解析姓和名的简单解决方案

DECLARE @Name varchar(10) = 'John Smith'

-- Get First Name
SELECT SUBSTRING(@Name, 0, (SELECT CHARINDEX(' ', @Name)))

-- Get Last Name
SELECT SUBSTRING(@Name, (SELECT CHARINDEX(' ', @Name)) + 1, LEN(@Name))

在我的例子中(在许多其他人中似乎也是如此……)，我有一个由一个空格隔开的姓和名列表。可以直接在选择语句中使用它来解析姓和名。

-- i.e. Get First and Last Name from a table of Full Names
SELECT SUBSTRING(FullName, 0, (SELECT CHARINDEX(' ', FullName))) as FirstName,
SUBSTRING(FullName, (SELECT CHARINDEX(' ', FullName)) + 1, LEN(FullName)) as LastName,
From FullNameTable

你可以在SQL用户定义函数解析带分隔符的字符串中找到有用的解决方案(来自代码项目)。

你可以使用这个简单的逻辑:

Declare @products varchar(200) = '1|20|3|343|44|6|8765'
Declare @individual varchar(20) = null

WHILE LEN(@products) > 0
BEGIN
    IF PATINDEX('%|%', @products) > 0
    BEGIN
        SET @individual = SUBSTRING(@products,
                                    0,
                                    PATINDEX('%|%', @products))
        SELECT @individual

        SET @products = SUBSTRING(@products,
                                  LEN(@individual + '|') + 1,
                                  LEN(@products))
    END
    ELSE
    BEGIN
        SET @individual = @products
        SET @products = NULL
        SELECT @individual
    END
END

下面是一个SQL UDF，它可以分割字符串并只抓取特定的部分。

create FUNCTION [dbo].[udf_SplitParseOut]
(
    @List nvarchar(MAX),
    @SplitOn nvarchar(5),
    @GetIndex smallint
)  
returns varchar(1000)
AS  

BEGIN

DECLARE @RtnValue table 
(

    Id int identity(0,1),
    Value nvarchar(MAX)
) 


    DECLARE @result varchar(1000)

    While (Charindex(@SplitOn,@List)>0)
    Begin
        Insert Into @RtnValue (value)
        Select Value = ltrim(rtrim(Substring(@List,1,Charindex(@SplitOn,@List)-1)))
        Set @List = Substring(@List,Charindex(@SplitOn,@List)+len(@SplitOn),len(@List))
    End

    Insert Into @RtnValue (Value)
    Select Value = ltrim(rtrim(@List))

    select @result = value from @RtnValue where ID = @GetIndex

    Return @result
END

好吧，我的代码并不那么简单，但下面是我用来将逗号分隔的输入变量分割为单个值，并将其放入表变量中的代码。我相信您可以稍微修改一下，根据空格进行分割，然后对该表变量执行基本的SELECT查询以获得结果。

-- Create temporary table to parse the list of accounting cycles.
DECLARE @tblAccountingCycles table
(
    AccountingCycle varchar(10)
)

DECLARE @vchAccountingCycle varchar(10)
DECLARE @intPosition int

SET @vchAccountingCycleIDs = LTRIM(RTRIM(@vchAccountingCycleIDs)) + ','
SET @intPosition = CHARINDEX(',', @vchAccountingCycleIDs, 1)

IF REPLACE(@vchAccountingCycleIDs, ',', '') <> ''
BEGIN
    WHILE @intPosition > 0
    BEGIN
        SET @vchAccountingCycle = LTRIM(RTRIM(LEFT(@vchAccountingCycleIDs, @intPosition - 1)))
        IF @vchAccountingCycle <> ''
        BEGIN
            INSERT INTO @tblAccountingCycles (AccountingCycle) VALUES (@vchAccountingCycle)
        END
        SET @vchAccountingCycleIDs = RIGHT(@vchAccountingCycleIDs, LEN(@vchAccountingCycleIDs) - @intPosition)
        SET @intPosition = CHARINDEX(',', @vchAccountingCycleIDs, 1)
    END
END

概念是差不多的。另一种选择是利用SQL Server 2005本身的. net兼容性。实际上，您可以在. net中编写一个简单的方法，将字符串分割，然后将其作为存储过程/函数公开。

下面是一个函数，它将完成问题的目标，即分割字符串并访问项目X:

CREATE FUNCTION [dbo].[SplitString]
(
   @List       VARCHAR(MAX),
   @Delimiter  VARCHAR(255),
   @ElementNumber INT
)
RETURNS VARCHAR(MAX)
AS
BEGIN

       DECLARE @inp VARCHAR(MAX)
       SET @inp = (SELECT REPLACE(@List,@Delimiter,'_DELMTR_') FOR XML PATH(''))

       DECLARE @xml XML
       SET @xml = '<split><el>' + REPLACE(@inp,'_DELMTR_','</el><el>') + '</el></split>'

       DECLARE @ret VARCHAR(MAX)
       SET @ret = (SELECT
              el = split.el.value('.','varchar(max)')
       FROM  @xml.nodes('/split/el[string-length(.)>0][position() = sql:variable("@elementnumber")]') split(el))

       RETURN @ret

END

用法:

SELECT dbo.SplitString('Hello John Smith', ' ', 2)

结果:

John

在我看来，你们把事情搞得太复杂了。只需要创建一个CLR UDF就可以了。

using System;
using System.Data;
using System.Data.SqlClient;
using System.Data.SqlTypes;
using Microsoft.SqlServer.Server;
using System.Collections.Generic;

public partial class UserDefinedFunctions {
  [SqlFunction]
  public static SqlString SearchString(string Search) {
    List<string> SearchWords = new List<string>();
    foreach (string s in Search.Split(new char[] { ' ' })) {
      if (!s.ToLower().Equals("or") && !s.ToLower().Equals("and")) {
        SearchWords.Add(s);
      }
    }

    return new SqlString(string.Join(" OR ", SearchWords.ToArray()));
  }
};