有人能告诉我同步方法比同步块的优势与一个例子吗?
当前回答
来自Java规范摘要: http://www.cs.cornell.edu/andru/javaspec/17.doc.html
The synchronized statement (§14.17) computes a reference to an object; it then attempts to perform a lock action on that object and does not proceed further until the lock action has successfully completed. ... A synchronized method (§8.4.3.5) automatically performs a lock action when it is invoked; its body is not executed until the lock action has successfully completed. If the method is an instance method, it locks the lock associated with the instance for which it was invoked (that is, the object that will be known as this during execution of the body of the method). If the method is static, it locks the lock associated with the Class object that represents the class in which the method is defined. ...
基于这些描述,我想说以前的大多数答案都是正确的,同步方法可能对静态方法特别有用,否则您必须弄清楚如何获得“表示定义方法的类的Class对象”。
编辑:我原本以为这些是对实际Java规范的引用。澄清一下,本页只是对规范的总结/解释
其他回答
Synchronizing with threads. 1) NEVER use synchronized(this) in a thread it doesn't work. Synchronizing with (this) uses the current thread as the locking thread object. Since each thread is independent of other threads, there is NO coordination of synchronization. 2) Tests of code show that in Java 1.6 on a Mac the method synchronization does not work. 3) synchronized(lockObj) where lockObj is a common shared object of all threads synchronizing on it will work. 4) ReenterantLock.lock() and .unlock() work. See Java tutorials for this.
The following code shows these points. It also contains the thread-safe Vector which would be substituted for the ArrayList, to show that many threads adding to a Vector do not lose any information, while the same with an ArrayList can lose information. 0) Current code shows loss of information due to race conditions A) Comment the current labeled A line, and uncomment the A line above it, then run, method loses data but it shouldn't. B) Reverse step A, uncomment B and // end block }. Then run to see results no loss of data C) Comment out B, uncomment C. Run, see synchronizing on (this) loses data, as expected. Don't have time to complete all the variations, hope this helps. If synchronizing on (this), or the method synchronization works, please state what version of Java and OS you tested. Thank you.
import java.util.*;
/** RaceCondition - Shows that when multiple threads compete for resources
thread one may grab the resource expecting to update a particular
area but is removed from the CPU before finishing. Thread one still
points to that resource. Then thread two grabs that resource and
completes the update. Then thread one gets to complete the update,
which over writes thread two's work.
DEMO: 1) Run as is - see missing counts from race condition, Run severa times, values change
2) Uncomment "synchronized(countLock){ }" - see counts work
Synchronized creates a lock on that block of code, no other threads can
execute code within a block that another thread has a lock.
3) Comment ArrayList, unComment Vector - See no loss in collection
Vectors work like ArrayList, but Vectors are "Thread Safe"
May use this code as long as attribution to the author remains intact.
/mf
*/
public class RaceCondition {
private ArrayList<Integer> raceList = new ArrayList<Integer>(); // simple add(#)
// private Vector<Integer> raceList = new Vector<Integer>(); // simple add(#)
private String countLock="lock"; // Object use for locking the raceCount
private int raceCount = 0; // simple add 1 to this counter
private int MAX = 10000; // Do this 10,000 times
private int NUM_THREADS = 100; // Create 100 threads
public static void main(String [] args) {
new RaceCondition();
}
public RaceCondition() {
ArrayList<Thread> arT = new ArrayList<Thread>();
// Create thread objects, add them to an array list
for( int i=0; i<NUM_THREADS; i++){
Thread rt = new RaceThread( ); // i );
arT.add( rt );
}
// Start all object at once.
for( Thread rt : arT ){
rt.start();
}
// Wait for all threads to finish before we can print totals created by threads
for( int i=0; i<NUM_THREADS; i++){
try { arT.get(i).join(); }
catch( InterruptedException ie ) { System.out.println("Interrupted thread "+i); }
}
// All threads finished, print the summary information.
// (Try to print this informaiton without the join loop above)
System.out.printf("\nRace condition, should have %,d. Really have %,d in array, and count of %,d.\n",
MAX*NUM_THREADS, raceList.size(), raceCount );
System.out.printf("Array lost %,d. Count lost %,d\n",
MAX*NUM_THREADS-raceList.size(), MAX*NUM_THREADS-raceCount );
} // end RaceCondition constructor
class RaceThread extends Thread {
public void run() {
for ( int i=0; i<MAX; i++){
try {
update( i );
} // These catches show when one thread steps on another's values
catch( ArrayIndexOutOfBoundsException ai ){ System.out.print("A"); }
catch( OutOfMemoryError oome ) { System.out.print("O"); }
}
}
// so we don't lose counts, need to synchronize on some object, not primitive
// Created "countLock" to show how this can work.
// Comment out the synchronized and ending {, see that we lose counts.
// public synchronized void update(int i){ // use A
public void update(int i){ // remove this when adding A
// synchronized(countLock){ // or B
// synchronized(this){ // or C
raceCount = raceCount + 1;
raceList.add( i ); // use Vector
// } // end block for B or C
} // end update
} // end RaceThread inner class
} // end RaceCondition outter class
谁能告诉我同步方法比同步块的优势与一个例子?谢谢。
与块相比,使用同步方法并没有明显的优势。
也许唯一的一点(但我不认为这是优点)是您不需要包含对象引用this。
方法:
public synchronized void method() { // blocks "this" from here....
