最近我似乎和合作者分享了很多代码。他们中的许多人是新手/中级R用户,并没有意识到他们必须安装他们还没有的包。
是否有一种优雅的方式来调用installed.packages(),比较那些我正在加载和安装如果丢失?
最近我似乎和合作者分享了很多代码。他们中的许多人是新手/中级R用户,并没有意识到他们必须安装他们还没有的包。
是否有一种优雅的方式来调用installed.packages(),比较那些我正在加载和安装如果丢失?
当前回答
让我分享一点疯狂:
c("ggplot2","ggsci", "hrbrthemes", "gghighlight", "dplyr") %>% # What will you need to load for this script?
(function (x) ifelse(t =!(x %in% installed.packages()),
install.packages(x[t]),
lapply(x, require)))
其他回答
此解决方案将获取包名的字符向量并尝试加载它们,或者在加载失败时安装它们。它依赖于require的返回行为来做到这一点,因为…
Require返回(不可见的)一个逻辑,指示所需的包是否可用
因此,我们可以简单地查看是否能够加载所需的包,如果不能,则使用依赖项安装它。所以给定一个你想要加载的包的字符向量…
foo <- function(x){
for( i in x ){
# require returns TRUE invisibly if it was able to load package
if( ! require( i , character.only = TRUE ) ){
# If package was not able to be loaded then re-install
install.packages( i , dependencies = TRUE )
# Load package after installing
require( i , character.only = TRUE )
}
}
}
# Then try/install packages...
foo( c("ggplot2" , "reshape2" , "data.table" ) )
我使用以下将检查包是否安装和依赖项是否更新,然后加载包。
p<-c('ggplot2','Rcpp')
install_package<-function(pack)
{if(!(pack %in% row.names(installed.packages())))
{
update.packages(ask=F)
install.packages(pack,dependencies=T)
}
require(pack,character.only=TRUE)
}
for(pack in p) {install_package(pack)}
completeFun <- function(data, desiredCols) {
completeVec <- complete.cases(data[, desiredCols])
return(data[completeVec, ])
}
library <- function(x){
x = toString(substitute(x))
if(!require(x,character.only=TRUE)){
install.packages(x)
base::library(x,character.only=TRUE)
}}
这适用于不带引号的包名,并且相当优雅(参见GeoObserver的答案)
pckg=c("shiny","ggplot2","dplyr","leaflet","lubridate","RColorBrewer","plotly","DT","shinythemes")
for(i in 1:length(pckg))
{
print(pckg[i])
if (!is.element(pckg[i], installed.packages()[,1]))
install.packages(pckg[i], dep = TRUE)
require(pckg[i], character.only = TRUE)
}
让我分享一点疯狂:
c("ggplot2","ggsci", "hrbrthemes", "gghighlight", "dplyr") %>% # What will you need to load for this script?
(function (x) ifelse(t =!(x %in% installed.packages()),
install.packages(x[t]),
lapply(x, require)))