我想比较两个数组。。。理想地、有效地。没有什么稀奇古怪的,如果它们是相同的,那就是真的,如果不是,那就是假的。毫不奇怪,比较运算符似乎不起作用。

var a1 = [1,2,3];
var a2 = [1,2,3];
console.log(a1==a2);    // Returns false
console.log(JSON.stringify(a1)==JSON.stringify(a2));    // Returns true

JSON对每个数组进行编码,但是否有一种更快或“更好”的方法来简单地比较数组而不必遍历每个值?


当前回答

此函数比较两个任意形状和尺寸的数组:

function equals(a1, a2) {

    if (!Array.isArray(a1) || !Array.isArray(a2)) {
        throw new Error("Arguments to function equals(a1, a2) must be arrays.");
    }

    if (a1.length !== a2.length) {
        return false;
    }

    for (var i=0; i<a1.length; i++) {
        if (Array.isArray(a1[i]) && Array.isArray(a2[i])) {
            if (equals(a1[i], a2[i])) {
                continue;
            } else {
                return false;
            }
        } else {
            if (a1[i] !== a2[i]) {
                return false;
            }
        }
    }

    return true;
}

其他回答

令人惊讶的是,没有人提出解决办法

const a = [1, 2, 3]
const b = [1, 2, 3, 4]
a.find((v,i) => v !== b[i])

这里的好处是,它不会比较所有值,而是查找第一次出现的值,并尽早结束循环。换句话说,它不是问“两个数组相等吗?”而是问“一个数组与另一个数组不同吗?”。

绩效基准排名第三https://jsben.ch/TgFrA

记住,顺序很重要,a.find(…)!==b.find(…),可以通过a.length==b.length进行检查

if (a.length === b.length && a.find((v,i) => v !== b[i]) === undefined) {
  // equal
}

我的解决方案比较对象,而不是数组。这将以与Tomáš相同的方式工作,因为数组是对象,但没有警告:

Object.prototype.compare_to = function(comparable){
    
    // Is the value being compared an object
    if(comparable instanceof Object){
        
        // Count the amount of properties in @comparable
        var count_of_comparable = 0;
        for(p in comparable) count_of_comparable++;
        
        // Loop through all the properties in @this
        for(property in this){
            
            // Decrements once for every property in @this
            count_of_comparable--;
            
            // Prevents an infinite loop
            if(property != "compare_to"){
                
                // Is the property in @comparable
                if(property in comparable){
                    
                    // Is the property also an Object
                    if(this[property] instanceof Object){
                        
                        // Compare the properties if yes
                        if(!(this[property].compare_to(comparable[property]))){
                            
                            // Return false if the Object properties don't match
                            return false;
                        }
                    // Are the values unequal
                    } else if(this[property] !== comparable[property]){
                        
                        // Return false if they are unequal
                        return false;
                    }
                } else {
                
                    // Return false if the property is not in the object being compared
                    return false;
                }
            }
        }
    } else {
        
        // Return false if the value is anything other than an object
        return false;
    }
    
    // Return true if their are as many properties in the comparable object as @this
    return count_of_comparable == 0;
}

干得好,

常量a=[1,2,3]常量b=[1,2,3,4,5]常量diff=b.filter(e=>!a.includes(e))console.log(差异)

以上大多数答案对无序列表都不起作用。这也适用于无序列表。

常量a=[3,2,1]常量b=[1,2,3,4,5]常量diff=b.filter(e=>!a.includes(e))console.log(差异)

如果a的大小大于b,

常量a=[1,2,3,4,5]常量b=[3,2,1]常量diff=a.length>b.length?a.过滤器(e=>!b.includes(e)):b.过滤器(e=>!a.includes(e))console.log(差异)

不清楚你所说的“相同”是什么意思。例如,下面的数组a和b是否相同(请注意嵌套数组)?

var a = ["foo", ["bar"]], b = ["foo", ["bar"]];

这里有一个优化的数组比较函数,它使用严格的相等性依次比较每个数组的对应元素,并且不递归比较本身为数组的数组元素,这意味着对于上面的示例,arraysIncore(a,b)将返回false。它适用于一般情况,而基于JSON和join()的解决方案不会:

function arraysIdentical(a, b) {
    var i = a.length;
    if (i != b.length) return false;
    while (i--) {
        if (a[i] !== b[i]) return false;
    }
    return true;
};

与JSON.encode相同的行是使用join()。

function checkArrays( arrA, arrB ){

    //check if lengths are different
    if(arrA.length !== arrB.length) return false;


    //slice so we do not effect the original
    //sort makes sure they are in order
    //join makes it a string so we can do a string compare
    var cA = arrA.slice().sort().join(","); 
    var cB = arrB.slice().sort().join(",");

    return cA===cB;

}

var a = [1,2,3,4,5];
var b = [5,4,3,2,1];
var c = [1,2,3,4];
var d = [1,2,3,4,6];
var e = ["1","2","3","4","5"];  //will return true

console.log( checkArrays(a,b) );  //true
console.log( checkArrays(a,c) );  //false
console.log( checkArrays(a,d) );  //false
console.log( checkArrays(a,e) );  //true

唯一的问题是,如果您关心上次比较测试的类型。如果你关心类型,你将不得不循环。

function checkArrays( arrA, arrB ){

    //check if lengths are different
    if(arrA.length !== arrB.length) return false;

    //slice so we do not effect the orginal
    //sort makes sure they are in order
    var cA = arrA.slice().sort(); 
    var cB = arrB.slice().sort();

    for(var i=0;i<cA.length;i++){
         if(cA[i]!==cB[i]) return false;
    }

    return true;

}

var a = [1,2,3,4,5];
var b = [5,4,3,2,1];
var c = [1,2,3,4];
var d = [1,2,3,4,6];
var e = ["1","2","3","4","5"];

console.log( checkArrays(a,b) );  //true
console.log( checkArrays(a,c) );  //false
console.log( checkArrays(a,d) );  //false
console.log( checkArrays(a,e) );  //false

如果顺序应该保持不变,而不是循环,则不需要排序。

function checkArrays( arrA, arrB ){

    //check if lengths are different
    if(arrA.length !== arrB.length) return false;


    for(var i=0;i<arrA.length;i++){
         if(arrA[i]!==arrB[i]) return false;
    }

    return true;

}

var a = [1,2,3,4,5];
var b = [5,4,3,2,1];
var c = [1,2,3,4];
var d = [1,2,3,4,6];
var e = ["1","2","3","4","5"];

console.log( checkArrays(a,a) );  //true
console.log( checkArrays(a,b) );  //false
console.log( checkArrays(a,c) );  //false
console.log( checkArrays(a,d) );  //false
console.log( checkArrays(a,e) );  //false