.Write("numbers contains {0} elements: ", numbers.Count);
DisplaySet(numbers);
}
private static void DisplaySet(HashSet<int> set)
{
Console.Write("{");
foreach (int i in set)
{
Console.Write(" {0}", i);
}
Console.WriteLine(" }");
}
}
/* This example produces output similar to the following:
* evenNumbers contains 5 elements: { 0 2 4 6 8 }
* oddNumbers contains 5 elements: { 1 3 5 7 9 }
* numbers UnionWith oddNumbers...
* numbers contains 10 elements: { 0 2 4 6 8 1 3 5 7 9 }
*/
根据删除重复,我们必须应用下面的逻辑,所以它将以快速的方式删除重复。
public class Program
{
public static void Main(string[] arges)
{
List<string> cities = new List<string>() { "Chennai", "Kolkata", "Mumbai", "Mumbai","Chennai", "Delhi", "Delhi", "Delhi", "Chennai", "Kolkata", "Mumbai", "Chennai" };
cities = RemoveDuplicate(cities);
foreach (var city in cities)
{
Console.WriteLine(city);
}
}
public static List<string> RemoveDuplicate(List<string> cities)
{
if (cities.Count < 2)
{
return cities;
}
int size = cities.Count;
for (int i = 0; i < size; i++)
{
for (int j = i+1; j < size; j++)
{
if (cities[i] == cities[j])
{
cities.RemoveAt(j);
size--;
j--;
}
}
}
return cities;
}
}
这里有一个简单的解决方案,不需要任何难读的LINQ或任何列表的预先排序。
private static void CheckForDuplicateItems(List<string> items)
{
if (items == null ||
items.Count == 0)
return;
for (int outerIndex = 0; outerIndex < items.Count; outerIndex++)
{
for (int innerIndex = 0; innerIndex < items.Count; innerIndex++)
{
if (innerIndex == outerIndex) continue;
if (items[outerIndex].Equals(items[innerIndex]))
{
// Duplicate Found
}
}
}
}
如果你使用。net 3+,你可以使用Linq。
List<T> withDupes = LoadSomeData();
List<T> noDupes = withDupes.Distinct().ToList();
推荐文章
- 实体框架核心:在上一个操作完成之前,在此上下文中开始的第二个操作
- 如何为构造函数定制Visual Studio的私有字段生成快捷方式?
- 如何使用JSON确保字符串是有效的JSON。网
- AppSettings从.config文件中获取值
- 为什么元组可以包含可变项?
- 通过HttpClient向REST API发布一个空体
- 如何检查IEnumerable是否为空或空?
- 不区分大小写的“in”
- 自动化invokerrequired代码模式
- 在c#代码中设置WPF文本框的背景颜色
- 在c#中,什么是单子?
- c#和Java中的泛型有什么不同?和模板在c++ ?
- c#线程安全快速(est)计数器
- 如何将此foreach代码转换为Parallel.ForEach?
- 如何分裂()一个分隔字符串到一个列表<字符串>