如何将datetime对象格式化为带有毫秒的字符串?


当前回答

使用[:-3]删除最后3个字符,因为%f代表微秒:

>>> from datetime import datetime
>>> datetime.now().strftime('%Y/%m/%d %H:%M:%S.%f')[:-3]
'2013/12/04 16:50:03.141'

其他回答

要获得以毫秒为单位的日期字符串,使用[:-3]修剪%f(微秒)的最后三位数字:

>>> from datetime import datetime
>>> datetime.utcnow().strftime('%Y-%m-%d %H:%M:%S.%f')[:-3]
'2022-09-24 10:18:32.926'

或者稍短一点:

>>> from datetime import datetime
>>> datetime.utcnow().strftime('%F %T.%f')[:-3]

使用[:-3]删除最后3个字符,因为%f代表微秒:

>>> from datetime import datetime
>>> datetime.now().strftime('%Y/%m/%d %H:%M:%S.%f')[:-3]
'2013/12/04 16:50:03.141'
datetime
t = datetime.datetime.now()
ms = '%s.%i' % (t.strftime('%H:%M:%S'), t.microsecond/1000)
print(ms)
14:44:37.134
import datetime

# convert string into date time format.

str_date = '2016-10-06 15:14:54.322989'
d_date = datetime.datetime.strptime(str_date , '%Y-%m-%d %H:%M:%S.%f')
print(d_date)
print(type(d_date)) # check d_date type.


# convert date time to regular format.

reg_format_date = d_date.strftime("%d %B %Y %I:%M:%S %p")
print(reg_format_date)

# some other date formats.
reg_format_date = d_date.strftime("%Y-%m-%d %I:%M:%S %p")
print(reg_format_date)
reg_format_date = d_date.strftime("%Y-%m-%d %H:%M:%S")
print(reg_format_date)

<<<<<<输出>>>>>>>

2016-10-06 15:14:54.322989    
<class 'datetime.datetime'>    
06 October 2016 03:14:54 PM    
2016-10-06 03:14:54 PM    
2016-10-06 15:14:54
python -c "from datetime import datetime; print str(datetime.now())[:-3]"
2017-02-09 10:06:37.006