我有一个长期运行的Python服务器,希望能够在不重新启动服务器的情况下升级服务。最好的方法是什么?
if foo.py has changed:
unimport foo <-- How do I do this?
import foo
myfoo = foo.Foo()
我有一个长期运行的Python服务器,希望能够在不重新启动服务器的情况下升级服务。最好的方法是什么?
if foo.py has changed:
unimport foo <-- How do I do this?
import foo
myfoo = foo.Foo()
当前回答
这是重新加载一个模块的现代方式:
from importlib import reload
如果你想支持3.5以上的Python版本,请使用以下命令:
from sys import version_info
if version_info[0] < 3:
pass # Python 2 has built in reload
elif version_info[0] == 3 and version_info[1] <= 4:
from imp import reload # Python 3.0 - 3.4
else:
from importlib import reload # Python 3.5+
这定义了一个重载方法,可以通过模块调用来重载它。例如,reload(math)将重载数学模块。
其他回答
下面的代码允许你兼容Python 2/3:
try:
reload
except NameError:
# Python 3
from imp import reload
你可以在两个版本中使用它作为reload(),这让事情变得更简单。
编辑(答案V2)
前面的解决方案只适用于获取重置信息,但它不会更改所有引用(超过重新加载,但小于所需)。为了设置所有的引用,我必须进入垃圾收集器,并在那里重写引用。现在它就像一个咒语!
请注意,如果GC被关闭,或者如果重新加载不受GC监视的数据,这将不起作用。如果您不想打乱GC,原始答案可能就足够了。
新代码:
import importlib
import inspect
import gc
from enum import EnumMeta
from weakref import ref
_readonly_attrs = {'__annotations__', '__call__', '__class__', '__closure__', '__code__', '__defaults__', '__delattr__',
'__dict__', '__dir__', '__doc__', '__eq__', '__format__', '__func__', '__ge__', '__get__',
'__getattribute__', '__globals__', '__gt__', '__hash__', '__init__', '__init_subclass__',
'__kwdefaults__', '__le__', '__lt__', '__module__', '__name__', '__ne__', '__new__', '__qualname__',
'__reduce__', '__reduce_ex__', '__repr__', '__self__', '__setattr__', '__sizeof__', '__str__',
'__subclasshook__', '__weakref__', '__members__', '__mro__', '__itemsize__', '__isabstractmethod__',
'__basicsize__', '__base__'}
def reset_module(module, inner_modules_also=True):
"""
This function is a stronger form of importlib's `reload` function. What it does, is that aside from reloading a
module, it goes to the old instance of the module, and sets all the (not read-only) attributes, functions and classes
to be the reloaded-module's
:param module: The module to reload (module reference, not the name)
:param inner_modules_also: Whether to treat ths module as a package as well, and reload all the modules within it.
"""
# For the case when the module is actually a package
if inner_modules_also:
submods = {submod for _, submod in inspect.getmembers(module)
if (type(submod).__name__ == 'module') and (submod.__package__.startswith(module.__name__))}
for submod in submods:
reset_module(submod, True)
# First, log all the references before reloading (because some references may be changed by the reload operation).
module_tree = _get_tree_references_to_reset_recursively(module, module.__name__)
new_module = importlib.reload(module)
_reset_item_recursively(module, module_tree, new_module)
def _update_referrers(item, new_item):
refs = gc.get_referrers(item)
weak_ref_item = ref(item)
for coll in refs:
if type(coll) == dict:
enumerator = coll.keys()
elif type(coll) == list:
enumerator = range(len(coll))
else:
continue
for key in enumerator:
if weak_ref_item() is None:
# No refs are left in the GC
return
if coll[key] is weak_ref_item():
coll[key] = new_item
def _get_tree_references_to_reset_recursively(item, module_name, grayed_out_item_ids = None):
if grayed_out_item_ids is None:
grayed_out_item_ids = set()
item_tree = dict()
attr_names = set(dir(item)) - _readonly_attrs
for sub_item_name in attr_names:
sub_item = getattr(item, sub_item_name)
item_tree[sub_item_name] = [sub_item, None]
try:
# Will work for classes and functions defined in that module.
mod_name = sub_item.__module__
except AttributeError:
mod_name = None
# If this item was defined within this module, deep-reset
if (mod_name is None) or (mod_name != module_name) or (id(sub_item) in grayed_out_item_ids) \
or isinstance(sub_item, EnumMeta):
continue
grayed_out_item_ids.add(id(sub_item))
item_tree[sub_item_name][1] = \
_get_tree_references_to_reset_recursively(sub_item, module_name, grayed_out_item_ids)
return item_tree
def _reset_item_recursively(item, item_subtree, new_item):
# Set children first so we don't lose the current references.
if item_subtree is not None:
for sub_item_name, (sub_item, sub_item_tree) in item_subtree.items():
try:
new_sub_item = getattr(new_item, sub_item_name)
except AttributeError:
