如果可以避免,我不想使用子视图。我想要一个带有背景图像,文本和图像的UIButton。现在,当我这样做的时候,图像在文本的左边。背景图像、文本和图像都有不同的高亮状态。
当前回答
一个快速的选项,做什么你想要不玩任何插图:
class RightImageButton: UIButton {
override func layoutSubviews() {
super.layoutSubviews()
if let textSize = titleLabel?.intrinsicContentSize(),
imageSize = imageView?.intrinsicContentSize() {
let wholeWidth = textSize.width + K.textImageGap + imageSize.width
titleLabel?.frame = CGRect(
x: round(bounds.width/2 - wholeWidth/2),
y: 0,
width: ceil(textSize.width),
height: bounds.height)
imageView?.frame = CGRect(
x: round(bounds.width/2 + wholeWidth/2 - imageSize.width),
y: RoundRetina(bounds.height/2 - imageSize.height/2),
width: imageSize.width,
height: imageSize.height)
}
}
struct K {
static let textImageGap: CGFloat = 5
}
}
其他回答
这里是解决方案的UIButton与中心对齐的内容。 这段代码使图像右对齐,并允许使用imageEdgeInsets和titleEdgeInsets进行宝贵的定位。
用你的自定义类子类化UIButton并添加:
- (CGRect)imageRectForContentRect:(CGRect)contentRect {
CGRect frame = [super imageRectForContentRect:contentRect];
CGFloat imageWidth = frame.size.width;
CGRect titleRect = CGRectZero;
titleRect.size = [[self titleForState:self.state] sizeWithAttributes:@{NSFontAttributeName: self.titleLabel.font}];
titleRect.origin.x = (self.frame.size.width - (titleRect.size.width + imageWidth)) / 2.0 + self.titleEdgeInsets.left - self.titleEdgeInsets.right;
frame.origin.x = titleRect.origin.x + titleRect.size.width - self.imageEdgeInsets.right + self.imageEdgeInsets.left;
return frame;
}
- (CGRect)titleRectForContentRect:(CGRect)contentRect {
CGFloat imageWidth = [self imageForState:self.state].size.width;
CGRect frame = [super titleRectForContentRect:contentRect];
frame.origin.x = (self.frame.size.width - (frame.size.width + imageWidth)) / 2.0 + self.titleEdgeInsets.left - self.titleEdgeInsets.right;
return frame;
}
在尝试了互联网上的多种解决方案后,我没有达到确切的要求。所以我最终编写了自定义实用程序代码。在将来帮助别人。 在swift 4.2上测试
// This function should be called in/after viewDidAppear to let view render
func addArrowImageToButton(button: UIButton, arrowImage:UIImage = #imageLiteral(resourceName: "my_image_name") ) {
let btnSize:CGFloat = 32
let imageView = UIImageView(image: arrowImage)
let btnFrame = button.frame
imageView.frame = CGRect(x: btnFrame.width-btnSize-8, y: btnFrame.height/2 - btnSize/2, width: btnSize, height: btnSize)
button.addSubview(imageView)
//Imageview on Top of View
button.bringSubviewToFront(imageView)
}
最简单的解决方案:
iOS 10及以上版本,Swift:
button.transform = CGAffineTransform(scaleX: -1.0, y: 1.0)
button.titleLabel?.transform = CGAffineTransform(scaleX: -1.0, y: 1.0)
button.imageView?.transform = CGAffineTransform(scaleX: -1.0, y: 1.0)
在iOS 10之前,Swift/Obj-C:
button.transform = CGAffineTransformMakeScale(-1.0, 1.0);
button.titleLabel.transform = CGAffineTransformMakeScale(-1.0, 1.0);
button.imageView.transform = CGAffineTransformMakeScale(-1.0, 1.0);
iOS 9及以上版本,Swift:(推荐)
button.semanticContentAttribute = .forceRightToLeft
约束条件呢?与semanticContentAttribute不同,它们不会改变语义。也许是这样的:
button.rightAnchorconstraint(equalTo: button.rightAnchor).isActive = true
或者在Objective-C中:
[button.imageView.rightAnchor constraintEqualToAnchor:button.rightAnchor].isActive = YES;
警告:未经测试,iOS 9+
这里提到的解决方案停止工作,一旦我启用自动布局。我不得不提出我自己的想法:
子类UIButton和覆盖layoutSubviews方法:
//
// MIThemeButtonImageAtRight.m
// Created by Lukasz Margielewski on 7/9/13.
//
#import "MIThemeButtonImageAtRight.h"
static CGRect CGRectByApplyingUIEdgeInsets(CGRect frame, UIEdgeInsets insets);
@implementation MIThemeButtonImageAtRight
- (void)layoutSubviews
{
[super layoutSubviews];
CGRect contentFrame = CGRectByApplyingUIEdgeInsets(self.bounds, self.contentEdgeInsets);
CGRect frameIcon = self.imageView.frame;
CGRect frameText = self.titleLabel.frame;
frameText.origin.x = CGRectGetMinX(contentFrame) + self.titleEdgeInsets.left;
frameIcon.origin.x = CGRectGetMaxX(contentFrame) - CGRectGetWidth(frameIcon);
self.imageView.frame = frameIcon;
self.titleLabel.frame = frameText;
}
@end
static CGRect CGRectByApplyingUIEdgeInsets(CGRect frame, UIEdgeInsets insets){
CGRect f = frame;
f.origin.x += insets.left;
f.size.width -= (insets.left + insets.right);
f.origin.y += (insets.top);
f.size.height -= (insets.top + insets.bottom);
return f;
}
结果:
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