我想了解以下内容:给定一个日期(datetime对象),一周中对应的日期是什么?
例如,星期天是第一天,星期一是第二天。。等等
然后如果输入的内容类似于今天的日期。
实例
>>> today = datetime.datetime(2017, 10, 20)
>>> today.get_weekday() # what I look for
产量可能是6(因为现在是星期五)
我想了解以下内容:给定一个日期(datetime对象),一周中对应的日期是什么?
例如,星期天是第一天,星期一是第二天。。等等
然后如果输入的内容类似于今天的日期。
实例
>>> today = datetime.datetime(2017, 10, 20)
>>> today.get_weekday() # what I look for
产量可能是6(因为现在是星期五)
当前回答
如果日期是datetime对象,这是一个解决方案。
import datetime
def dow(date):
days=["Monday","Tuesday","Wednesday","Thursday","Friday","Saturday","Sunday"]
dayNumber=date.weekday()
print days[dayNumber]
其他回答
import numpy as np
def date(df):
df['weekday'] = df['date'].dt.day_name()
conditions = [(df['weekday'] == 'Sunday'),
(df['weekday'] == 'Monday'),
(df['weekday'] == 'Tuesday'),
(df['weekday'] == 'Wednesday'),
(df['weekday'] == 'Thursday'),
(df['weekday'] == 'Friday'),
(df['weekday'] == 'Saturday')]
choices = [0, 1, 2, 3, 4, 5, 6]
df['week'] = np.select(conditions, choices)
return df
如果日期是datetime对象,这是一个解决方案。
import datetime
def dow(date):
days=["Monday","Tuesday","Wednesday","Thursday","Friday","Saturday","Sunday"]
dayNumber=date.weekday()
print days[dayNumber]
以下是如何将小端字符串日期列表转换为datetime:
import datetime, time
ls = ['31/1/2007', '14/2/2017']
for d in ls:
dt = datetime.datetime.strptime(d, "%d/%m/%Y")
print(dt)
print(dt.strftime("%A"))
我为CodeChef问题解决了这个问题。
import datetime
dt = '21/03/2012'
day, month, year = (int(x) for x in dt.split('/'))
ans = datetime.date(year, month, day)
print (ans.strftime("%A"))
使用weekday():
>>> import datetime
>>> datetime.datetime.today()
datetime.datetime(2012, 3, 23, 23, 24, 55, 173504)
>>> datetime.datetime.today().weekday()
4
根据文档:
以整数形式返回星期几,其中星期一为0,星期日为6。