...
...
...
} // to here
布洛克:
public void method() {
synchronized( this ) { // blocks "this" from here ....
....
....
....
} // to here...
}
看到了吗?一点好处都没有。
块确实比方法有优势,主要是灵活性,因为你可以使用另一个对象作为锁,而同步方法将锁定整个对象。
比较:
// locks the whole object
...
private synchronized void someInputRelatedWork() {
...
}
private synchronized void someOutputRelatedWork() {
...
}
vs.
// Using specific locks
Object inputLock = new Object();
Object outputLock = new Object();
private void someInputRelatedWork() {
synchronized(inputLock) {
...
}
}
private void someOutputRelatedWork() {
synchronized(outputLock) {
...
}
}
另外,如果方法增长了,你仍然可以保持同步段的分离:
private void method() {
... code here
... code here
... code here
synchronized( lock ) {
... very few lines of code here
}
... code here
... code here
... code here
... code here
}
在同步方法的情况下,锁将在对象上获得。但是如果你使用同步块,你可以选择指定一个对象来获取锁。
例子:
Class Example {
String test = "abc";
// lock will be acquired on String test object.
synchronized (test) {
// do something
}
lock will be acquired on Example Object
public synchronized void testMethod() {
// do some thing
}
}
同步的方法
同步方法有两个效果。 首先,当一个线程正在为一个对象执行同步方法时,所有为同一对象调用同步方法的其他线程将阻塞(暂停执行),直到第一个线程处理完该对象。
其次,当同步方法退出时,它自动与同一对象的同步方法的任何后续调用建立happens-before关系。这保证了对对象状态的更改对于所有线程都是可见的。
注意,构造函数不能同步——在构造函数中使用synchronized关键字是一个语法错误。同步构造函数没有意义,因为只有创建对象的线程才能在构造对象时访问它。
同步语句
与同步方法不同,同步语句必须指定提供内在锁的对象:大多数情况下,我使用它来同步对列表或映射的访问,但我不想阻塞对对象的所有方法的访问。
Q:内在锁和同步 同步是围绕一个称为内在锁或监视器锁的内部实体构建的。(API规范通常将此实体简单地称为“监视器”)内在锁在同步的两个方面都发挥作用:强制独占访问对象的状态,并建立对可见性至关重要的happens-before关系。
Every object has an intrinsic lock associated with it. By convention, a thread that needs exclusive and consistent access to an object's fields has to acquire the object's intrinsic lock before accessing them, and then release the intrinsic lock when it's done with them. A thread is said to own the intrinsic lock between the time it has acquired the lock and released the lock. As long as a thread owns an intrinsic lock, no other thread can acquire the same lock. The other thread will block when it attempts to acquire the lock.
package test;
public class SynchTest implements Runnable {
private int c = 0;
public static void main(String[] args) {
new SynchTest().test();
}
public void test() {
// Create the object with the run() method
Runnable runnable = new SynchTest();
Runnable runnable2 = new SynchTest();
// Create the thread supplying it with the runnable object
Thread thread = new Thread(runnable,"thread-1");
Thread thread2 = new Thread(runnable,"thread-2");
// Here the key point is passing same object, if you pass runnable2 for thread2,
// then its not applicable for synchronization test and that wont give expected
// output Synchronization method means "it is not possible for two invocations
// of synchronized methods on the same object to interleave"
// Start the thread
thread.start();
thread2.start();
}
public synchronized void increment() {
System.out.println("Begin thread " + Thread.currentThread().getName());
System.out.println(this.hashCode() + "Value of C = " + c);
// If we uncomment this for synchronized block, then the result would be different
// synchronized(this) {
for (int i = 0; i < 9999999; i++) {
c += i;
}
// }
System.out.println("End thread " + Thread.currentThread().getName());
}
// public synchronized void decrement() {
// System.out.println("Decrement " + Thread.currentThread().getName());
// }
public int value() {
return c;
}
@Override
public void run() {
this.increment();
}
}
用同步方法,块和不同步交叉检查不同的输出。
大多数情况下,我使用它来同步对列表或映射的访问,但我不想阻止对对象的所有方法的访问。
在下面的代码中,修改列表的线程不会阻塞等待正在修改映射的线程。如果方法在对象上是同步的,那么每个方法都必须等待,即使它们所做的修改不会冲突。
private List<Foo> myList = new ArrayList<Foo>();
private Map<String,Bar) myMap = new HashMap<String,Bar>();
public void put( String s, Bar b ) {
synchronized( myMap ) {
myMap.put( s,b );
// then some thing that may take a while like a database access or RPC or notifying listeners
}
}
public void hasKey( String s, ) {
synchronized( myMap ) {
myMap.hasKey( s );
}
}
public void add( Foo f ) {
synchronized( myList ) {
myList.add( f );
// then some thing that may take a while like a database access or RPC or notifying listeners
}
}
public Thing getMedianFoo() {
Foo med = null;
synchronized( myList ) {
Collections.sort(myList);
med = myList.get(myList.size()/2);
}
return med;
}
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