# The item doesn't exist in the reloaded module. Ignore.
continue
try:
# Set the item
_reset_item_recursively(sub_item, sub_item_tree, new_sub_item)
except Exception as ex:
pass
_update_referrers(item, new_item)
原来的答案
正如在@bobince的回答中所写的,如果在另一个模块中已经有对该模块的引用(特别是如果它是用As关键字导入的,如import numpy As np),该实例将不会被覆盖。
当应用需要配置模块的“全新”状态的测试时,这对我来说是相当有问题的,所以我写了一个名为reset_module的函数,它使用importlib的reload函数并递归地覆盖所有声明的模块属性。它已经用Python版本3.6进行了测试。
import importlib
import inspect
from enum import EnumMeta
_readonly_attrs = {'__annotations__', '__call__', '__class__', '__closure__', '__code__', '__defaults__', '__delattr__',
'__dict__', '__dir__', '__doc__', '__eq__', '__format__', '__func__', '__ge__', '__get__',
'__getattribute__', '__globals__', '__gt__', '__hash__', '__init__', '__init_subclass__',
'__kwdefaults__', '__le__', '__lt__', '__module__', '__name__', '__ne__', '__new__', '__qualname__',
'__reduce__', '__reduce_ex__', '__repr__', '__self__', '__setattr__', '__sizeof__', '__str__',
'__subclasshook__', '__weakref__', '__members__', '__mro__', '__itemsize__', '__isabstractmethod__',
'__basicsize__', '__base__'}
def reset_module(module, inner_modules_also=True):
"""
This function is a stronger form of importlib's `reload` function. What it does, is that aside from reloading a
module, it goes to the old instance of the module, and sets all the (not read-only) attributes, functions and classes
to be the reloaded-module's
:param module: The module to reload (module reference, not the name)
:param inner_modules_also: Whether to treat ths module as a package as well, and reload all the modules within it.
"""
new_module = importlib.reload(module)
reset_items = set()
# For the case when the module is actually a package
if inner_modules_also:
submods = {submod for _, submod in inspect.getmembers(module)
if (type(submod).__name__ == 'module') and (submod.__package__.startswith(module.__name__))}
for submod in submods:
reset_module(submod, True)
_reset_item_recursively(module, new_module, module.__name__, reset_items)
def _reset_item_recursively(item, new_item, module_name, reset_items=None):
if reset_items is None:
reset_items = set()
attr_names = set(dir(item)) - _readonly_attrs
for sitem_name in attr_names:
sitem = getattr(item, sitem_name)
new_sitem = getattr(new_item, sitem_name)
try:
# Set the item
setattr(item, sitem_name, new_sitem)
try:
# Will work for classes and functions defined in that module.
mod_name = sitem.__module__
except AttributeError:
mod_name = None
# If this item was defined within this module, deep-reset
if (mod_name is None) or (mod_name != module_name) or (id(sitem) in reset_items) \
or isinstance(sitem, EnumMeta): # Deal with enums
continue
reset_items.add(id(sitem))
_reset_item_recursively(sitem, new_sitem, module_name, reset_items)
except Exception as ex:
raise Exception(sitem_name) from ex
注意事项:请谨慎使用!在非外围模块(例如,定义外部使用的类的模块)上使用这些可能会导致Python中的内部问题(例如pickle / unpickling问题)。
你可以使用importlib.reload()重新加载一个已经被导入的模块:
from importlib import reload # Python 3.4+
import foo
while True:
# Do some things.
if is_changed(foo):
foo = reload(foo)
在Python 2中,重载是内置的。在Python 3中,它被移动到imp模块。在3.4中,弃用了imp,改用了importlib。当目标为3或更高版本时,在调用reload或import时引用适当的模块。
我觉得这就是你想要的。像Django的开发服务器这样的Web服务器使用了这个功能,这样你就可以在不重启服务器进程的情况下看到代码更改的效果。
引用文件中的内容:
Python module’s code is recompiled and the module-level code re-executed, defining a new set of objects which are bound to names in the module’s dictionary by reusing the loader which originally loaded the module. The init function of extension modules is not called a second time. As with all other objects in Python the old objects are only reclaimed after their reference counts drop to zero. The names in the module namespace are updated to point to any new or changed objects. Other references to the old objects (such as names external to the module) are not rebound to refer to the new objects and must be updated in each namespace where they occur if that is desired.
正如您在问题中所指出的,如果Foo类驻留在Foo模块中,则必须重新构造Foo对象。
对于像我这样想卸载所有模块的人(当在Emacs下的Python解释器中运行时):
for mod in sys.modules.values():
reload(mod)
更多信息请参见重新加载Python模块。
从sys. exe中移除模块。modules也需要删除'None'类型。
方法1:
import sys
import json ## your module
for mod in [ m for m in sys.modules if m.lstrip('_').startswith('json') or sys.modules[m] == None ]: del sys.modules[mod]
print( json.dumps( [1] ) ) ## test if functionality has been removed
方法2,使用簿记条目,删除所有依赖项:
import sys
before_import = [mod for mod in sys.modules]
import json ## your module
after_import = [mod for mod in sys.modules if mod not in before_import]
for mod in [m for m in sys.modules if m in after_import or sys.modules[m] == None]: del sys.modules[mod]
print( json.dumps( [2] ) ) ## test if functionality has been removed
可选的,只是为了确保所有的条目都出来了,如果你这样选择:
import gc
gc.collect()